Problem 63
Question
Solve each equation. Use words or set notation to identify equations that have no solution, or equations that are true for all real numbers. $$7+2(3 x-5)=8-3(2 x+1)$$
Step-by-Step Solution
Verified Answer
The solution to the equation is \(x = \frac{2}{3}\).
1Step 1: Apply Distributive Property
Distribute the values outside the parentheses to all the values within. So, \(7 + 2(3x - 5) = 8 - 3(2x + 1)\) simplifies into: \(7 + 6x - 10 = 8 - 6x - 3\).
2Step 2: Simplify
Combine like terms on the left-hand side (LHS) and right-hand side (RHS) of the equation. This gives: \( -3 + 6x = 5 - 6x \).
3Step 3: Isolate the Variable x
Moving \(6x\) from LHS to RHS gives: \( -3 = 5 - 12x \). Further simplifying by moving constants out and reversing the equation, we get: \(12x = 5 + 3 \).
4Step 4: Solving for x
Final step is to divide by \(12\) on both sides to isolate \(x\), so we get: \(x = \frac{8}{12} = \frac{2}{3}\).
Key Concepts
Distributive PropertyIsolate VariableCombine Like TermsSimplifying Equations
Distributive Property
Understanding the distributive property is key to solving equations when there are parentheses involved. This mathematical property allows you to multiply a single term across terms inside parentheses. In the original exercise, we have terms like \(2(3x - 5)\) and \(-3(2x + 1)\).
- For the expression \(2(3x - 5)\), you'll distribute the \(2\) to both \(3x\) and \(-5\), resulting in \(6x - 10\).
- Similarly, \(-3(2x + 1)\) becomes \(-6x - 3\) after applying the distributive property.
Isolate Variable
Once you've expanded and simplified both sides of the equation, the next step is to isolate the variable. Isolating the variable means rearranging the equation so the variable, typically \(x\), is one side alone.
This is done by moving all terms involving \(x\) to one side and constants to the other.
In the solution of our exercise, you saw that after simplifying, we have \(-3 + 6x = 5 - 6x\). From here, we moved \(6x\) from the left side to the right side, which requires adding \(6x\) to both sides, giving \( -3 = 5 - 12x\).
This type of manipulation ensures that you can focus solely on solving for \(x\) without extra numbers crowding the equation.
This is done by moving all terms involving \(x\) to one side and constants to the other.
In the solution of our exercise, you saw that after simplifying, we have \(-3 + 6x = 5 - 6x\). From here, we moved \(6x\) from the left side to the right side, which requires adding \(6x\) to both sides, giving \( -3 = 5 - 12x\).
This type of manipulation ensures that you can focus solely on solving for \(x\) without extra numbers crowding the equation.
Combine Like Terms
Combining like terms is a crucial part of simplifying equations. This involves adding or subtracting terms that have identical variables raised to the same power, or simply merging constant terms.
In the example given, after distributing the terms, we noticed expressions that could be combined:
In the example given, after distributing the terms, we noticed expressions that could be combined:
- On the left side, terms \(7\) and \(-10\) can be combined to give \(-3\).
- Similarly, on the right side, \(8\) and \(-3\) give \(5\).
Simplifying Equations
Simplifying equations is essentially tidying things up. It involves using the properties we discussed — like distribution and combining like terms — to make the equation as straightforward as possible.
You need to ensure each side of your equation is reduced to its simplest form. In the exercise, simplifying \(7 + 6x - 10 = 8 - 6x - 3\) results in \(-3 + 6x = 5 - 6x\).
Simplification highlights the relationships between numbers and terms, allowing you to isolate variables more easily.
Think of it as decluttering the equation. You want to see the key components — the terms involving \(x\) and the constants — clearly, which leads to quicker and more efficient problem-solving.
You need to ensure each side of your equation is reduced to its simplest form. In the exercise, simplifying \(7 + 6x - 10 = 8 - 6x - 3\) results in \(-3 + 6x = 5 - 6x\).
Simplification highlights the relationships between numbers and terms, allowing you to isolate variables more easily.
Think of it as decluttering the equation. You want to see the key components — the terms involving \(x\) and the constants — clearly, which leads to quicker and more efficient problem-solving.
Other exercises in this chapter
Problem 63
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