Problem 63
Question
For the functions in Exercises \(59-66,\) use your graphing calculator to find a comprehensive graph and answer each of the following. (a) Determine the domain. (b) Determine all local minimum points, and tell if any is an absolute minimum point. (Approximate coordinates to the nearest hundredth.) (c) Determine all local maximum points, and tell if any is an absolute maximum point. (Approximate coordinates to the nearest hundredth.) (d) Determine the range. (If an approximation is necessary, give it to the nearest hundredth.) (e) Determine all intercepts. For each function, there is at least one \(x\) -intercept that has an integer \(x\) -value. For those that are not integers, give approximations to the nearest hundredth. Determine the \(y\) -intercept analytically. (f) Give the open interval(s) over which the function is increasing. (g) Give the open interval(s) over which the function is decreasing. $$P(x)=2 x^{4}+3 x^{3}-17 x^{2}-6 x-72$$
Step-by-Step Solution
VerifiedKey Concepts
Domain and Range
Now, let's talk about the range, which represents all possible outputs or \(y\) values. For polynomials with an even degree and a positive leading coefficient, such as our function, the range typically approaches positive infinity. The lowest part of the graph isn't technically limited either, giving you a range from \([-\infty, \text{max y-value}]\). Using a graphing calculator, you can approximate this maximum \(y\)-value which likely occurs at the local maximum or on the tails of the graph.
Local Minimum and Maximum
- Find critical points: Solve \(P'(x) = 0\).
- Identify the nature: Use graph or second derivative test to judge if points are minima or maxima.
Intercepts
- X-intercepts: These occur where \(P(x) = 0\). Use a graphing tool or calculator to solve \(2x^4 + 3x^3 - 17x^2 - 6x - 72 = 0\). Often, these intercepts will not be integers, but there should be at least one that is, given as exactly or approximately.
- Y-intercept: Easy to find by setting \(x=0\) in the function: \(P(0) = -72\). Hence, the y-intercept is at the point \((0, -72)\).
Increasing and Decreasing Intervals
- Increasing Intervals: Examine where \(P'(x) > 0\). This happens when the derivative is positive, meaning the slope of the tangent to the curve is upward.
- Decreasing Intervals: Occur where \(P'(x) < 0\). Here, the slope of the tangent is downward, and the graph is descending.