Problem 63
Question
In Exercises 63–68, find the solution set for each system by graphing both of the system’s equations in the same rectangular coordinate system and finding points of intersection. Check all solutions in both equations. $$ \left\\{\begin{aligned} (y-2)^{2} &=x+4 \\ y &=-\frac{1}{2} x \end{aligned}\right. $$
Step-by-Step Solution
Verified Answer
The system of equations do not have any solution as none of the intersection points satisfies both equations simultaneously.
1Step 1: Rewrite the Equations
The first equation \( (y-2)^{2} =x+4 \) can be rewritten as \( y = \sqrt{x + 4} + 2 \) and the second equation \( y = -\frac{1}{2} x \) remains as it is.
2Step 2: Graph the Equations
Next, graph the two equations in the same coordinate system.\\For the square root function, start from (-4,2), which is the vertex. Since it is a square root function starting from 2 the graph will be quarter of a circle opening upwards.\\For the linear function with a negative slope, draw a straight line that starts from the origin (0,0) and goes downwards to the right.
3Step 3: Find Points of Intersection
The solution to the system of equations are the points where the two graphs intersect. From the graph, it can be seen that the two graphs intersect at two points. They are approximately (-2,3) and (0,2).
4Step 4: Verify the Solutions
Lastly, verify that these points are solutions for both equations.\\For checkpoint (-2,3), put these values into both equations: \\ For the first equation: \( (3-2)^{2} =-2+4 \) which simplifies to \( 1=2 \), which is a false statement. Therefore, (-2,3) is not a solution.\\For checkpoint (0,2), put these values into both equations:\\For the first equation: \( (2-2)^{2} =0+4 \), which simplifies to \( 0=4 \), which is again a false statement. Therefore, (0,2) is also not a solution.\\Thus, no solutions were found.
Key Concepts
GraphingSolution SetRectangular Coordinate SystemIntersection Points
Graphing
Graphing is a powerful method used to find solutions to systems of equations, especially when it's hard to solve analytically. It involves plotting equations on a graph to see where they intersect. Each equation is represented as a curve or line. By comparing their graphical representations, we can visually identify common points which, if any, are the solutions to the system.
- For non-linear equations, the graph can be a curve such as a parabola, hyperbola, or another type of curve depending on the function involved.
- For linear equations, like our second equation, the graph is a straight line.
Solution Set
The solution set of a system of equations consists of all the intersection points of the graphs of those equations. In essence, these are the points that satisfy all the given equations at once.
- In our exercise, we attempted to figure out where the output of each function overlaps, indicating that an x-value gives the same y-value in both equations.
- Once you identify these points from the graph, these are the candidates for the solution set, assuming the graphing is accurate and correctly identifies all intersections.
Rectangular Coordinate System
The rectangular coordinate system, also known as the Cartesian coordinate system, is the framework used to graph equations visually. It consists of two perpendicular axes:
On interacting with it, the system makes it easier to detect when and where graphs will intersect, which is essential for solving systems of equations by the graphing method.
- The horizontal axis is called the x-axis.
- The vertical axis is known as the y-axis.
On interacting with it, the system makes it easier to detect when and where graphs will intersect, which is essential for solving systems of equations by the graphing method.
Intersection Points
Intersection points occur when two graphs meet at certain coordinates on the xy-plane; such points provide potential solutions for a system of equations. If each point satisfies all equations involved, it belongs to the solution set. During the graphing of our exercise:
This lesson underscores the importance of not only finding these points but also checking if they satisfy all involved equations.
- We anticipated intersection points like (-2, 3) and (0, 2) based on our plotted graphs.
- However, on verifying these points with the original equations, neither of them held true as solutions.
This lesson underscores the importance of not only finding these points but also checking if they satisfy all involved equations.
Other exercises in this chapter
Problem 63
In Exercises \(61-66,\) find the solution set for each system by graphing both of the system's equations in the same rectangular coordinate system and finding p
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Sketch the function represented by the given parametric equations. Then use the graph to determine each of the following: a. intervals, if any, on which the fun
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An architect designs two houses that are shaped and positioned like a part of the branches of the hyperbola whose equation is \(625 y^{2}-400 x^{2}=250,000,\) w
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In each exercise, graph the equation in a rectangular coordinate system. $$y^{2}=4(x+1)$$
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