Problem 64
Question
For the following exercises, use the given information about the polynomial graph to write the equation. Degree 5. Roots of multiplicity 2 at \(x=-3\) and \(x=2\) and a root of multiplicity 1 at \(x=-2\). \(y\) -intercept at (0,4) .
Step-by-Step Solution
Verified Answer
The polynomial equation is \( P(x) = \frac{1}{18}(x+3)^2(x-2)^2(x+2) \).
1Step 1: Identify the Root Factors
Given the roots of multiplicity, we can form the polynomial's factors. The roots are -3 (multiplicity 2), 2 (multiplicity 2), and -2 (multiplicity 1). The factors are \((x+3)^2\), \((x-2)^2\), and \((x+2)\)."
2Step 2: Write the General Polynomial Equation
By multiplying the identified factors, we get the general form of the polynomial:\[ P(x) = a(x+3)^2(x-2)^2(x+2) \]where \(a\) is a constant that needs to be determined using additional information given in the problem.
3Step 3: Use the y-intercept to Find 'a'
We know the polynomial passes through the point (0, 4), making it the \(y\)-intercept. Substitute \(x = 0\) and \(P(x) = 4\):\[ 4 = a(0+3)^2(0-2)^2(0+2) \]\[ 4 = a(9)(4)(2) \]\[ 4 = 72a \]Solve for \(a\):\[ a = \frac{4}{72} = \frac{1}{18} \]
4Step 4: Write the Final Polynomial Equation
Substitute the value of \(a\) back into the polynomial equation:\[ P(x) = \frac{1}{18}(x+3)^2(x-2)^2(x+2) \]This is the final polynomial equation with the given roots and y-intercept.
Key Concepts
Roots and MultiplicityY-interceptDegree of Polynomial
Roots and Multiplicity
In the world of polynomial equations, roots are special numbers that make the polynomial equal to zero when substituted for the variable. Each root can have a certain multiplicity, which tells us how many times that particular root appears in the factorization of the polynomial.
For instance, a root with multiplicity 2 means it appears twice, making its factor squared in the polynomial equation. If we consider the given polynomial, we have roots at \(x = -3\) and \(x = 2\) with a multiplicity of 2 each. This means the factors \((x + 3)\) and \((x - 2)\) are squared:
For instance, a root with multiplicity 2 means it appears twice, making its factor squared in the polynomial equation. If we consider the given polynomial, we have roots at \(x = -3\) and \(x = 2\) with a multiplicity of 2 each. This means the factors \((x + 3)\) and \((x - 2)\) are squared:
- Root \(-3\) with multiplicity 2: \((x + 3)^2\)
- Root \(2\) with multiplicity 2: \((x - 2)^2\)
- Root \(-2\) with multiplicity 1: \((x + 2)\)
Y-intercept
The y-intercept is a crucial part of understanding the behavior of a polynomial graph. It represents the point where the graph crosses the y-axis, meaning it is the point where \(x\) is equal to zero.
For any polynomial function \(P(x)\), finding the y-intercept involves simply setting \(x = 0\). In our example, the point given is (0, 4), meaning that when \(x = 0\), the value of the polynomial is 4. Using this information, we can compute the constant "a" that scales the polynomial to this y-intercept.
By setting \[ 4 = a(0+3)^2(0-2)^2(0+2), \]you can solve for "a" and find that \(a = \frac{1}{18}\).
This step ensures that the polynomial equation accurately represents the specific graph by confirming it passes through the correct y-intercept, crucial for graph's vertical alignment.
For any polynomial function \(P(x)\), finding the y-intercept involves simply setting \(x = 0\). In our example, the point given is (0, 4), meaning that when \(x = 0\), the value of the polynomial is 4. Using this information, we can compute the constant "a" that scales the polynomial to this y-intercept.
By setting \[ 4 = a(0+3)^2(0-2)^2(0+2), \]you can solve for "a" and find that \(a = \frac{1}{18}\).
This step ensures that the polynomial equation accurately represents the specific graph by confirming it passes through the correct y-intercept, crucial for graph's vertical alignment.
Degree of Polynomial
A polynomial's degree is vital as it determines the number of roots and the behavior of its graph. The degree is the highest power of the variable in the polynomial equation when it is expanded and fully simplified.
For the polynomial described in the exercise, the degree is 5. This is derived from the multiplication of its factors and terms, accounting for the multiplicity of each root: \((x+3)^2(x-2)^2(x+2)\).
To find this degree, consider:
The degree dictates not only the number of roots but also the end behavior of the polynomial. Higher degree polynomials have more complex shapes and crossing points. Thus, knowing the degree is important for understanding the overall form of the graph.
For the polynomial described in the exercise, the degree is 5. This is derived from the multiplication of its factors and terms, accounting for the multiplicity of each root: \((x+3)^2(x-2)^2(x+2)\).
To find this degree, consider:
- Factor \((x+3)^2\) contributes 2 to the degree.
- Factor \((x-2)^2\) also adds 2.
- Factor \((x+2)\) adds 1.
The degree dictates not only the number of roots but also the end behavior of the polynomial. Higher degree polynomials have more complex shapes and crossing points. Thus, knowing the degree is important for understanding the overall form of the graph.
Other exercises in this chapter
Problem 64
For the following exercises, use your calculator to graph the polynomial function. Based on the graph, find the rational zeros. All real solutions are rational.
View solution Problem 64
For the following exercises, use the given length and area of a rectangle to express the width algebraically. Length is \(x+5,\) area is \(2 x^{2}+9 x-5\)
View solution Problem 64
For the following exercises, use the information about the graph of a polynomial function to determine the function. Assume the leading coefficient is 1 or -1 .
View solution Problem 64
For the following exercises, write the equation of the quadratic function that contains the given point and has the same shape as the given function. Contains (
View solution