Problem 64
Question
\(\cdot\) A solenoid contains 750 coils of very thin wire evenly wrapped over a length of 15.0 \(\mathrm{cm} .\) Each coil is 0.800 \(\mathrm{cm}\) in diameter. If this solenoid carries a current of \(7.00 \mathrm{A},\) what is the magnetic field at its center?
Step-by-Step Solution
Verified Answer
The magnetic field at the solenoid's center is approximately 0.0440 T.
1Step 1: Identify the formula for the magnetic field inside a solenoid
The magnetic field inside a solenoid is given by the formula \( B = \mu_0 n I \), where \( B \) is the magnetic field, \( \mu_0 \) is the permeability of free space (\( 4\pi \times 10^{-7} \ \text{T m/A} \)), \( n \) is the number of turns per unit length, and \( I \) is the current.
2Step 2: Calculate the number of turns per unit length
The total number of coils, or turns, is given as 750, and the length of the solenoid is 15.0 cm, which can be converted to meters as 0.15 m. Thus, the number of turns per unit length \( n \) is calculated as \( n = \frac{750}{0.15} \).
3Step 3: Plug in the values for the calculation
Substitute the known values into the formula: \( B = (4\pi \times 10^{-7} \ \text{T m/A}) \times (\frac{750}{0.15}) \times 7 \).
4Step 4: Calculate the magnetic field
Calculate the result using the values from the previous step, resulting in \( B \approx 0.0440 \ \text{T} \).
Key Concepts
Solenoid PropertiesMagnetic Field CalculationPermeability of Free Space
Solenoid Properties
A solenoid is a coil of wire that is often shaped like a cylinder. These coils can create a magnetic field when an electric current passes through them, a principle that is fundamental in many electromagnetic devices. Some key properties of a solenoid to consider include:
- Number of Turns: Each wrap of wire around the cylinder is a turn or coil. The number of turns is directly proportional to the strength of the magnetic field generated.
- Length of Solenoid: This is the total distance over which the wire is wrapped. It's important to note the length impacts how concentrated the turns are, which in turn affects the magnetic field intensity.
- Coil Diameter: Though not directly required for calculating the magnetic field, it plays a role in applications where the spacing of the coils and the physical design are matters of concern.
- Core Type: The core material (often air or iron) inside affects how the magnetic field is distributed and its overall strength. However, for this scenario, we assume an air core.
Magnetic Field Calculation
To find the magnetic field in the center of a solenoid, the formula used is:\[ B = \mu_0 n I \]Where:
- \( B \) is the magnetic field strength.
- \( \mu_0 \) is the permeability of free space, a constant value.
- \( n \), the number of turns per unit length, is calculated by dividing the total number of turns by the solenoid's length.
- \( I \) is the current passing through the solenoid.
Permeability of Free Space
The permeability of free space \( \mu_0 \) is a fundamental constant crucial to understanding electromagnetism. Its value is approximately \( 4\pi \times 10^{-7} \ \text{T m/A} \), and it signifies how much resistance is encountered when forming a magnetic field in a vacuum. This concept helps define the relationship between magnetic fields and currents in spaces that are not filled with material that may otherwise amplify or diminish the magnetic effects.
The idea becomes significant when calculating the magnetic field in air-core solenoids like the one discussed. The permeability of free space sets the baseline for determining the field's intensity inside a solenoid, as it works as a proportional constant in the main magnetic field equation. By knowing \( \mu_0 \), we can better predict and manipulate magnetic fields in various devices, from simple electromagnets to advanced equipment, allowing for a broad range of applications in technology and physics.
The idea becomes significant when calculating the magnetic field in air-core solenoids like the one discussed. The permeability of free space sets the baseline for determining the field's intensity inside a solenoid, as it works as a proportional constant in the main magnetic field equation. By knowing \( \mu_0 \), we can better predict and manipulate magnetic fields in various devices, from simple electromagnets to advanced equipment, allowing for a broad range of applications in technology and physics.
Other exercises in this chapter
Problem 61
A closely wound, circular coil with radius 2.40 \(\mathrm{cm}\) has 800 turns. What must the current in the coil be if the magnetic field at the center of the c
View solution Problem 62
\(\bullet\) Two circular concentric loops of wire lie on a tabletop, one inside the other. The inner loop has a diameter of 20.0 \(\mathrm{cm}\) and carries a c
View solution Problem 65
\(\bullet\) As a new electrical technician, you are designing a large solenoid to produce a uniform 0.150 T magnetic field near its center. You have enough wire
View solution Problem 67
\bullet A single circular current loop 10.0 \(\mathrm{cm}\) in diameter carries a 2.00 A current. (a) What is the magnetic field at the center of this loop? (b)
View solution