Problem 63
Question
If equal amounts of the four inert gases \(\mathrm{Ar}, \mathrm{Ne}, \mathrm{Kr},\) and Xe are released at the same time at one end of a long, evacuated tube, which gas will reach the other end of the tube first? Explain your answer.
Step-by-Step Solution
Verified Answer
Neon (Ne) will reach the other end of the tube first due to its lowest molar mass, resulting in the highest molecular speed.
1Step 1: Understand Molecular Speed
The speed of a gas is determined by the root mean square (RMS) velocity, which depends inversely on the square root of the molecular mass. A lighter gas will have a higher molecular speed.
2Step 2: Determine the Molar Masses
Find the approximate molar masses of the gases: Argon (Ar) = 40 g/mol, Neon (Ne) = 20 g/mol, Krypton (Kr) = 84 g/mol, and Xenon (Xe) = 131 g/mol. Neon, being the lightest gas, has the smallest molar mass.
3Step 3: Apply Graham's Law
According to Graham's Law, the rate of effusion or diffusion of a gas is inversely proportional to the square root of its molar mass. Since Neon has the lowest molar mass, it will diffuse the fastest.
4Step 4: Conclusion Based on Calculations
Since Neon's speed is the greatest due to its lowest molar mass, Neon will reach the other end of the tube before the other gases.
Key Concepts
Root Mean Square VelocityGraham's LawMolar Mass
Root Mean Square Velocity
The root mean square velocity (RMS velocity) is a key concept in understanding how gas molecules move. It is a measure of the average speed of gas particles. The RMS velocity links the microscopic world of gas particles to macroscopic properties like temperature.
The formula for RMS velocity is given by:\[ v_{ rms } = \sqrt{\frac{3RT}{M}} \] Where:
The formula for RMS velocity is given by:\[ v_{ rms } = \sqrt{\frac{3RT}{M}} \] Where:
- \( v_{ rms } \) is the root mean square velocity.
- \( R \) is the ideal gas constant (8.314 J/mol·K).
- \( T \) is the temperature in Kelvin.
- \( M \) is the molar mass of the gas in kilograms per mole.
Graham's Law
Graham's Law of Effusion provides insights into why different gases move at different rates. According to Graham's Law, the rate of effusion or diffusion of a gas is inversely proportional to the square root of its molar mass. Mathematically, this is expressed as:\[ \frac{r_1}{r_2} = \sqrt{\frac{M_2}{M_1}} \]Where:
- \( r_1 \) and \( r_2 \) are the effusion rates of gas 1 and gas 2, respectively.
- \( M_1 \) and \( M_2 \) are the molar masses of gas 1 and gas 2, respectively.
Molar Mass
Molar mass is a fundamental concept in the study of gases, determining key properties like speed and rate of diffusion or effusion. It is defined as the mass of one mole of a substance, and its unit is typically grams per mole (g/mol).
In the context of molecular speed and gases, the molar mass has a significant impact. According to both the RMS velocity formula and Graham's Law, the molar mass directly influences a gas's speed and effusion behavior. In our example, the molar masses of inert gases are crucial:
In the context of molecular speed and gases, the molar mass has a significant impact. According to both the RMS velocity formula and Graham's Law, the molar mass directly influences a gas's speed and effusion behavior. In our example, the molar masses of inert gases are crucial:
- Argon (Ar): 40 g/mol
- Neon (Ne): 20 g/mol
- Krypton (Kr): 84 g/mol
- Xenon (Xe): 131 g/mol
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