Problem 63
Question
Solve each problem. Back Stress If a person bends at the waist with a straight back, making an angle of \(\theta\) degrees with the horizontal, then the force \(F\) exerted on the back muscles can be modeled by the equation $$F=\frac{0.6 W \sin \left(\theta+90^{\circ}\right)}{\sin 12^{\circ}}$$ where \(W\) is the weight of the person. (Source: Metcalf, H., Topics in Classical Biophysics, Prentice- Hall.) (a) Calculate \(F\) when \(W=170\) pounds and \(\theta=30^{\circ}\) (b) Use an identity to show that \(F\) is approximately equal to \(2.9 \mathrm{W} \cos \theta\) (c) For what value of \(\theta\) is \(F\) maximum?
Step-by-Step Solution
Verified Answer
(a) Calculate using specific values. (b) Prove the approximation with an identity. (c) Max value when \(\theta = 0^{\circ}\).
1Step 1: Substitute given values into the equation
For part (a), we are provided with \(W = 170\) pounds and \(\theta = 30^{\circ}\). Substitute these values into the equation for \(F\):\[F = \frac{0.6 \times 170 \times \sin(30^{\circ} + 90^{\circ})}{\sin 12^{\circ}}.\]
2Step 2: Simplify using trigonometric identities
Calculate \(\sin(120^{\circ})\) since \(30^{\circ} + 90^{\circ} = 120^{\circ}\). We know that \(\sin(120^{\circ}) = \sin(180^{\circ} - 60^{\circ}) = \sin(60^{\circ}) = \frac{\sqrt{3}}{2}\).
3Step 3: Calculate F
Substitute \(\sin(120^{\circ}) = \frac{\sqrt{3}}{2}\) and \(\sin(12^{\circ})\) into the equation:\[F = \frac{0.6 \times 170 \times \frac{\sqrt{3}}{2}}{\sin 12^{\circ}}.\]Use a calculator to find \(F\).
4Step 4: Use identity to prove the approximation
For part (b), use the identity \(\sin(\theta + 90^{\circ}) = \cos \theta\) to rewrite the equation as:\[F = \frac{0.6 W \cos \theta}{\sin 12^{\circ}}.\]Given \(\frac{0.6}{\sin 12^{\circ}} \approx 2.9\), we can state: \[F \approx 2.9 W \cos \theta.\]
5Step 5: Determine maximum value of F
For part (c), the function has its maximum value when \(\cos \theta\) is maximized. Since -1 to 1 is the range for \(\cos \theta\), \(\cos \theta\) reaches its maximum value of 1 when \(\theta = 0^{\circ}\).
Key Concepts
Trigonometric IdentitiesTrigonometric EquationsProblem Solving
Trigonometric Identities
Trigonometric identities are equations that involve trigonometric functions and are true for every value of the variable. They help us simplify expressions and solve trigonometric equations more easily. In this exercise, you can see how a trigonometric identity can transform a problem involving sine into one involving cosine.
One essential identity used here is the relationship
Understanding trigonometric identities is crucial for breaking down complex trigonometric equations into simpler forms. This allows for easier calculations and insights into the relationships of the trigonometric functions involved.
One essential identity used here is the relationship
- \(\sin(\theta + 90^\circ) = \cos \theta\)
Understanding trigonometric identities is crucial for breaking down complex trigonometric equations into simpler forms. This allows for easier calculations and insights into the relationships of the trigonometric functions involved.
Trigonometric Equations
Trigonometric equations are equations that involve trigonometric functions, such as sine, cosine, and tangent. Solving them involves finding unknown angles that satisfy the equation. In this exercise, we dealt with an equation that modeled the force exerted on back muscles.
The equation given was:
The equation given was:
- \[F = \frac{0.6 W \sin \left(\theta+90^{\circ}\right)}{\sin 12^{\circ}}\]
- \[F \approx 2.9 W \cos \theta\]
Problem Solving
Problem-solving with trigonometry often involves the sequential application of mathematical principles and identities to arrive at a solution. This exercise gave us a real-world scenario where an analytical approach was required to find the desired values.
To solve such problems effectively:
To solve such problems effectively:
- Start by identifying known values and substituting them into the given formula.
- Use trigonometric identities to simplify the equation if necessary. This often involves transforming between sine and cosine, as shown in this problem.
- Then, solve the equation to find the numeric values or to express in simpler forms.
- \(\cos \theta\) reaches its maximum when \(\theta = 0^\circ\)
Other exercises in this chapter
Problem 62
Give solutions over the interval \([0,2 \pi)\) as approximations to the nearest hundredth when exact values cannot be determined. You may need to use the quadra
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Perform indicated operation and simplify the result. $$\frac{\sec x}{\csc x}+\frac{\csc x}{\sec x}$$
View solution Problem 63
Verify that each equation is an identity. $$\cos 2 \theta=\frac{2-\sec ^{2} \theta}{\sec ^{2} \theta}$$
View solution Problem 63
Give solutions over the interval \([0,2 \pi)\) as approximations to the nearest hundredth when exact values cannot be determined. You may need to use the quadra
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