Problem 63
Question
There is a generalized pigeonhole principle which says that if we partition a set with more than \(k n\) elements into \(n\) blocks, then at least one block has at least \(k+1\) elements. Prove the generalized pigeonhole principle. (h)
Step-by-Step Solution
Verified Answer
If a set with more than \(kn\) elements is partitioned into \(n\) blocks, at least one block has at least \(k+1\) elements.
1Step 1: Understand the Problem
According to the generalized pigeonhole principle, if we partition a set with more than \(kn\) elements into \(n\) blocks, at least one block will contain at least \(k+1\) elements. We need to prove this statement.
2Step 2: State the Variables
Let the total number of elements be \(N\) where \(N > kn\), and let these elements be divided into \(n\) blocks. We aim to show that at least one block contains at least \(k+1\) elements.
3Step 3: Calculate the Maximum Possible Elements per Block
If each block had exactly \(k\) elements, the total number of elements would be \(kn\). Therefore, if the set contains more than \(kn\) elements, this equal distribution is not possible.
4Step 4: Use Proof by Contradiction
Assume every block has at most \(k\) elements. If that were the case, then the total number of elements in all \(n\) blocks would be at most \(kn\). But this contradicts our condition that the set has more than \(kn\) elements.
5Step 5: Conclude the Proof
Since our assumption (every block has at most \(k\) elements) leads to a contradiction, it must be false. Thus, there must be at least one block with more than \(k\) elements, which means at least \(k+1\) elements in one block.
Key Concepts
CombinatoricsProof by ContradictionSet Partition
Combinatorics
Combinatorics is a branch of mathematics that focuses on counting, arrangement, and combination of objects within a set. In the context of the generalized pigeonhole principle, combinatorics helps us understand the distribution of elements into different partitions or blocks. This principle can be used to identify patterns and establish that if we distribute a large number of items (more than kn) into smaller groups (n blocks), the uniform distribution is impossible if the item count exceeds kn. This realization is a crucial part of solving and understanding the given problem.
Proof by Contradiction
Proof by contradiction is a fundamental technique in mathematics used to demonstrate the truth of a statement. This method involves assuming the opposite of the desired conclusion, and then showing that this assumption leads to a logical contradiction.
To apply the proof by contradiction method in the given problem, we start by assuming the opposite of what we want to prove: That every block has at most k elements. From this assumption, we derive that the total number of elements would be at most kn. However, according to the problem, we actually have more than kn elements. This contradiction between our assumption and the given information confirms that at least one block must have more than k elements, thus verifying the statement we set out to prove.
To apply the proof by contradiction method in the given problem, we start by assuming the opposite of what we want to prove: That every block has at most k elements. From this assumption, we derive that the total number of elements would be at most kn. However, according to the problem, we actually have more than kn elements. This contradiction between our assumption and the given information confirms that at least one block must have more than k elements, thus verifying the statement we set out to prove.
Set Partition
A set partition divides a set into non-overlapping subsets, such that every element of the original set is included in one and only one subset. When dealing with set partitions in the context of the generalized pigeonhole principle, we partition a set of more than kn items into n blocks.
Because there are more items than could evenly fit into the n blocks with each block having k elements, it is guaranteed that at least one block must contain at least one more element than this average, ensuring that at least one block has k+1 elements. This simple yet powerful observation is the core idea behind the generalized pigeonhole principle.
Because there are more items than could evenly fit into the n blocks with each block having k elements, it is guaranteed that at least one block must contain at least one more element than this average, ensuring that at least one block has k+1 elements. This simple yet powerful observation is the core idea behind the generalized pigeonhole principle.
Other exercises in this chapter
Problem 61
Show that if we have a function from a set of size \(n\) to a set of size less than \(n,\) then \(f\) is not one-to-one. \((\mathrm{h})\)
View solution Problem 62
Show that if \(S\) and \(T\) are finite sets of the same size, then a function \(f\) from \(S\) to \(T\) is one-to-one if and only if it is onto. (h)
View solution Problem 65
Show that in a set of six people, there is a set of at least three people who all know each other, or a set of at least three people none of whom know each othe
View solution Problem 60
American coins are all marked with the year in which they were made. How many coins do you need to have in your hand to guarantee that on two (at least) of them
View solution