Problem 64
Question
Completely factor the expression.\((t-1)^{2}-49\)
Step-by-Step Solution
Verified Answer
The expression \((t-1)^2 - 49\) factors to \((t - 8)(t + 6)\).
1Step 1: Identify a and b
In the formula \((a^2 - b^2) = (a - b)(a + b)\), we can see that the expression \((t-1)^2 - 49\) fits this format with \(a = t-1\) and \(b = 7\).
2Step 2: Apply the formula
To factor the expression, apply the formula for the difference of squares \((a^2 - b^2) = (a - b)(a + b)\). Replace \(a\) with \(t-1\) and \(b\) with \(7\) to get the factored form.
3Step 3: Simplify
Simplify to find that \((t-1 - 7)(t-1 + 7) = (t-8)(t+6)\).
Key Concepts
Difference of squaresFactoring polynomialsAlgebraic expressions
Difference of squares
The difference of squares is a special pattern in algebra where you have two perfect squares separated by a subtraction sign. This is a useful concept because it allows us to factor expressions quickly and efficiently.
In general, this pattern is expressed as \(a^2 - b^2\), and it factors into the product \((a-b)(a+b)\). Recognizing this form in algebraic expressions helps simplify and solve equations more easily.
Take, for example, the expression \((t-1)^2 - 49\). Here, \((t-1)^2\) is the square of \(t-1\), and 49 is the square of 7. Hence, this expression is in the difference of squares form.
When you spot a difference of squares pattern like this, you can apply the formula directly to factor it. This makes it much easier than expanding or applying other lengthy methods.
In general, this pattern is expressed as \(a^2 - b^2\), and it factors into the product \((a-b)(a+b)\). Recognizing this form in algebraic expressions helps simplify and solve equations more easily.
Take, for example, the expression \((t-1)^2 - 49\). Here, \((t-1)^2\) is the square of \(t-1\), and 49 is the square of 7. Hence, this expression is in the difference of squares form.
When you spot a difference of squares pattern like this, you can apply the formula directly to factor it. This makes it much easier than expanding or applying other lengthy methods.
Factoring polynomials
Factoring polynomials involves breaking down a complex polynomial into simpler expressions that, when multiplied together, provide the original polynomial. This is a fundamental skill in algebra and simplifies the process of solving equations.
There are several strategies for factoring polynomials, including:
There are several strategies for factoring polynomials, including:
- Finding the greatest common factor (if there is one).
- Applying special patterns such as the difference of squares.
- Identifying and using sum/difference of cubes or quadratic trinomials.
- Using factorization by grouping when applicable.
Algebraic expressions
Algebraic expressions are combinations of variables, numbers, operations, and sometimes exponents that represent values and relationships. Understanding how to manipulate these expressions is crucial in solving algebra problems.
Working with algebraic expressions involves:
Working with algebraic expressions involves:
- Simplifying expressions using the order of operations.
- Combining like terms to make them easier to work with.
- Expanding expressions when necessary.
- Factorizing expressions to find their simplest forms.
Other exercises in this chapter
Problem 64
Find the distance between \(a\) and \(b\).\(a=\frac{1}{4}, b=\frac{11}{4}\)
View solution Problem 64
Simplify the complex fraction.\(\frac{(x-3)}{\left(\frac{x}{4}-\frac{4}{x}\right)}\)
View solution Problem 64
\(\quad\) A box has a length of \((57-2 x)\) inches, a width of \((39-2 x)\) inches, and a height of \(x\) inches. Find the volume when \(x=4, x=6\), and \(x=10
View solution Problem 64
Use rational exponents to reduce the index of the radical.\(\sqrt[4]{\left(3 x^{2}\right)^{4}}\)
View solution