Problem 63
Question
Begin by graphing the standard quadratic function, \(f(x)-x^{2} .\) Then use transformations of this graph to graph the given function. $$ h(x)-2(x-2)^{2}-1 $$
Step-by-Step Solution
Verified Answer
The graph of the function \(h(x) = 2(x-2)^2 - 1\) is a parabola that opens upwards with its vertex at (2, -1) and is two times steeper than the standard quadratic function \(f(x) = x^2\).
1Step 1: Plot the standard quadratic function
The standard quadratic function is given as \(f(x) = x^2\), which forms a parabola. This graph opens upwards and its vertex is at the origin, (0,0).
2Step 2: Identify the transformations from the given function
The given function is \(h(x) = 2(x-2)^2 - 1\). Comparing it with the standard quadratic function, the transformations needed are: a horizontal shift to the right by 2 units (due to (x-2), a vertical shift downward by 1 unit (due to -1), and a vertical stretch by factor of 2 (due to the coefficient of 2).
3Step 3: Apply the transformations to graph the function
Starting with the graph of \(f(x) = x^2\), move the curve to the right by 2 units, representing a horizontal shift. Then, move it downward by 1 unit to represent the vertical shift. Finally, stretch the resulting graph vertically by a factor of 2. The vertex of the new parabola is (2, -1), the graph opens upwards and it is 2 times steeper than the graph of the standard quadratic function.
Key Concepts
Graph TransformationsParabolaVertexVertical Stretch
Graph Transformations
When working with quadratic functions, graph transformations are a powerful way to understand changes in a graph's appearance by applying shifts, stretches, or reflections. The standard form of a quadratic function is typically represented as \(f(x) = x^2\), which forms a simple, upward-opening parabola centered at the origin (0, 0). By applying specific transformations, we can modify the graph's position and shape without changing its basic parabolic nature.
These transformations include:
These transformations include:
- Horizontal Shifts: Moving the graph left or right along the x-axis.
- Vertical Shifts: Moving the graph up or down along the y-axis.
- Vertical Stretches or Compressions: Making the graph appear taller or flatter.
Parabola
The parabola is a U-shaped curve that graphically represents quadratic functions. For the standard quadratic function \(f(x) = x^2\), the parabola opens upward, indicating that its arms extend toward positive infinity as you move away from the vertex.
Every parabola has a distinctive set of features:
Every parabola has a distinctive set of features:
- Vertex: The highest or lowest point of the parabola.
- Axis of Symmetry: A vertical line that splits the parabola into two mirror images.
- Direction: Determines whether the parabola opens upwards or downwards, which depends on the sign of the coefficient before \(x^2\).
Vertex
The vertex of a parabola is a significant point that tells us a lot about the graph's orientation and position. In the parent function \(f(x) = x^2\), the vertex is at the origin (0, 0). It is located at the highest or lowest point on the graph, depending on the parabola's direction.
For the transformed function \(h(x) = 2(x-2)^2 - 1\), the vertex has moved due to the applied graph transformations:
For the transformed function \(h(x) = 2(x-2)^2 - 1\), the vertex has moved due to the applied graph transformations:
- The horizontal shift to the right by 2 units results in the new vertex being at x = 2.
- The vertical shift downward by 1 unit changes the y-coordinate of the vertex to -1.
Vertical Stretch
Vertical stretches alter the height of a parabola, making it narrower or wider. This transformation depends on the coefficient of the \(x^2\) term in the quadratic function. In the case of \(h(x) = 2(x-2)^2 - 1\), the coefficient 2 indicates a vertical stretch.
To visualize a vertical stretch:
To visualize a vertical stretch:
- A coefficient greater than 1, like 2, makes the parabola narrower than the standard \(f(x) = x^2\) parabola.
- A coefficient between 0 and 1 would make it wider.
Other exercises in this chapter
Problem 62
Complete the square and write the equation in standard form. Then give the center and radius of each circle and graph the equation. $$ x^{2}+y^{2}+x+y-\frac{1}{
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View solution Problem 63
Complete the square and write the equation in standard form. Then give the center and radius of each circle and graph the equation. $$ x^{2}+y^{2}+3 x-2 y-1=0 $
View solution Problem 63
Find and simplify the difference quotient $$\frac{f(x+h)-f(x)}{h}, h \neq 0$$ for the given function. $$f(x)=2 x^{2}+x-1$$
View solution