Problem 63
Question
Convert the polar equation to rectangular coordinates. $$r=\frac{4}{1+2 \sin \theta}$$
Step-by-Step Solution
Verified Answer
The rectangular form is \(x^2 - 3y^2 + 16y - 16 = 0\).
1Step 1: Recall the Polar to Rectangular Conversion Formulas
To convert from polar coordinates \((r, \theta)\) to rectangular coordinates \((x, y)\), we use: - \(x = r \cos \theta\) - \(y = r \sin \theta\) - \(r^2 = x^2 + y^2\)
2Step 2: Substitute \(r\) and Simplify
Given the equation \(r = \frac{4}{1 + 2 \sin \theta}\), multiply both sides by \(1 + 2 \sin \theta\) to clear the fraction:\[ r(1 + 2 \sin \theta) = 4 \]Substitute \(y = r \sin \theta\):\[ r + 2y = 4 \]
3Step 3: Substitute \(r = \sqrt{x^2 + y^2}\) and Simplify Further
Substitute \(r = \sqrt{x^2 + y^2}\) into \(r + 2y = 4\):\[ \sqrt{x^2 + y^2} + 2y = 4 \]Rearrange to isolate the square root term:\[ \sqrt{x^2 + y^2} = 4 - 2y \]
4Step 4: Square Both Sides to Eliminate the Square Root
Square both sides of \(\sqrt{x^2 + y^2} = 4 - 2y\):\[ x^2 + y^2 = (4 - 2y)^2 \]Expand the right side:\[ x^2 + y^2 = 16 - 16y + 4y^2 \]
5Step 5: Rearrange to Form a Rectangular Equation
Bring all terms to one side of the equation to maintain the equation's form:\[ x^2 + y^2 - 4y^2 + 16y - 16 = 0 \]Simplify the equation:\[ x^2 - 3y^2 + 16y - 16 = 0 \]
Key Concepts
Rectangular CoordinatesPolar CoordinatesConversion Formulas
Rectangular Coordinates
Rectangular coordinates, also known as Cartesian coordinates, are used to determine a position in a plane using two numbers. These numbers are \(x\) and \(y\), where \(x\) represents the horizontal distance from the origin, and \(y\) represents the vertical distance from the origin.
This coordinate system is based on a grid with perpendicular axes, allowing for easy calculation of distances and angles. Here are the main points to understand about rectangular coordinates:
This coordinate system is based on a grid with perpendicular axes, allowing for easy calculation of distances and angles. Here are the main points to understand about rectangular coordinates:
- The plane is divided into four quadrants by the x-axis (horizontal) and the y-axis (vertical).
- Coordinates are written as \( (x, y) \).
- The origin is the point \( (0, 0) \), where the x-axis and y-axis intersect.
Polar Coordinates
Polar coordinates offer a different system for expressing points in a plane, defined by a radius and an angle. Instead of using \(x\) and \(y\) like the rectangular system, polar coordinates use \(r\) and \(\theta\). These represent the distance from the origin and the angle from a reference direction, respectively.
In the polar system:
In the polar system:
- The radius \(r\) indicates how far the point is from the origin.
- The angle \(\theta\) is measured in radians or degrees, usually from the positive x-axis.
- Coordinates are described as \( (r, \theta) \).
Conversion Formulas
The conversion between polar and rectangular coordinates allows us to switch between these two systems of describing locations in a plane. This involves using specific formulas to translate a point from one coordinate system to the other.
To convert from polar coordinates \( (r, \theta) \) to rectangular coordinates \( (x, y) \), use the following formulas:
Understanding these conversions is crucial when dealing with problems requiring switches between the coordinate systems, as seen in tasks like converting polar equations to rectangular equations and vice versa.
To convert from polar coordinates \( (r, \theta) \) to rectangular coordinates \( (x, y) \), use the following formulas:
- \( x = r \cos \theta \)
- \( y = r \sin \theta \)
- \( r^2 = x^2 + y^2 \)
Understanding these conversions is crucial when dealing with problems requiring switches between the coordinate systems, as seen in tasks like converting polar equations to rectangular equations and vice versa.
Other exercises in this chapter
Problem 63
Write \(z_{1}\) and \(z_{2}\) in polar form, and then find the product \(z_{1} z_{2}\) and the quotients \(z_{1} / z_{2}\) and \(1 / z_{1}\). $$z_{1}=2 \sqrt{3}
View solution Problem 63
Compare the rectangular equation of the line \(y=2\) with its polar equation. In which coordinate system is the equation simpler? Which coordinate system would
View solution Problem 64
Write \(z_{1}\) and \(z_{2}\) in polar form, and then find the product \(z_{1} z_{2}\) and the quotients \(z_{1} / z_{2}\) and \(1 / z_{1}\). $$z_{1}=-\sqrt{2}
View solution Problem 64
Convert the polar equation to rectangular coordinates. $$r=\frac{2}{1-\cos \theta}$$
View solution