Problem 63
Question
Solve for the specified variable. $$F=\frac{\pi P R^{4}}{8 V L} \text { for } R$$
Step-by-Step Solution
Verified Answer
\( R = \sqrt[4]{\frac{8 F V L}{\pi P}} \)
1Step 1: Understand the Equation
The equation given is: \[ F = \frac{\pi P R^{4}}{8 V L} \]We need to solve this equation for the variable \( R \). This means isolating \( R \) on one side of the equation.
2Step 2: Multiply Both Sides by the Denominator
To remove the fraction, multiply both sides by \( 8 V L \):\[ F \times 8 V L = \pi P R^{4} \]This simplifies to:\[ 8 F V L = \pi P R^{4} \]
3Step 3: Divide by the Coefficient of \( R^4 \)
Now divide both sides by \( \pi P \) to isolate \( R^4 \):\[ \frac{8 F V L}{\pi P} = R^{4} \]
4Step 4: Take the Fourth Root
To solve for \( R \), take the fourth root of both sides:\[ R = \sqrt[4]{\frac{8 F V L}{\pi P}} \]This gives us \( R \) in terms of the other variables.
Key Concepts
Equation ManipulationAlgebraic IsolationExponentiation and Roots
Equation Manipulation
Equation manipulation is a crucial skill in algebra, as it allows you to rearrange an equation to solve for a particular variable. In our exercise, manipulating the equation involves dealing with a fraction and rearranging terms to isolate the desired variable.
Start by identifying what you need to solve for—in this case, it's the variable \( R \). The original equation is in the form \( F = \frac{\pi P R^{4}}{8 V L} \). Notice that \( R \) is part of a larger fraction. To solve for \( R \), you must first "undo" this fraction to free \( R \) from the denominator.
Multiply both sides of the equation by the entire denominator \( 8 V L \). This step is critical in removing the fraction:
Start by identifying what you need to solve for—in this case, it's the variable \( R \). The original equation is in the form \( F = \frac{\pi P R^{4}}{8 V L} \). Notice that \( R \) is part of a larger fraction. To solve for \( R \), you must first "undo" this fraction to free \( R \) from the denominator.
Multiply both sides of the equation by the entire denominator \( 8 V L \). This step is critical in removing the fraction:
- \( F \times 8 V L = \pi P R^{4} \)
Algebraic Isolation
Algebraic isolation refers to the process of getting the variable you’re solving for on its own on one side of the equation. When isolating a variable, you undo any addition, subtraction, multiplication, or division that’s affecting that variable.
In our example, after removing the fraction, the equation simplifies to \( 8 F V L = \pi P R^{4} \). Now, the goal is to have \( R^{4} \) by itself. To accomplish this, divide both sides by \( \pi P \), which is the coefficient accompanying \( R^{4} \):
In our example, after removing the fraction, the equation simplifies to \( 8 F V L = \pi P R^{4} \). Now, the goal is to have \( R^{4} \) by itself. To accomplish this, divide both sides by \( \pi P \), which is the coefficient accompanying \( R^{4} \):
- \( \frac{8 F V L}{\pi P} = R^{4} \)
Exponentiation and Roots
Exponentiation and its inverse operation, roots, are used to manage powers when solving equations. An exponent indicates how many times a number is multiplied by itself. Conversely, taking a root undoes this multiplication, which is essential when a variable is raised to a power.
In this problem, \( R \) is raised to the fourth power (\( R^{4} \)). To "undo" this, you need to take the fourth root of both sides. This operation will solve for \( R \):
In this problem, \( R \) is raised to the fourth power (\( R^{4} \)). To "undo" this, you need to take the fourth root of both sides. This operation will solve for \( R \):
- \( R = \sqrt[4]{\frac{8 F V L}{\pi P}} \)
Other exercises in this chapter
Problem 63
Simplify the expression, and rationalize the denominator when appropriate. \(\sqrt{9 x^{-4} y^{6}}\)
View solution Problem 63
The formula occurs in the indicated application. Solve for the specified variable. \(d=\frac{1}{2} \sqrt{4 R^{2}-C^{2}}\) for \(C\) (segments of circles)
View solution Problem 63
Rationalize the denominator. $$\frac{1}{\sqrt[3]{a}-\sqrt[3]{b}}$$
View solution Problem 64
Simplify the expression, and rationalize the denominator when appropriate. $$\sqrt{16 a^{8} b^{-2}}$$
View solution