Problem 63
Question
Find the value of the discriminant for each quadratic equation. Then describe the number and type of roots for the equation. $$ 2 x^{2}-5 x+6=0 $$
Step-by-Step Solution
Verified Answer
Discriminant is -23, leading to two complex roots.
1Step 1: Identify a, b, and c
In the quadratic equation \( ax^2 + bx + c = 0 \), we identify the coefficients: \( a = 2 \), \( b = -5 \), and \( c = 6 \).
2Step 2: Use the Discriminant Formula
The discriminant \( D \) of a quadratic equation is given by the formula \( D = b^2 - 4ac \). We will use this formula to calculate the discriminant.
3Step 3: Calculate \( b^2 \)
Calculate the square of \( b \): \((-5)^2 = 25\).
4Step 4: Calculate \( 4ac \)
Calculate \( 4 \) times \( a \) times \( c \): \( 4 \times 2 \times 6 = 48 \).
5Step 5: Evaluate the Discriminant
Substitute the calculated values into the discriminant formula: \( D = 25 - 48 = -23 \).
6Step 6: Determine the Nature of the Roots
Since the discriminant \( D = -23 \), which is less than zero, the quadratic equation has two complex roots.
Key Concepts
Nature of RootsComplex RootsQuadratic Equation Coefficients
Nature of Roots
Every quadratic equation may have different types of roots, depending on its discriminant, which is found using the formula \( D = b^2 - 4ac \). You can scatter out simplified pieces of information to understand this concept better:
This means by simply glancing at the value of \( D \), you can deduce if you will encounter real numbers or complex numbers as roots.
Learning to quickly assess the nature of roots helps sharpen problem-solving skills, especially when handling numerous quadratic equations.
- If \( D > 0 \), the equation has two distinct real roots.
- If \( D = 0 \), it has exactly one real root, also known as a repeated or double root.
- If \( D < 0 \), the roots are not real - they are complex.
This means by simply glancing at the value of \( D \), you can deduce if you will encounter real numbers or complex numbers as roots.
Learning to quickly assess the nature of roots helps sharpen problem-solving skills, especially when handling numerous quadratic equations.
Complex Roots
Complex roots appear when the discriminant \( D \,<\, 0 \). These roots aren't plain numbers like 2, -5, or \( \frac{1}{3} \).
They come in pairs, and you can imagine them consisting of both real and imaginary parts.
Understanding complex roots gives a deeper insight into the diverse real-world applications, such as physics where complex numbers are used to describe phenomena like wave mechanics.
They come in pairs, and you can imagine them consisting of both real and imaginary parts.
- A complex number looks like this: \( a + bi \), where \( a \) and \( b \) are real numbers, and \( i \) is the imaginary unit.
- The imaginary unit \( i \) is defined by \( i^2 = -1 \).
Understanding complex roots gives a deeper insight into the diverse real-world applications, such as physics where complex numbers are used to describe phenomena like wave mechanics.
Quadratic Equation Coefficients
Quadratic equations take this familiar form \( ax^2 + bx + c = 0 \), where \( a, \) \( b, \) and \( c \) stand as the coefficients. Let's break down their roles:
This makes it crucial to know the correct values of \( a, b, \) and \( c \) for successful root analysis.
Lifting the fog on these coefficients equips you to better manipulate equations and predict their behaviors visually without sketching a graph every time!
- \( a \) decides the opening direction and width of the parabola.
- \( b \) influences the location of the vertex along the x-axis.
- \( c \) is simply there to set the y-intercept when \( x = 0 \).
This makes it crucial to know the correct values of \( a, b, \) and \( c \) for successful root analysis.
Lifting the fog on these coefficients equips you to better manipulate equations and predict their behaviors visually without sketching a graph every time!
Other exercises in this chapter
Problem 63
Solve each system of inequalities. \(x \geq 1\) \(y \leq-1\) \(y \leq x\)
View solution Problem 63
Find each product, if possible. $$ \left[\begin{array}{ccc}{2} & {-6} & {3}\end{array}\right] \cdot\left[\begin{array}{rr}{3} & {-3} \\ {9} & {0} \\ {-2} & {4}\
View solution Problem 63
Simplify. $$ (2+i)(1+2 i)(3-4 i) $$
View solution Problem 63
Factor completely. $$ x^{2}-18 x+81 $$
View solution