Problem 63
Question
Enthalpy change in the following process is \(\mathrm{M}+\mathrm{e}^{-} \longrightarrow \mathrm{M}^{-}, \Delta \mathrm{H}=\mathrm{X} \mathrm{kJ} \mathrm{mole}^{-1}\) Which of the following process have enthalpy change \(=\mathrm{X} \mathrm{kJ} \mathrm{mole}^{-1} ?\) (a) \(\mathrm{M}^{-} \longrightarrow \mathrm{M}+\mathrm{e}^{-}\) (b) \(\mathrm{M}^{+}+\mathrm{e}^{-} \longrightarrow \mathrm{M}\) (c) \(\mathrm{M}^{2+}+\mathrm{e}^{2} \longrightarrow \mathrm{M}^{+}\) (d) \(\mathrm{M}+\mathrm{e}^{-} \longrightarrow \mathrm{M}^{-}\)
Step-by-Step Solution
Verified Answer
The correct process is (d): \( \mathrm{M} + \mathrm{e}^{-} \longrightarrow \mathrm{M}^{-} \).
1Step 1: Identify the given reaction
The enthalpy change given in the problem is for the reaction: \( \mathrm{M} + \mathrm{e}^{-} \longrightarrow \mathrm{M}^{-} \) with \( \Delta \mathrm{H} = \mathrm{X} \mathrm{kJ} \text{ mole}^{-1} \). Here, a neutral atom \( \mathrm{M} \) gains an electron to become an anion \( \mathrm{M}^{-} \).
2Step 2: Analyze each option's reaction
Let's analyze each option:(a) \( \mathrm{M}^{-} \longrightarrow \mathrm{M} + \mathrm{e}^{-} \): This is the reverse reaction of the given process, where an anion loses an electron to form a neutral atom. The enthalpy change for this reaction would be \( -X \mathrm{kJ} \text{ mole}^{-1} \) (opposite in sign because it's the reverse).
3Step 3: Determine pairs for Option (b)
(b) \( \mathrm{M}^{+} + \mathrm{e}^{-} \longrightarrow \mathrm{M} \): In this process, a cation gains an electron to form a neutral atom. Typically, this process does not have the same enthalpy change as forming an anion from a neutral atom as described in the given reaction.
4Step 4: Examine Option (c)
(c) \( \mathrm{M}^{2+} + \mathrm{e}^{2-} \longrightarrow \mathrm{M}^{+} \): This would involve a doubly charged cation gaining one electron to become a singly charged cation. The stoichiometry does not match, nor does the nature of enthalpy change align with the given reaction \( \Delta \mathrm{H} = X \mathrm{kJ} \text{ mole}^{-1} \).
5Step 5: Confirmation of given process (Option (d))
(d) \( \mathrm{M} + \mathrm{e}^{-} \longrightarrow \mathrm{M}^{-} \): This is the same as the original reaction given in the problem. Hence, the enthalpy change for this process is clearly \( X \mathrm{kJ} \text{ mole}^{-1} \), matching the description provided.
Key Concepts
ThermochemistryIonization EnergyChemical ReactionsElectron Affinity
Thermochemistry
Thermochemistry focuses on the heat changes that occur during chemical reactions. It deals with the relationship between chemical reactions and energy changes involving heat. The enthalpy change is a crucial concept in thermochemistry. It's the amount of heat absorbed or released in a reaction at constant pressure.
Understanding how different reactions absorb or release energy helps us manipulate reactions for desired results. For example, knowing the enthalpy change helps predict reaction feasibility under given conditions.
Key to understanding enthalpy changes is realizing that they can be positive or negative:
- A positive enthalpy change (9H > 0) indicates an endothermic process, where heat is absorbed.
- A negative enthalpy change (9H < 0) indicates an exothermic process, where heat is released.
Ionization Energy
Ionization energy is the energy required to remove an electron from a gaseous atom or ion. It's a fundamental property that measures the tendency of an atom to resist losing an electron.
For instance, turning a neutral atom into a cation involves overcoming the attraction between the negatively charged electron and the positively charged nucleus:
- First ionization energy refers to the removal of the first electron.
- Successive ionization energies refer to removing additional electrons, each requiring more energy.
Chemical Reactions
Chemical reactions are processes that lead to the transformation of one set of chemical substances to another. They involve breaking and forming bonds between atoms, leading to changes in the composition and energy of substances involved.
In reactions:
- Reactants are the starting substances.
- Products are the substances formed as a result.
Electron Affinity
Electron affinity measures an atom's tendency to gain an electron, forming a negative ion. It's the energy change when an electron is added to a gaseous atom.
Electron affinities vary across the periodic table and provide insights into the chemical properties of elements. A higher electron affinity indicates a greater tendency to accept an electron:
- Most nonmetals have high electron affinities, making them more likely to form anions.
- Typically, electron affinity becomes more negative across a period and less negative down a group.
Other exercises in this chapter
Problem 61
The electron affinities of \(\mathrm{N}, \mathrm{O}, \mathrm{S}\) and \(\mathrm{Cl}\) are (a) \(\mathrm{O} \approx \mathrm{Cl}
View solution Problem 62
While moving down a group in the periodic table, which of the following would be true? (1) all the atoms have the same number of valence electrons (2) gram atom
View solution Problem 64
The formation of \(\mathrm{O}^{2-}(\mathrm{g})\) starting from \(\mathrm{O}(\mathrm{g})\) is endothermic by \(603 \mathrm{~kJ} \mathrm{~mol}^{-1}\). If electron
View solution Problem 66
The correct order of first ionization potential is (a) \(\mathrm{F}>\mathrm{He}>\mathrm{Mg}>\mathrm{N}>\mathrm{O}\) (b) \(\mathrm{He}>\mathrm{F}>\mathrm{N}>\mat
View solution