Problem 64
Question
If \( \displaystyle f(x) = \int^x_0 (1 - t^2) e^{t^2} \,dt \), on what interval is \( f \) increasing?
Step-by-Step Solution
Verified Answer
\(-1 < x < 1\)
1Step 1: Understand the Function
The function given is \( f(x) = \int_0^x (1 - t^2) e^{t^2} \,dt \). To determine where \( f \) is increasing, we need to consider the derivative of \( f(x) \). According to the Fundamental Theorem of Calculus, the derivative of a definite integral with a variable upper bound is the integrand evaluated at that bound.
2Step 2: Find the Derivative
Apply the Fundamental Theorem of Calculus to find the derivative of \( f(x) \). The derivative is \( f'(x) = (1 - x^2)e^{x^2} \). The sign of \( f'(x) \) determines whether \( f \) is increasing or decreasing.
3Step 3: Determine When \( f'(x) > 0 \)
For \( f(x) \) to be increasing, \( f'(x) = (1 - x^2)e^{x^2} \) must be positive. Since the exponential function \( e^{x^2} \) is always positive, the sign of \( f'(x) \) depends on \( 1 - x^2 \). Therefore, \( 1 - x^2 > 0 \) leads to \( x^2 < 1 \), which simplifies to \(-1 < x < 1\).
4Step 4: Conclude the Interval
Based on the inequality obtained in the previous step, \( f(x) \) is increasing on the interval \(-1 < x < 1\). This is because within this interval, the expression \( (1 - x^2)e^{x^2} \) is positive, thus \( f'(x) > 0 \).
Key Concepts
Increasing FunctionsDerivative of an IntegralExponential FunctionInequality Solutions
Increasing Functions
Understanding which intervals make a function increasing is essential in calculus. An increasing function is one where, as you move from left to right along the x-axis, the value of the function also goes up. But how can you determine this behavior mathematically? The secret lies in the derivative:
- If the derivative of a function, denoted as \(f'(x)\), is greater than zero, the function is increasing within that interval.
- If \(f'(x) < 0\), the function will be decreasing in that region.
Derivative of an Integral
The Fundamental Theorem of Calculus is a powerful tool that bridges the concept of differentiation and integration. It provides a way to find the derivative of an integral function. According to this theorem:
- The derivative of the integral of a function with respect to a variable, especially when that variable is the upper limit of the integral, is simply the original function.
- \(f'(x) = (1 - x^2)e^{x^2}\)
Exponential Function
The exponential function, denoted as \(e^{x^2}\) in this problem, plays a crucial role. Exponential functions have unique properties:
- They are always positive, regardless of the value they are raised to.
- They grow rapidly, increasing the speed of growth as the exponent becomes larger.
Inequality Solutions
Solving inequalities is a fundamental algebraic skill that is particularly useful when studying the behavior of functions in calculus. In our problem, we need to solve \(1 - x^2 > 0\) to determine where the function \(f(x)\) is increasing.
- Start by rearranging terms: \(1 > x^2\).
- Recognize that this means \(-1 < x < 1\).
Other exercises in this chapter
Problem 64
Evaluate the definite integral. \( \displaystyle \int^a_0 x\sqrt{a^2 - x^2} \, dx \)
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Water flows from the bottom of a storage tank at a rate of \( r(t) = 200 - 4t \) liters per minute, where \( 0 \le t \le 50 \). Find the amount of water that fl
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Evaluate the definite integral. \( \displaystyle \int^a_0 x\sqrt{x^2 + a^2} \, dx \) \( (a > 0) \)
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Evaluate the definite integral. \( \displaystyle \int^{\pi/3}_{-\pi/3} x^4 \sin x \, dx \)
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