Problem 63
Question
Describe how the graph of \(f\) varies as \(c\) varies. Graph several members of the family to illustrate the trends that you discover. In particular, you should investigate how maximum and minimum points and inflection points move when \(c\) changes. You should also identify any transitional values of \(c\) at which the basic shape of the curve changes. $$f(x)=e^{-c / x^{2}}$$
Step-by-Step Solution
Verified Answer
As \( c \) increases, the curve flatten and approach zero faster. Inflection points and critical points depend on \( c \).
1Step 1: Understand the Function
The given function is \( f(x) = e^{-c / x^2} \). This is an exponential function where the exponent is a negative rational function of \( x \). As \( c \) varies, we need to evaluate how the shape and characteristics of this function change, particularly at maximum, minimum, and inflection points.
2Step 2: Analyze Influence of Parameter \( c \)
The parameter \( c \) affects the steepness and spread of the function. When \( c \) is larger, the exponent \(-c/x^2\) becomes more negative if \( x eq 0 \), making \( f(x) \) closer to zero. As \( c \) approaches zero, the exponent approaches zero, making \( f(x) \) approach 1 for \( x eq 0 \).
3Step 3: Maximum and Minimum Points
For \( f(x) \), there are no maximum or minimum points in the traditional sense as the function is not bounded; however, you may observe points where the function changes its increasing or decreasing behavior depending on \( c \). Such analyses generally involve looking at the derivative \( f'(x) \).
4Step 4: Inflection Points
An inflection point occurs where the second derivative \( f''(x) \) changes sign. To find these points, compute \( f''(x) \) and study how it changes as \( c \) varies. Analyzing these derivatives helps determine how the concavity changes and locate any inflection points.
5Step 5: Transitional Values of \( c \)
These are the values of \( c \) that cause the shape of \( f(x) \) to change significantly, often when new inflection points appear or disappear, or when \( f'(x) \) changes its sign pattern. Study \( f'(x) \) and \( f''(x) \) to identify these transitional behaviors as \( c \) changes.
Key Concepts
Exponential FunctionInflection PointsDerivativesGraph Analysis
Exponential Function
The function we are working with, \( f(x) = e^{-c / x^2} \), is an example of an exponential function. In these types of functions, the variable \( x \) is in the exponent. Here, however, our exponent is uniquely expressed as a negative rational function involving \( c \) and \( x^2 \). This structure gives the function some interesting properties that are influenced significantly by the parameter \( c \).
- When \( c \) is larger, the expression \(-c/x^2\) means \( f(x) \) tends to zero as the exponent becomes very negative.
- As \( c \) approaches zero, the exponent nears zero, making \( f(x) \) approach 1, except when \( x = 0 \).
Inflection Points
An inflection point is where a curve changes its concavity - from concave up to concave down, or vice versa. In simpler terms, it's where the graph goes from being shaped like a "cup" to a "cap," or from a "cap" to a "cup."
For our function \( f(x) = e^{-c/x^2} \), finding inflection points involves computing the second derivative, \( f''(x) \). Wherever \( f''(x) \) transitions from positive to negative (or negative to positive) defines our inflection points.
For our function \( f(x) = e^{-c/x^2} \), finding inflection points involves computing the second derivative, \( f''(x) \). Wherever \( f''(x) \) transitions from positive to negative (or negative to positive) defines our inflection points.
- These points help in understanding how \( f(x) \) "bends" as \( c \) varies.
- Inflection points may appear or vanish as the parameter \( c \) changes, indicating a notable transformation in the curve's shape.
Derivatives
In calculus, derivatives help us analyze functions by revealing information about their rates of change. For our function, \( f(x) = e^{-c/x^2} \), both the first and second derivatives are key in understanding its behavior.
- The first derivative, \( f'(x) \), tells us where the function is increasing or decreasing. It can reveal the locations of peaks and troughs, though in this unbounded function, typical max/min points don't exist.
- The second derivative, \( f''(x) \), provides insight into the inflection points and the concavity of \( f(x) \).
Graph Analysis
Graph analysis involves understanding how a function behaves visually as parameters change. For \( f(x) = e^{-c/x^2} \), graph analysis helps us see the impact of changing \( c \) on its shape.
This analysis helps in forecasting the behavior of functions and understanding how sensitive they are to adjustments in parameters, like \( c \) in our example.
- Higher values of \( c \) generally make the graph's rise and fall more "steep" and localized around \( x = 0 \).
- As \( c \) decreases, the graph flattens, approaching the line \( y = 1 \), especially away from \( x = 0 \).
This analysis helps in forecasting the behavior of functions and understanding how sensitive they are to adjustments in parameters, like \( c \) in our example.
Other exercises in this chapter
Problem 62
Show that if \(f(x)=x^{4},\) then \(f^{\prime \prime}(0)=0,\) but \((0,0)\) is not an inflection point of the graph of \(f .\)
View solution Problem 63
Prove that the function \(f(x)=x^{101}+x^{51}+x+1\) has neither a local maximum nor a local minimum.
View solution Problem 63
Show that the function \(g(x)=x|x|\) has an inflection point at \((0,0)\) but \(g^{\prime \prime}(0)\) does not exist.
View solution Problem 64
If \(f\) has a local minimum value at \(c,\) show that the function \(g(x)=-f(x)\) has a local maximum value at \(c .\)
View solution