Problem 63
Question
Determine whether each statement makes sense or does not make sense, and explain your reasoning. I noticed that for a right triangle, the Law of Cosines reduces to the Pythagorean Theorem.
Step-by-Step Solution
Verified Answer
Yes, the statement makes sense. For a right triangle, the Law of Cosines does reduce to the Pythagorean Theorem.
1Step 1 Verify the Statement
Write down the Law of Cosines formula and Pythagorean Theorem. Law of Cosines is \(c^2 = a^2 + b^2 - 2ab \cos(C)\) and Pythagorean Theorem is \(c^2 = a^2 + b^2\).
2Step 2 Adjust the law of Cosines
Since we are dealing with a right triangle for this case, angle C would be 90 degrees. Plug 90 degrees into cos(C) in the Law of Cosines. The cosine of 90 degrees equals 0.
3Step 3 Observe
Once 0 is plugged in, the Law of Cosines \(c^2 = a^2 + b^2 - 2ab \cos(C)\) becomes \(c^2 = a^2 + b^2 - 2ab(0)\). Since anything multiplied by 0 is 0, the equation simplifies to \(c^2 = a^2 + b^2\).
4Step 4 Compare
Notice the Law of Cosines has reduced to the Pythagorean Theorem, as the statement suggested.
Other exercises in this chapter
Problem 63
Use a graphing utility to graph the polar equation. $$r=2+2 \sin \theta$$
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In Exercises \(53-64,\) use DeMoivre's Theorem to find the indicated power of the complex number. Write answers in rectangular form. $$ (\sqrt{3}-i)^{6} $$
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Convert each polar equation to a rectangular equation. Then use a rectangular coordinate system to graph the rectangular equation. $$ r \sin \theta=3 $$
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Explaining the Concepts. Briefly describe how the Law of Sines is proved.
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