Problem 63
Question
Show that $$ |a+b+c| \leq|a|+|b|+|c| $$ for all real numbers \(a, b,\) and \(c .\) Hint: The left-hand side can be written \(|a+(b+c)| .\) Now use the triangle inequality.
Step-by-Step Solution
Verified Answer
By applying the triangle inequality, we verify the inequality.
1Step 1: Understand the Triangle Inequality
The triangle inequality states that for any real numbers, \(x\) and \(y\), the absolute value of their sum is less than or equal to the sum of their absolute values: \(|x+y| \leq |x| + |y|\). This property will be used to prove the given inequality.
2Step 2: Apply the Triangle Inequality to Sum of b and c
Consider the expression \(|b+c|\). According to the triangle inequality, we have:\[|b+c| \leq |b| + |c|\]
Key Concepts
Absolute ValueInequality ProofReal Numbers
Absolute Value
The absolute value of a number is essentially a measure of how far that number is from zero on the number line, regardless of its direction. It's denoted as \(|x|\), where \(x\) can be any real number. The absolute value of a number is always non-negative. This is because it either retains the number itself if it's already positive or converts it to positive if it was initially negative.
- If \(x \, \geq \, 0\), then \(|x| = x\).
- If \(x \, < \, 0\), then \(|x| = -x\).
Inequality Proof
Inequality proofs are important in mathematics as they establish the relative sizes of expressions without needing to know their exact values. In this exercise, you are asked to prove an inequality involving the sum of three real numbers and their absolute values. The hint suggests rewriting the expression in a specific way to aid the proof.
An inequality proof often involves several primary strategies:
An inequality proof often involves several primary strategies:
- Direct application of known inequalities, such as the triangle inequality.
- Breaking down complex expressions into simpler parts.
- Using algebraic manipulations to relate the given inequality to known results.
Real Numbers
Real numbers are an encompassing set that includes numbers from the domains of both rational and irrational numbers. Essentially, they cover every point on the number line.
Real numbers can be:- Positive numbers like 1, 2, and 3.- Negative numbers like -1, -2, and -3.- Zero.- Fractions and decimals like 0.5, or \(rac{3}{4}\).- Irrational numbers, which cannot be expressed as a simple fraction, like \(\pi\) or \(\sqrt{2}\).The concept of real numbers is fundamental because they provide the complete system of numbers that are used in everyday mathematics and scientific calculations. In this exercise, we're specifically working with real numbers \(a\), \(b\), and \(c\) to explore their properties through inequalities. This ensures that the statements and proofs we deal with apply broadly and generally, beyond just whole numbers. Understanding the behaviors and properties of real numbers allows for thoroughly addressing more complex mathematical topics.
Real numbers can be:- Positive numbers like 1, 2, and 3.- Negative numbers like -1, -2, and -3.- Zero.- Fractions and decimals like 0.5, or \(rac{3}{4}\).- Irrational numbers, which cannot be expressed as a simple fraction, like \(\pi\) or \(\sqrt{2}\).The concept of real numbers is fundamental because they provide the complete system of numbers that are used in everyday mathematics and scientific calculations. In this exercise, we're specifically working with real numbers \(a\), \(b\), and \(c\) to explore their properties through inequalities. This ensures that the statements and proofs we deal with apply broadly and generally, beyond just whole numbers. Understanding the behaviors and properties of real numbers allows for thoroughly addressing more complex mathematical topics.
Other exercises in this chapter
Problem 62
Show that for all real numbers \(a\) and \(b,\) we have $$ |a|-|b| \leq|a-b| $$ Hint: Beginning with the identity \(a=(a-b)+b,\) take the absolute value of each
View solution Problem 62
Solve each equation for \(x\) in terms of the other letters. $$\frac{x+2 p}{2 q-x}+\frac{x-2 p}{2 q+x}-\frac{4 p q}{4 q^{2}-x^{2}}=0$$
View solution Problem 63
Solve each equation for \(x\) in terms of the other letters. $$\frac{x-a}{x-b}=\frac{b-x}{a-x}, \text { where } a \neq b$$
View solution Problem 64
Explain why there are no real numbers that satisfy the equation \(\left|x^{2}+4 x\right|=-12\).
View solution