Problem 63
Question
The entropy values in \(\mathrm{J} \mathrm{K}^{-1} \mathrm{~mol}^{-1}\) of \(\mathrm{H}_{2}(\mathrm{~g})=130.6\), \(\mathrm{Cl}_{2}(\mathrm{~g})=223\) and \(\mathrm{HC} 1(\mathrm{~g})=186.7\) at \(298 \mathrm{~K}\) and 1 atm pressure. Then entropy change for the reaction \(\mathrm{H}_{2}(\mathrm{~g})+\mathrm{Cl}_{2}(\mathrm{~g}) \longrightarrow 2 \mathrm{HC} 1(\mathrm{~g})\) is (a) \(+540.3\) (b) \(+727.3\) (c) \(-166.9\) (d) \(+19.8\)
Step-by-Step Solution
Verified Answer
The entropy change is \( +19.8 \text{ J K}^{-1} \text{ mol}^{-1} \).
1Step 1: Understand the Reaction
The reaction given is \( \mathrm{H}_{2}(\mathrm{~g}) + \mathrm{Cl}_{2}(\mathrm{~g}) \longrightarrow 2 \ \mathrm{HC}1(\mathrm{~g}) \). We need to calculate the change in entropy for this reaction using the provided standard molar entropy values for each compound.
2Step 2: Write the Entropy Change Formula
The formula to find the entropy change \( \Delta S \) for a reaction is: \[ \Delta S = \sum ( S_{\text{products}}) - \sum ( S_{\text{reactants}}) \]Where \( S \) represents the standard molar entropy of the components. For this reaction, we calculate using the given molar entropy values.
3Step 3: Calculate the Entropy of Products
The product is \( 2 \mathrm{HC}l(\mathrm{~g}) \), and its entropy is given as 186.7 J K⁻¹ mol⁻¹. So, the total entropy for \( 2 \mathrm{HC}l \) is: \( 2 \times 186.7 = 373.4 \) J K⁻¹ mol⁻¹.
4Step 4: Calculate the Entropy of Reactants
For the reactants, we have \( \mathrm{H}_{2}(\mathrm{~g}) \) and \( \mathrm{Cl}_{2}(\mathrm{~g}) \) with entropies of 130.6 and 223 J K⁻¹ mol⁻¹, respectively. The total entropy for the reactants is: \( 130.6 + 223 = 353.6 \) J K⁻¹ mol⁻¹.
5Step 5: Find the Entropy Change
Now, substitute the values into the entropy change formula: \[ \Delta S = 373.4 - 353.6 = 19.8 \text{ J K}^{-1} \text{ mol}^{-1} \]. This result matches one of the options provided.
Key Concepts
Standard Molar EntropyThermodynamicsChemical ReactionsMolar Entropy Values
Standard Molar Entropy
Standard molar entropy is a critical concept in understanding how heat and energy are distributed in a chemical system. It's defined as the entropy content of one mole of substance under standard conditions, typically at 298 K and 1 atm pressure. This standardization allows chemists to compare entropy values across different substances and reactions.
In essence, standard molar entropy provides insight into the spontaneity of reactions and the disorder within a system. A higher value indicates more disorder or randomness, which is common in gases due to their free-moving particles. Calculating the standard molar entropy for substances involved in a reaction helps predict the energetic favorability of the reaction and its potential direction.
In essence, standard molar entropy provides insight into the spontaneity of reactions and the disorder within a system. A higher value indicates more disorder or randomness, which is common in gases due to their free-moving particles. Calculating the standard molar entropy for substances involved in a reaction helps predict the energetic favorability of the reaction and its potential direction.
- Helps in calculating the total entropy change.
- Important for understanding temperature and pressure conditions.
- Aids in determining the spontaneity of reactions.
Thermodynamics
Thermodynamics is the study of the changes in energy and matter within chemical processes. It provides the framework for understanding how entropy, enthalpy, and free energy connect and influence chemical reactions.
A core principle in thermodynamics is the Second Law, which states that the entropy of an isolated system will increase over time, ultimately reaching maximum disorder. This concept is critical for calculating the entropy change in reactions. When a reaction occurs, the entropy change can hint at the system's tendency to become more disordered.
A core principle in thermodynamics is the Second Law, which states that the entropy of an isolated system will increase over time, ultimately reaching maximum disorder. This concept is critical for calculating the entropy change in reactions. When a reaction occurs, the entropy change can hint at the system's tendency to become more disordered.
- Examines energy exchanges in reactions.
- Uses the Second Law to understand entropy increase.
- Links to predicting reaction spontaneity and equilibrium.
Chemical Reactions
Chemical reactions involve the conversion of reactants into products, often accompanied by changes in energy and matter configuration. Calculating the entropy change gives valuable insight into these transformations.
In the reaction given in the exercise, the reactants, hydrogen gas and chlorine gas, combine to form hydrogen chloride gas. By understanding standard molar entropy and thermodynamics, you can determine the entropy change of this specific reaction. If the products' entropy is greater, it suggests an increase in disorder, typical in energy-favorable reactions.
In the reaction given in the exercise, the reactants, hydrogen gas and chlorine gas, combine to form hydrogen chloride gas. By understanding standard molar entropy and thermodynamics, you can determine the entropy change of this specific reaction. If the products' entropy is greater, it suggests an increase in disorder, typical in energy-favorable reactions.
- Requires knowledge of reactants and products' entropies.
- Depends on the changes in the molecular arrangement and energy release or absorption.
- Lends insight into reaction kinetics and equilibrium.
Molar Entropy Values
Molar entropy values are essential for quantitative assessments in reaction calculations. Each substance in a chemical reaction has a particular molar entropy, measurable in
J K⁻¹ mol⁻¹ (joules per kelvin per mole).
In a balanced chemical equation, these values allow you to compute the total entropy change of the reaction. For instance, in the exercise, the molar entropy for each component – hydrogen gas, chlorine gas, and hydrogen chloride – must be known to find the final entropy change. By summing the standard molar entropies of the products and subtracting those of the reactants, you achieve the reaction's net entropy change, which tells you whether the process is energetically favorable.
In a balanced chemical equation, these values allow you to compute the total entropy change of the reaction. For instance, in the exercise, the molar entropy for each component – hydrogen gas, chlorine gas, and hydrogen chloride – must be known to find the final entropy change. By summing the standard molar entropies of the products and subtracting those of the reactants, you achieve the reaction's net entropy change, which tells you whether the process is energetically favorable.
- Used for calculating reaction entropy change.
- Assists in understanding reaction spontaneity.
- Important for analyzing energy transformations.
Other exercises in this chapter
Problem 61
For a reaction at \(300 \mathrm{~K}\), enthalpy and entropy changes are \(-11.5 \times 10^{3} \mathrm{~J} \mathrm{~mol}^{-1}\) and \(-105 \mathrm{JK}^{-1} \math
View solution Problem 62
The standard enthalpy of decomposition of \(\mathrm{N}_{2} \mathrm{O}_{4}\) to \(\mathrm{NO}_{2}\) is \(58.04 \mathrm{~kJ}\) and standard entropy of this reacti
View solution Problem 65
2 moles of an ideal gas is expanded isothermally and reversibly from 1 litre of 10 litre at \(300 \mathrm{~K}\). The enthalpy change (in \(\mathrm{kJ}\) ) for t
View solution Problem 66
The enthalpy of vaporization of a liquid is \(30 \mathrm{~kJ} \mathrm{~mol}^{-1}\) and entropy of vaporization is \(5 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}
View solution