Problem 63
Question
simplify each complex rational expression. $$ \frac{\frac{1}{x}+\frac{1}{y}}{x+y} $$
Step-by-Step Solution
Verified Answer
The simplified form of the complex rational expression \(\frac{\frac{1}{x}+\frac{1}{y}}{x+y}\) is \(\frac{1}{xy}\).
1Step 1: Find a common denominator for the fractions in the numerator
Here, both fractions in the numerator have different denominators, \(x\) and \(y\). So, the LCD (Least Common Denominator) will be \(xy\). The LCD is then multiplied with each fraction. That simplifies \(\frac{1}{x}+\frac{1}{y}\) to \(\frac{y}{xy} + \frac{x}{xy}\) = \(\frac{x+y}{xy}\)
2Step 2: Recreate the complex fraction
In this step, replace the original numerator \(\frac{1}{x}+\frac{1}{y}\) with \(\frac{x+y}{xy}\) which was done in step one. Now, the complex function becomes \(\frac{\frac{x+y}{xy}}{x+y}\).
3Step 3: Simplify the complex fraction
To simplify, multiply the whole expression by the reciprocal of the denominator. This cancels out the \(x+y\) terms on top and bottom of the fraction. Therefore, the fraction simplifies to \(\frac{1}{xy}\)
Key Concepts
Understanding Algebra: The BasicsFinding the Least Common DenominatorSimplifying Fractions: The Key Steps
Understanding Algebra: The Basics
Algebra is the language of mathematics that helps us express patterns and relationships using numbers and symbols. Think of it as a way of solving problems by finding the unknowns. In this exercise, we use algebraic techniques to simplify a complex rational expression. Complex rational expressions often include fractions within fractions. These can look tricky, but with a systematic approach, they become manageable.
When working with algebra, it's essential to be comfortable with:
When working with algebra, it's essential to be comfortable with:
- Variables, such as \(x\) and \(y\), which can hold any number.
- Operations, including addition, subtraction, multiplication, and division.
- Manipulating expressions to find a solution.
Finding the Least Common Denominator
The Least Common Denominator (LCD) is critical when dealing with fractions. It helps you combine fractions into a single expression. When you have fractions with different denominators, like \(\frac{1}{x}\) and \(\frac{1}{y}\), finding the LCD involves identifying the smallest common multiple of these denominators.
For our exercise, the denominators are \(x\) and \(y\). The smallest multiple that both can divide is \(xy\). By converting fractions to a common denominator, you make it easy to add or subtract them. Here's a quick process:
For our exercise, the denominators are \(x\) and \(y\). The smallest multiple that both can divide is \(xy\). By converting fractions to a common denominator, you make it easy to add or subtract them. Here's a quick process:
- Multiply each fraction's numerator and denominator by a term that would create the LCD.
- For \(\frac{1}{x}\), multiply by \(\frac{y}{y}\) to get \(\frac{y}{xy}\).
- For \(\frac{1}{y}\), multiply by \(\frac{x}{x}\) to get \(\frac{x}{xy}\).
- Add these fractions together to form \(\frac{x+y}{xy}\).
Simplifying Fractions: The Key Steps
Simplifying fractions involves reducing them to their simplest form so that they are more understandable and easier to work with. In our complex rational expression, this means transforming \(\frac{\frac{x+y}{xy}}{x+y}\) into something simpler. Here’s how you can think about it:
- You have a fraction within a fraction – the numerator is already simplified using the LCD.
- To simplify the entire expression, multiply by the reciprocal of the denominator. The denominator is \(x+y\).
- Multiplying by the reciprocal \(\frac{1}{x+y}\) cancels out the \(x+y\) terms.
- The result is \(\frac{1}{xy}\), a simpler and clearer expression.
Other exercises in this chapter
Problem 62
Evaluate each algebraic expression for x = 2 and y = -5. $$|x-y|$$
View solution Problem 62
Simplify each exponential expression. $$ \left(\frac{-30 a^{14} b^{8}}{10 a^{17} b^{-2}}\right)^{3} $$
View solution Problem 63
Factor using the formula for the sum or difference of two cubes. $$64 x^{3}+27$$
View solution Problem 63
Evaluate each expression in Exercises \(55-66,\) or indicate that the root is not a real number. $$ \sqrt[5]{(-3)^{5}} $$
View solution