Problem 63
Question
Suppose \(f\) and \(g\) are functions with continuous derivatives on an interval containing \([a, b] .\) Prove that if \(f(a) \leq g(a)\) and if \(f^{\prime}(x) \leq g^{\prime}(x)\) for all \(x\) in \([a, b],\) then \(f(x) \leq g(x)\) for all \(x\) in \([a, b]\)
Step-by-Step Solution
Verified Answer
The given conditions imply \(f(x) \leq g(x)\) for all \(x\) in \([a, b]\) by analyzing \(h(x) = f(x) - g(x)\).
1Step 1: Understanding the Problem
We need to prove that if two functions, \(f\) and \(g\), have continuous derivatives on an interval and satisfy \(f(a) \leq g(a)\) and \(f'(x) \leq g'(x)\), then \(f(x) \leq g(x)\) holds for all \(x\) in \([a, b]\).
2Step 2: Define a New Function
Define a new function \(h(x) = f(x) - g(x)\). Given the conditions, we have \(h(a) \leq 0\).
3Step 3: Derivative Analysis of h(x)
Find the derivative of \(h(x)\), which is \(h'(x) = f'(x) - g'(x)\). From the assumption, \(f'(x) \leq g'(x)\), thus \(h'(x) \leq 0\).
4Step 4: Apply the Mean Value Theorem
Since \(h(x)\) is a function with a continuous derivative, use the Mean Value Theorem on \([a, x]\) for any \(x\in[a,b]\). There exists a \(c\in[a,x]\) such that \(h'(c) = \frac{h(x) - h(a)}{x - a}\).
5Step 5: Conclude with Inequality
Since \(h'(x) \leq 0\), by the Mean Value Theorem, \(h(x) \leq h(a)\). Given \(h(a) \leq 0\), we find \(h(x) \leq 0\), leading to \(f(x) \leq g(x)\) for all \(x\in[a, b]\).
Key Concepts
Continuous DerivativesInequalityDifferentiable Functions
Continuous Derivatives
In calculus, a function possessing a continuous derivative means that both the function and its derivative are well-behaved without any abrupt changes. This continuity implies two things: first that the function is smooth, and second, that there are no jumps or breaks in either the function itself or its derivative.
This concept is essential because when you apply the Mean Value Theorem or similar concepts, continuity of derivatives ensures that you can smoothly "travel" along the curve without unexpected stops. Think of it like driving on a highway without any sudden roadblocks. Everything flows precisely as it should.
This concept is essential because when you apply the Mean Value Theorem or similar concepts, continuity of derivatives ensures that you can smoothly "travel" along the curve without unexpected stops. Think of it like driving on a highway without any sudden roadblocks. Everything flows precisely as it should.
- Allows usage of important theorems like the Mean Value Theorem.
- Makes sure that changes in the function are predictable and smooth.
Inequality
In mathematics, an inequality explains how two elements compare within a mathematical sentence. Inequalities tell us which element is larger, smaller, or if they are potentially equal under particular conditions.
In this problem, we encounter inequalities like \(f(a) \leq g(a)\) and \(f'(x) \leq g'(x)\). These inequalities give us foundational relationships that must persist across the interval \([a, b]\).
In this problem, we encounter inequalities like \(f(a) \leq g(a)\) and \(f'(x) \leq g'(x)\). These inequalities give us foundational relationships that must persist across the interval \([a, b]\).
- \(f(a) \leq g(a)\) implies initially, function \(f\) is not greater than \(g\).
- \(f'(x) \leq g'(x)\) tells us that the rate of change (slope) of \(f\) is not steeper than that of \(g\).
Differentiable Functions
A function being differentiable means that it has a derivative at each point in its domain. Differentiability is not just about having a derivative, but also about having a derivative that is well-defined and finite everywhere on the interval.
In our exercise, \(f\) and \(g\) are both assumed to be differentiable over \([a, b]\). This implies:
In our exercise, \(f\) and \(g\) are both assumed to be differentiable over \([a, b]\). This implies:
- The functions are smooth, with no sharp corners or cusps.
- They have a derivative everywhere on the interval.
Other exercises in this chapter
Problem 63
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