Problem 63
Question
The equations in Exercises \(59-70\) combine the types of equations we have discussed in this section. Solve each equation or state that it is true for all real numbers or no real numbers. $$ 8 x-(3 x+2)+10=3 x $$
Step-by-Step Solution
Verified Answer
The solution is \(x = -4\).
1Step 1: Distribute the Subtraction
Distribute the subtraction operation over the terms inside the parentheses: \(8x - 3x - 2 + 10 = 3x\) .
2Step 2: Combine like Terms
Combine like terms on both sides of the equation: \(5x + 8 = 3x\).
3Step 3: Rearrange the Equation
Rearrange the equation to isolate \(x\) on one side. Subtract \(3x\) from each side of the equation to eliminate \(3x\) on the right side and simplify the left side: \(2x + 8 = 0 \). Then, subtract 8 from each side of the equation: \(2x = -8\).
4Step 4: Solve for \(x\)
Finally, solve for \(x\) by dividing each side of the equation by 2: \(x = -4\) .
Key Concepts
Distributive PropertyCombining Like TermsIsolating VariablesEquation Rearrangement
Distributive Property
The distributive property is a handy tool when working with equations, especially when you have parentheses involved. It allows you to multiply a single term by each term within the parentheses. In our specific problem, we use distribution to deal with subtraction by considering it as multiplying by -1. This approach helps in simplifying the initial equation, like converting:
- \(8x - (3x + 2) + 10\) becomes \(8x - 3x - 2 + 10\).
Combining Like Terms
Once you use the distributive property, the next step is combining like terms. Like terms are those that have the same variable and exponent, or no variable at all. For instance, in our problem, terms like \(8x\) and \(-3x\) are considered like terms because they both contain the variable \(x\). Right after distribution, what you do is:
- Add or subtract these similar terms together.
Isolating Variables
After combining like terms, the aim is to isolate the variable, so you can find its value. Isolating a variable means getting it by itself on one side of the equation. In our problem, the initial rearrangement \(5x + 8 = 3x\) shows this stage. You need to clear out the \(3x\) from one side to give us something more straightforward:
- Subtract \(3x\) from both sides which leaves \(2x + 8=0\).
Equation Rearrangement
Rearranging equations is about moving terms around to solve them. Once like terms are combined and the variable is isolated, you have to finalize the rearrangements to solve for it. In our solution, when \(2x + 8 = 0\) is achieved, subsequent steps involve:
- Subtract 8 to remove it from one side, leading to \(2x = -8\).
- Finally, divide both sides by 2 to completely isolate and determine \(x\), giving \(x = -4\).
Other exercises in this chapter
Problem 63
In Exercises \(57-76,\) solve each formula for the specified variable. Do you recognize the formula? If so, what does it describe? \(E=m c^{2}\) for \(m\)
View solution Problem 63
Solve each inequality in Exercises 57-84 by first rewriting each one as an equivalent inequality without absolute value bars. Graph the solution set on a number
View solution Problem 64
Solve each absolute value equation or indicate the equation has no solution. $$ |2 x-3|=11 $$
View solution Problem 64
Solve each equation in Exercises \(55-64\) using the quadratic formula. $$ x^{2}-2 x+17=0 $$
View solution