Problem 63
Question
Factor the expression completely. $$ 8 x^{3}-125 $$
Step-by-Step Solution
Verified Answer
The expression \( 8x^3 - 125 \) factors to \((2x - 5)(4x^2 + 10x + 25)\).
1Step 1: Identify the Expression as a Difference of Cubes
The given expression is \( 8x^3 - 125 \). Notice that this can be written as a difference of cubes, because \( 8x^3 = (2x)^3 \) and \( 125 = 5^3 \). Let's express the expression in the form \( (a^3 - b^3) \), where \( a = 2x \) and \( b = 5 \).
2Step 2: Recall the Difference of Cubes Formula
The formula for factoring the difference of cubes is \( a^3 - b^3 = (a-b)(a^2 + ab + b^2) \). In our case, \( a = 2x \) and \( b = 5 \).
3Step 3: Apply the Difference of Cubes Formula
Substitute \( a = 2x \) and \( b = 5 \) into the formula: \( a^3 - b^3 = (a-b)(a^2 + ab + b^2) \) becomes \( (2x - 5)((2x)^2 + (2x)(5) + 5^2) \).
4Step 4: Simplify the Factored Expression
Calculate each term in the factored expression: \((2x - 5)\) and \((2x)^2 = 4x^2\), \((2x)(5) = 10x\), \(5^2 = 25\). Thus, \((2x - 5)(4x^2 + 10x + 25)\).
5Step 5: Verify Solution
Multiply both factors to verify correctness: Expand \((2x - 5)(4x^2 + 10x + 25)\) to ensure it equals the original expression \(8x^3 - 125\). This confirms the factorization is correct.
Key Concepts
Factoring PolynomialsAlgebraCubed Numbers
Factoring Polynomials
Factoring polynomials means breaking down a complex expression into simpler parts or products. Think of it like unwrapping a present to see what's inside! When a polynomial is 'factored completely,' it means no further factorization is possible, and you've found all the smallest pieces.
Here's a basic approach to factoring:
Here's a basic approach to factoring:
- Identify if the polynomial is a simple form or complex.
- Check for common patterns, such as differences of squares or cubes.
- Look for any common factors first.
- Apply known formulas like the difference of cubes.
Algebra
Algebra is a branch of mathematics that uses symbols and letters to solve equations with various quantities. It's like solving puzzles where letters stand in for numbers until we find their true value.
Key concepts in algebra include:
Key concepts in algebra include:
- Variables: Symbols like \(x\) or \(y\) that represent unknowns or quantities that can change.
- Expressions: Combinations of numbers, variables, and operators like \(+\), \(-\), or \(\times\).
- Equations: Statements that two expressions are equal, often involving variables.
- Formulas: A special equation that shows the relationship between different variables.
Cubed Numbers
Cubed numbers are numbers raised to the power of three, denoted as \(n^3\). Imagine a cube in geometry with all side lengths being \(n\); its volume would be \(n^3\). It's essentially multiplying a number by itself twice more.
For example:
For example:
- \(2^3 = 2 \times 2 \times 2 = 8\)
- \(3^3 = 3 \times 3 \times 3 = 27\)
- \(4^3 = 4 \times 4 \times 4 = 64\)
Other exercises in this chapter
Problem 63
Perform the addition or subtraction and simplify. $$ \frac{1}{x^{2}+3 x+2}-\frac{1}{x^{2}-2 x-3} $$
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\(47-72\) . Simplify the expression, and eliminate any negative exponent(s). $$ \frac{8 a^{3} b^{-4}}{2 a^{-5} b^{5}} $$
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\(49-68=\) Simplify the expression and eliminate any negative exponent(s). Assume that all letters denote positive numbers. $$ \left(\frac{x^{8} y^{-4}}{16 y^{4
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Multiply the algebraic expressions using a Special Product Formula, and simplify. \((x+3 y)(x-3 y)\)
View solution