Problem 63
Question
Simplify. See Example \(8 .\) $$ \frac{2-a}{a^{2}-a-2} $$
Step-by-Step Solution
Verified Answer
The expression simplifies to \(-\frac{1}{a+1}\).
1Step 1: Identify the Denominator
The denominator of the fraction is the expression \(a^{2} - a - 2\).
2Step 2: Factor the Quadratic Expression
The quadratic expression \(a^{2} - a - 2\) factors into two binomials. We look for two numbers that multiply to \(-2\) and add to \(-1\). These numbers are \(-2\) and \(1\), so \(a^{2} - a - 2 = (a-2)(a+1)\).
3Step 3: Rewrite the Fraction
Substitute the factored form of the denominator back into the fraction. This gives \[ \frac{2-a}{(a-2)(a+1)} \]
4Step 4: Simplify the Fraction
Notice that the numerator \(2-a\) can be rewritten as \(-1(a-2)\). This is because \(2-a = -(a-2)\). Thus, the fraction becomes \[-\frac{a-2}{(a-2)(a+1)}\]
5Step 5: Cancel Common Factors
The expression \(a-2\) appears in both the numerator and the denominator, so they can be cancelled out, resulting in \[ -\frac{1}{a+1} \]
6Step 6: Present the Simplified Expression
The fraction simplifies to \[ -\frac{1}{a+1} \]
Key Concepts
Simplifying ExpressionsFactoring QuadraticsCanceling Common Factors
Simplifying Expressions
Simplifying algebraic expressions is an essential skill in algebra. The goal is to make expressions as concise and clear as possible, which often involves reducing fractions and combining like terms. When simplifying fractions, we aim to write them in their simplest form. This usually involves factoring and canceling out any common factors between the numerator and the denominator.
In the context of our original exercise, we began with the expression \( \frac{2-a}{a^{2}-a-2} \). The initial step was to factor the denominator, recognizing it as a quadratic that could be rewritten as a product of two binomials. Once rewritten as \((a-2)(a+1)\), it allowed us to see common factors more clearly, which is crucial for the simplification process.
By rewriting the numerator \(2-a\) as \(-1(a-2)\), we located a common factor that could be canceled, ultimately simplifying the expression.
Simplifying saves time and reduces complexity, making further calculations or comparisons easier.
In the context of our original exercise, we began with the expression \( \frac{2-a}{a^{2}-a-2} \). The initial step was to factor the denominator, recognizing it as a quadratic that could be rewritten as a product of two binomials. Once rewritten as \((a-2)(a+1)\), it allowed us to see common factors more clearly, which is crucial for the simplification process.
By rewriting the numerator \(2-a\) as \(-1(a-2)\), we located a common factor that could be canceled, ultimately simplifying the expression.
Simplifying saves time and reduces complexity, making further calculations or comparisons easier.
Factoring Quadratics
Factoring quadratics is a method used to express a quadratic equation in a simpler form by finding its binomial factors. This process is especially useful in simplifying fractions where a quadratic is in the denominator.
Let's examine the quadratic expression \(a^2 - a - 2\). To factor it, we needed numbers that multiply to the constant term \(-2\) and add up to the linear coefficient \(-1\).
Let's examine the quadratic expression \(a^2 - a - 2\). To factor it, we needed numbers that multiply to the constant term \(-2\) and add up to the linear coefficient \(-1\).
- Here, the numbers were \(-2\) and \(+1\).
- This allowed us to break the quadratic into \((a-2)(a+1)\).
Canceling Common Factors
Canceling common factors is a significant simplification strategy in algebra. It involves eliminating identical elements present in both the numerator and the denominator of a fraction, thereby reducing it to its simplest form.
Take our fraction from the exercise: \[-\frac{a-2}{(a-2)(a+1)}\]. The factor \(a-2\) was in both the top and the bottom. By canceling these out, we simplified the fraction to \(-\frac{1}{a+1}\).
Take our fraction from the exercise: \[-\frac{a-2}{(a-2)(a+1)}\]. The factor \(a-2\) was in both the top and the bottom. By canceling these out, we simplified the fraction to \(-\frac{1}{a+1}\).
- Canceling is only applicable when the same factor appears in the numerator and denominator.
- This process should not change the value of the expression, aside from its complexity and appearance.
Other exercises in this chapter
Problem 63
Perform the operations. Simplify, if possible. $$ \frac{g}{g^{2}-4}+\frac{2}{4-g^{2}} $$
View solution Problem 63
Solve each proportion. $$ \frac{c}{10}=\frac{10}{c} $$
View solution Problem 63
Simplify each complex fraction. $$ \frac{\frac{m}{n}+\frac{n}{m}}{\frac{m}{n}-\frac{n}{m}} $$
View solution Problem 63
Solve each equation and check the result. If an equation has no solution, so indicate. $$ \frac{1}{3}+\frac{2}{x-3}=1 $$
View solution