Problem 63
Question
Simplify each complex rational expression. $$\frac{\frac{1}{x}+\frac{1}{y}}{x+y}$$
Step-by-Step Solution
Verified Answer
The simplified form of the given complex rational expression is \(\frac{1}{xy}\).
1Step 1: Identify the Denominator
The denominator of the complex rational expression is \(x + y\), and this will be retained in the simplified form.
2Step 2: Find the Common Denominator
In the numerator, the common denominator for the fractions \(\frac{1}{x}\) and \(\frac{1}{y}\) is \(x * y\) or \(xy\). Hence, you rewrite these fractions as \(\frac{y}{xy}\) and \(\frac{x}{xy}\), respectively.
3Step 3: Simplify the Numerator
Add those fractions to simplify the numerator - which becomes \(\frac{x+y}{xy}\). So, the complex fraction can now be rewritten as \(\frac{(x+y)/xy}{x+y}\).
4Step 4: Multiply the main Numerator and Denominator by the reciprocal
When you have a fraction within a fraction, you can multiply the main numerator and denominator by the reciprocal of the denominator. So, multiply the complex fraction by \( \frac{xy}{1}\), which simplifies to \(\frac{(x+y)}{(x+y)*xy} = \frac{1}{xy}\).
Other exercises in this chapter
Problem 63
Evaluate each expression or indicate that the root is not a real number. $$\sqrt[5]{(-3)^{5}}$$
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Perform the indicated operations Indicate the degree of the resulting polynomial. $$ \left(x^{3}+7 x y-5 y^{2}\right)-\left(6 x^{3}-x y+4 y^{2}\right) $$
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Simplify each exponential expression in Exercises 23–64. $$\left(\frac{3 a^{-5} b^{2}}{12 a^{3} b^{-4}}\right)^{0}$$
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Factor using the formula for the sum or difference of tho cubes. $$ 8 x^{3}+125 $$
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