Problem 63
Question
Evaluate the expression by band. Approximate the answer to the nearest hundredth when appropriate. $$ 2^{1 / 2} \cdot 2^{2 / 3} $$
Step-by-Step Solution
Verified Answer
The expression evaluates to approximately 2.30.
1Step 1: Understand the expression
The expression we have is a multiplication of two exponential terms, \(2^{1/2}\) and \(2^{2/3}\). We need to multiply these two exponential terms together.
2Step 2: Apply properties of exponents
To multiply terms with the same base, use the property of exponents: \(a^m \cdot a^n = a^{m+n}\). In this case, both terms have the base 2. So, we apply the property: \(2^{1/2} \cdot 2^{2/3} = 2^{1/2 + 2/3}\).
3Step 3: Find a common denominator for the fractions
Add the exponents \(1/2\) and \(2/3\) by first finding a common denominator, which is 6. Rewriting the fractions: \(1/2 = 3/6\) and \(2/3 = 4/6\).
4Step 4: Add the exponents
Add \(3/6\) and \(4/6\) to get \(7/6\). Thus, the expression becomes \(2^{7/6}\).
5Step 5: Approximate the result
Convert \(2^{7/6}\) to a decimal using a calculator. This gives approximately 2.297. Rounded to the nearest hundredth, the result is 2.30.
Key Concepts
Properties of ExponentsMultiplication of Exponential TermsFraction AdditionApproximating Results
Properties of Exponents
Exponents are a way to express repeated multiplication. There are several properties of exponents that can help simplify complex expressions:
- When you multiply terms with the same base, you add the exponents. This is known as the product of powers property: \( a^m \cdot a^n = a^{m+n} \).
- When you divide terms with the same base, you subtract the exponents: \( a^m / a^n = a^{m-n} \).
- Any number raised to the power of zero is 1: \( a^0 = 1 \).
- Raising a power to another power involves multiplying the exponents: \((a^m)^n = a^{m \cdot n} \).
Multiplication of Exponential Terms
Multiplying exponential terms becomes straightforward when all the bases are the same. For the expression \(2^{1/2} \cdot 2^{2/3}\), the base "2" remains unchanged.
Apply the property of exponents, which states that you add the exponents when multiplying like bases. This transforms the problem to \(2^{1/2 + 2/3}\).
It's crucial to note that this property only applies when the terms share the same base. Other operations require different rules.
Apply the property of exponents, which states that you add the exponents when multiplying like bases. This transforms the problem to \(2^{1/2 + 2/3}\).
It's crucial to note that this property only applies when the terms share the same base. Other operations require different rules.
Fraction Addition
Adding fractions involves finding a common denominator. This allows you to combine the numerators easily.
- First, identify the least common multiple (LCM) of the denominators. For \(1/2 + 2/3\), the LCM of 2 and 3 is 6.
- Rewrite each fraction so that both have the common denominator. Convert \(1/2\) to \(3/6\) and \(2/3\) to \(4/6\).
- Add the new numerators: \(3/6 + 4/6 = 7/6\).
Approximating Results
Once you've manipulated the expression, sometimes you'll end up with an irrational number or a difficult exponential form. Approximating such results can provide a more practical answer.
Using a calculator, raise a base to a fractional exponent, like \(2^{7/6}\). This gives a decimal approximation.
In this case, \(2^{7/6} \approx 2.297\). By rounding to the nearest hundredth, the result becomes 2.30. Rounding numbers makes them easier to use in real-world applications and helps present answers clearly.
Using a calculator, raise a base to a fractional exponent, like \(2^{7/6}\). This gives a decimal approximation.
In this case, \(2^{7/6} \approx 2.297\). By rounding to the nearest hundredth, the result becomes 2.30. Rounding numbers makes them easier to use in real-world applications and helps present answers clearly.
Other exercises in this chapter
Problem 63
Simplify the expression. Assume that all variables are positive. $$ 2 \sqrt{3}+7 \sqrt{3} $$
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Factor the expression completely, if possible. \(36 x^{2}-100\)
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Multiply the binomials. $$\left(x^{2}-2\right)\left(x^{2}+4\right)$$
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Exercises \(55-64:\) Use the power rules to simplify the expression. Use positive exponents to write your answer. $$ \left(\frac{2 x y}{3 z^{5}}\right)^{-1} $$
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