Problem 63
Question
In a triangle \(A B C, \angle C=\frac{\pi}{2}\) If \(r\) is the inradius and \(R\) is the circumradius of the the triangle \(A B C\), then 2 ( \(r+\) \(R\) ) equals (A) \(b+c\) (B) \(a+b\) (C) \(a+b+c\) (D) \(c+a\)
Step-by-Step Solution
Verified Answer
The answer is (B) \(a+b\).
1Step 1: Recall Definitions
The inradius \( r \) of a triangle is the radius of the inscribed circle, and the circumradius \( R \) is the radius of the circle that passes through all three vertices of the triangle. In a right triangle, these have special relationships.
2Step 2: Use Formula for Inradius in Right Triangle
In a right triangle, the inradius \( r \) can be expressed as \( r = \frac{a+b-c}{2} \), where \( a \), \( b \), and \( c \) are the side lengths with \( c \) as the hypotenuse.
3Step 3: Use Formula for Circumradius in Right Triangle
In a right triangle, the circumradius \( R \) is given by \( R = \frac{c}{2} \), as the hypotenuse forms the diameter of the circumcircle.
4Step 4: Combine Terms in Expression
We seek \( 2(r+R) \). Substitute the expressions for \( r \) and \( R \):\[2 \left( \frac{a+b-c}{2} + \frac{c}{2} \right) = (a+b-c + c) = a+b\]
5Step 5: Compare with Options
The expression simplifies to \( a+b \), which matches option (B).
Key Concepts
Inradius of a TriangleCircumradius of a TriangleRight Triangle Properties
Inradius of a Triangle
The inradius of a triangle refers to the radius of the circle that fits snugly inside the triangle, touching all three sides. This circle is known as the incircle. All triangles have an inradius, but the calculation varies depending on the type of triangle.
For a right triangle, the formula to calculate the inradius \( r \) is:
This formula highlights a key attribute: in a right triangle, the inradius depends on how the legs and the hypotenuse interact. The inradius formula simplifies calculations for problems involving the triangle's area or perimeter and is especially valuable when examining inscribed circles.
For a right triangle, the formula to calculate the inradius \( r \) is:
- \( r = \frac{a+b-c}{2} \)
This formula highlights a key attribute: in a right triangle, the inradius depends on how the legs and the hypotenuse interact. The inradius formula simplifies calculations for problems involving the triangle's area or perimeter and is especially valuable when examining inscribed circles.
Circumradius of a Triangle
The circumradius of a triangle is the radius of the circumcircle, which is a circle that circumscribes the triangle. This means it passes through all three vertices of the triangle. Each triangle has a unique circumcircle, and the formula for the circumradius \( R \) depends on the triangle's properties.
In a right triangle, the circumradius is particularly simple:
In a right triangle, the circumradius is particularly simple:
- \( R = \frac{c}{2} \)
Right Triangle Properties
A right triangle is a triangle in which one angle measures exactly 90 degrees. This structure leads to unique and often simpler geometric properties when compared to other triangles. Understanding these properties is crucial when working with right triangles in triangle geometry.
Key properties include:
Key properties include:
- The Pythagorean theorem: \( a^2 + b^2 = c^2 \), where \( a \) and \( b \) are the legs, and \( c \) is the hypotenuse.
- The inradius formula: \( r = \frac{a+b-c}{2} \)
- The circumradius formula: \( R = \frac{c}{2} \)
Other exercises in this chapter
Problem 61
The sides of a triangle are \(\sin \alpha, \cos \alpha\) and \(\sqrt{1+\sin \alpha \cos \alpha}\) for some \(0
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In a triangle \(P Q R, \angle R=\frac{\pi}{2} .\) If \(\tan \left(\frac{P}{2}\right)\) and \(\tan \left(\frac{Q}{2}\right)\) are the roots of \(a x^{2}+b x+c=0,
View solution Problem 64
If the roots of the quadratic equation \(x^{2}+p x+q=0\) are \(\tan 30^{\circ}\) and \(\tan 15^{\circ}\), respectively then the value of \(2+\) \(q-p\) is (A) 2
View solution Problem 65
The number of values of \(x\) in the interval \([0,3 \pi]\) satisfying the equation \(2 \sin ^{2} x+5 \sin x-3=0\) is \(\quad\) (A) 4 (B) 6 (C) 1 (D) 2
View solution