Problem 63
Question
Determine whether the following statement is sometimes, always, or never true. Explain your reasoning. For all positive numbers \(x\) and \(y, \frac{\log x}{\log y}=\frac{\ln x}{\ln y}\)
Step-by-Step Solution
Verified Answer
The statement is always true.
1Step 1: Understand the Problem
We need to determine whether the given expression \(\frac{\log x}{\log y} = \frac{\ln x}{\ln y}\) is sometimes, always, or never true for all positive numbers \(x\) and \(y\). The expression involves two different logarithmic bases: base 10 (\(\log\)) and base \(e\) (\(\ln\)).
2Step 2: Review Logarithmic Properties
Recall that for a logarithm of any base \(b\), the change of base formula can be defined as: \[ \log_b a = \frac{\log_k a}{\log_k b} \]where \(k\) can be any positive base different from 1. Using this, both \(\log\) and \(\ln\) can be expressed in terms of each other or a common base.
3Step 3: Apply Change of Base Formula
Apply the change of base formula for \(\log x\) and \(\log y\) using the natural logarithm (\(\ln\)) as their base:\[ \log x = \frac{\ln x}{\ln 10} \] \[ \log y = \frac{\ln y}{\ln 10} \]Thus, the expression \(\frac{\log x}{\log y}\) becomes:\[ \frac{\ln x / \ln 10}{\ln y / \ln 10} = \frac{\ln x}{\ln y} \]The \(\ln 10\) terms cancel out.
4Step 4: Conclusion
Since after simplification, \(\frac{\log x}{\log y}\) simplifies to \(\frac{\ln x}{\ln y}\), the expression \(\frac{\log x}{\log y} = \frac{\ln x}{\ln y}\) holds for all positive numbers \(x\) and \(y\). Hence, it is **always true.**
Key Concepts
Change of Base FormulaNatural LogarithmLogarithmic Properties
Change of Base Formula
The change of base formula is a crucial tool in logarithmic calculations. This formula allows you to convert a logarithm from one base to another. This can be especially helpful when dealing with different bases, like base 10, represented as \(\log\), and base \(e\), represented as \(\ln\).
The formula is expressed as:
\[\log_b a = \frac{\log_k a}{\log_k b} \]
where \(b\) is the original base, and \(k\) is the new base we are converting to. This change is possible because logarithms can be expressed in terms of **any** base, as long as that base is positive and not equal to one.
Applying the change of base formula allows us to convert between logarithms with different bases, making computations easier and more flexible. In our exercise, we used the natural logarithm as the base to demonstrate that the expression \(\frac{\log x}{\log y} = \frac{\ln x}{\ln y}\) is always true, regardless of the values of \(x\) and \(y\) as long as they are positive.
The formula is expressed as:
\[\log_b a = \frac{\log_k a}{\log_k b} \]
where \(b\) is the original base, and \(k\) is the new base we are converting to. This change is possible because logarithms can be expressed in terms of **any** base, as long as that base is positive and not equal to one.
Applying the change of base formula allows us to convert between logarithms with different bases, making computations easier and more flexible. In our exercise, we used the natural logarithm as the base to demonstrate that the expression \(\frac{\log x}{\log y} = \frac{\ln x}{\ln y}\) is always true, regardless of the values of \(x\) and \(y\) as long as they are positive.
Natural Logarithm
The natural logarithm, denoted \(\ln\), is a specific logarithm with the base of \(e\), an irrational number approximately equal to 2.718. The natural logarithm is widely used in mathematics due to its unique properties and simplicity in differentiation and integration.
For any positive number \(x\), \(\ln x\) is defined as the power to which \(e\) must be raised to obtain \(x\). It is commonly used in calculus, particularly in dealing with exponential growth and decay problems, because of its natural properties that simplify mathematical analysis.
For any positive number \(x\), \(\ln x\) is defined as the power to which \(e\) must be raised to obtain \(x\). It is commonly used in calculus, particularly in dealing with exponential growth and decay problems, because of its natural properties that simplify mathematical analysis.
- The derivative of \(\ln x\) with respect to \(x\) is \(\frac{1}{x}\).
- The natural logarithm of 1 is 0. That is, \(\ln 1 = 0\).
- \(\ln e = 1\) since \(e^1 = e\).
Logarithmic Properties
Logarithms have a set of properties that make them incredibly useful for solving complex problems. These properties allow for simplification and transformation of expressions, which is handy in both theoretical and applied mathematics.
The main logarithmic properties include:
In our exercise, we effectively used the change of base formula, combining it with the property that allows division inside a logarithm to be expressed as a difference. It showed \(\frac{\log x}{\log y}\) and \(\frac{\ln x}{\ln y}\) reduce to the same expression, proving it is always true. Understanding these properties ensures a strong foundational grasp on handling problems involving logarithms.
The main logarithmic properties include:
- **Product Property**: \(\log_b(xy) = \log_b x + \log_b y\)
- **Quotient Property**: \(\log_b\left(\frac{x}{y}\right) = \log_b x - \log_b y\)
- **Power Property**: \(\log_b(x^k) = k\log_b x\)
- **Change of Base Formula**: \(\log_b a = \frac{\log_k a}{\log_k b}\)
In our exercise, we effectively used the change of base formula, combining it with the property that allows division inside a logarithm to be expressed as a difference. It showed \(\frac{\log x}{\log y}\) and \(\frac{\ln x}{\ln y}\) reduce to the same expression, proving it is always true. Understanding these properties ensures a strong foundational grasp on handling problems involving logarithms.
Other exercises in this chapter
Problem 62
Show that each statement is true. \(\log _{7}\left[\log _{3}\left(\log _{2} 8\right)\right]=0\)
View solution Problem 62
REASONING Identify each function as linear, quadratic, or exponential. $$\begin{array}{llll}{\text { a. } y=3 x^{2}} & {\text { b. } y=4(3)^{x}} & {\text { c. }
View solution Problem 63
PREREQUISITE SKILL Solve each equation or inequality. Check your solutions. $$ \log _{10} 2^{x}=\log _{10} 32 $$
View solution Problem 63
Use \(\log _{7} 2 \approx 0.3562\) and \(\log _{7} 3 \approx 0.5646\) to approximate the value of each expression. $$ \log _{7} 16 $$
View solution