Problem 63
Question
If eight persons are to address a meeting then the number of ways in which a specified speaker is to speak before another specified speaker, is (A) 40320 (B) 2520 (C) 20160 (D) None of these
Step-by-Step Solution
Verified Answer
The number of ways is 20160.
1Step 1: Understanding the Problem
We need to determine the number of ways to arrange eight speakers in such a way that a specified speaker (Speaker A) speaks before another specified speaker (Speaker B). This is a classic problem of permutations with a condition.
2Step 2: Calculate Total Permutations
First, we calculate the total number of ways to arrange all eight speakers without any restrictions. This is given by the factorial of 8, denoted as \(8!\). So, \(8! = 40320\).
3Step 3: Set Condition on Speakers
We need only those permutations where Speaker A speaks before Speaker B. When arranging two specific items (Speaker A and Speaker B), there are two possible orders: A before B or B before A. Given this specific condition, only half of the total arrangements will have A before B.
4Step 4: Calculate Valid Arrangements
Since there are two possibilities (A before B or B before A) and we want A before B, divide the total permutations by 2. Thus, the number of permutations where A speaks before B will be \( \frac{8!}{2} = \frac{40320}{2} = 20160\).
Key Concepts
FactorialConditional ArrangementsCombinatorics
Factorial
In mathematics, the factorial of a number is a fundamental concept often denoted by an exclamation mark, such as in "8!". This operation signifies the product of all positive integers up to that number. For example, the factorial of 8 (written as 8!) is calculated by multiplying all the integers from 1 to 8 together:
- 8! = 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1
- This results in 40320
Conditional Arrangements
Conditional arrangements refer to permutations that are organized under specific conditions or restrictions. In this exercise, one such condition is that one specified speaker must speak before another. This means we are concerned only with those arrangements of eight speakers that satisfy this specific order.
- First, determine the total number of arrangements without any conditions — this is calculated through the factorial of the total number of items (8! in this instance).
- Next, apply the condition: half of these arrangements will naturally have Speaker A before Speaker B, and the other half will have the reverse order (B before A).
Combinatorics
Combinatorics is a fascinating field of mathematics focusing on counting, arrangement, and combinations of objects. Problems in this domain often involve determining the number of ways to arrange or select items, which is exactly the task at hand in this exercise.
- Permutations are a central theme in combinatorics. They deal with the arrangement of objects where the order is important.
- Factorial calculations are a basis for determining permutations, providing a way to quantify total possible arrangements.
- Conditional arrangements narrow these permutations by applying specific sequence rules, as seen when determining how many speaker setups place one before another.
Other exercises in this chapter
Problem 60
In an examination a candidate has to pass in each of the papers to be successful. If the total number of ways to fail is 63 , how many papers are there in the e
View solution Problem 61
If \(A\) denotes the property that two elements of \(A=\\{1\), \(5,9,13 \ldots, 1093\\}\) add up to 1094 , then the maximum number of elements in \(A\) can be (
View solution Problem 64
The number of permutations of letters \(a, b, c, d, e, f, g\) so that neither the pattern beg nor cad appears is (A) \(\frac{7 !}{3 ! 3 !}\) (B) \(\frac{7 !}{2
View solution Problem 65
The sum of all the numbers that can be formed with the digits \(2,3,4,5\) taken all at a time is (A) 66666 (B) 84844 (C) 93324 (D) None of these
View solution