Problem 63
Question
Find each of the products and express the answers in the standard form of a complex number. $$ (7 i)(-6 i) $$
Step-by-Step Solution
Verified Answer
42
1Step 1: Understand the Problem
We need to multiply two imaginary numbers, \(7i\) and \(-6i\), and express the result as a complex number in standard form, which is \(a + bi\), where \(a\) and \(b\) are real numbers.
2Step 2: Multiply the Coefficients
First multiply the numerical coefficients of the imaginary numbers: \( 7 \times (-6) = -42 \).
3Step 3: Multiply the Imaginary Units
When you multiply \(i \times i\), it results in \(i^2\). We have: \(i^2 = -1\). Therefore, the multiplication becomes \(-42 \times i^2 = -42 \times (-1)\).
4Step 4: Simplify the Expression
Simplify the product \(-42 \times (-1)\) to get 42. Thus, the result is a real number 42.
5Step 5: Express in Standard Form
Since the result is purely real, we can write it as \(42 + 0i\). This is already in the standard form of a complex number \(a + bi\).
Key Concepts
Imaginary NumbersStandard FormMultiplication of Complex Numbers
Imaginary Numbers
Imagine a number with a twist. That's what an imaginary number is! In mathematics, imaginary numbers stem from the need to find a solution to negative square roots. To break it down, the foundation of imaginary numbers is the imaginary unit, denoted as \(i\). The imaginary unit \(i\) is defined as the square root of -1, or mathematically expressed as:
When we talk about imaginary numbers, they are generally expressed as \(bi\) where \(b\) is a real number. For example, in the exercise \(7i\) and \(-6i\) are imaginary numbers because the value in front of \(i\) (which is a real number) gives its magnitude.
Imaginary numbers are essential not only in theoretical mathematics but also in practical fields like engineering and physics, where they help to solve real-world problems by providing a fuller set of numbers for calculation.
- \(i = \sqrt{-1}\)
When we talk about imaginary numbers, they are generally expressed as \(bi\) where \(b\) is a real number. For example, in the exercise \(7i\) and \(-6i\) are imaginary numbers because the value in front of \(i\) (which is a real number) gives its magnitude.
Imaginary numbers are essential not only in theoretical mathematics but also in practical fields like engineering and physics, where they help to solve real-world problems by providing a fuller set of numbers for calculation.
Standard Form
Expressing complex numbers in a clear format helps maintain consistency and understanding. The standard form of a complex number is typically written as \(a + bi\). This form is easy to read and clearly indicates the real part \(a\) and the imaginary part \(bi\). For instance:
- \(a\) represents the real portion of the number.
- \(bi\) signifies the imaginary part, where \(b\) is a real number and represents the coefficient of the imaginary unit \(i\).
Multiplication of Complex Numbers
Multiplying complex numbers might seem daunting at first, but it's quite methodical. The process involves multiplying both the real and imaginary parts just like you would perform multiplication of binomials.
This result is a real number. Lastly, express the result in standard form \(42 + 0i\). Multiplication of complex numbers is a fundamental skill in mathematics, opening doors to understanding further operations and branches within the subject. It becomes easier with practice and aids in numerous applications across various fields.
- Start by multiplying the coefficients of the imaginary parts.
- Then multiply the imaginary units.
- Multiply the coefficients: \(7 \times -6 = -42\)
- \(i \times i = i^2\) and we know \(i^2 = -1\)
This result is a real number. Lastly, express the result in standard form \(42 + 0i\). Multiplication of complex numbers is a fundamental skill in mathematics, opening doors to understanding further operations and branches within the subject. It becomes easier with practice and aids in numerous applications across various fields.
Other exercises in this chapter
Problem 63
Give a step-by-step description of how to solve \(3 x^{2}+9 x-4=0\) by completing the square.
View solution Problem 63
For Problems \(63-68, a\) and \(b\) represent the lengths of the legs of a right triangle, and \(c\) represents the length of the hypotenuse. Express answers in
View solution Problem 64
Set up an equation and solve each problem. The formula \(D=\frac{n(n-3)}{2}\) yields the number of diagonals, \(D\), in a polygon of \(n\) sides. Find the numbe
View solution Problem 64
The solution set for \(x^{2}-4 x-37=0\) is \(\\{2 \pm \sqrt{41}\\}\). With a calculator, we found a rational approximation, to the nearest one-thousandth, for e
View solution