Problem 63
Question
ASTRONOMY The comet Encke has an elliptical orbit with an eccentricity of \(e \approx 0.847\). The length of the major axis of the orbit is approximately \(4.42\) astronomical units. Find a polar equation for the orbit. How close does the comet come to the sun?
Step-by-Step Solution
Verified Answer
The polar equation for the orbit of the comet Encke is \(r = \frac{2.21}{1 + 0.847 \cdot cos(\theta)}\). The comet comes closest to the sun at a distance of 0.69 Astronomical Units.
1Step 1: Define the Ellipse's Polar Equation
The polar equation of an ellipse with one of its foci at the origin (which in astronomy is typically the Sun) is given by \(r = \frac{l}{1 + e \cdot cos(\theta)}\) where \(l\) is the semi-major axis (half the length of the major axis), \(e\) is the eccentricity, and \(\theta\) is the angle.
2Step 2: Substitute Known Values
Now, filling in the given values for \(e\) (0.847) and \(l\) (which is half of 4.42 Astronomical Units, so it equals 2.21), the equation of Encke's comet can be derived: \(r = \frac{2.21}{1 + 0.847 \cdot cos(\theta)}\). This equation describes the ellipse traced by the comet around the sun.
3Step 3: Determine the Closest Approach to the Sun
The comet will be closest to the sun when \(\theta = 0\). Substituting \(\theta = 0\) into the equation gives us the distance at the closest approach, which is known as the perihelion distance: \(r = \frac{2.21}{1 + 0.847 \cdot cos(0)} = \frac{2.21}{1 + 0.847} = 0.69\) Astronomical Units.
Key Concepts
Understanding EccentricityExploring Elliptical OrbitsPerihelion Distance Explained
Understanding Eccentricity
Eccentricity is a key characteristic of an ellipse. It measures how much an ellipse deviates from being a perfect circle. An eccentricity value can range from 0 to 1.
Eccentricity is crucial not only for determining the shape but also for calculating other parameters such as the distance from the focal point. This elongation allows astronomers to determine the distances within the orbit, such as the perihelion and aphelion (the comet's farthest point from the Sun). Understanding eccentricity helps in interpreting how celestial bodies like comets travel in elliptical paths.
- If the eccentricity (\(e\)) is 0, the shape is a perfect circle.
- If \(0 < e < 1\), the shape is an ellipse.
- As \(e\) approaches 1, the ellipse becomes more elongated.
Eccentricity is crucial not only for determining the shape but also for calculating other parameters such as the distance from the focal point. This elongation allows astronomers to determine the distances within the orbit, such as the perihelion and aphelion (the comet's farthest point from the Sun). Understanding eccentricity helps in interpreting how celestial bodies like comets travel in elliptical paths.
Exploring Elliptical Orbits
An elliptical orbit is the oval-shaped path that celestial bodies follow as they move around a focal point. In the case of comets, planets, and other celestial objects, this focal point is usually a star like the Sun. This is because of the gravitational pull exerted by the star.
In an elliptical orbit:
In an elliptical orbit:
- Each ellipse has two focal points, but in celestial mechanics, one of these points typically coincides with the center of mass of the system, like the Sun.
- The longest line that can be drawn across the ellipse is called the major axis. The length of the semi-major axis (\(l\)) is half of this distance, and in comet Encke's case, it is 2.21 astronomical units.
- The polar equation describing an ellipse is given by \(r = \frac{l}{1 + e \cdot \cos(\theta)}\), where \(\theta\) represents the angle of deviation from the perihelion.
Perihelion Distance Explained
The perihelion distance is all about how close a celestial body, like a comet, comes to the Sun during its orbit. This point marks the minimum radius in the elliptical path.
Calculating the perihelion distance involves setting \(\theta = 0\) in the polar equation of the ellipse, as this represents the angle at which the object is closest to the Sun.
Calculating the perihelion distance involves setting \(\theta = 0\) in the polar equation of the ellipse, as this represents the angle at which the object is closest to the Sun.
- For example, using Encke's comet eccentricity of 0.847, the perihelion distance was calculated to be approximately 0.69 astronomical units.
- This calculation involves substituting \(\theta\) with 0 in the equation, transforming it into \(r = \frac{2.21}{1 + 0.847}\).
- This is the shortest distance the comet will achieve from the Sun, highlighting its proximity during this part of the orbit.
Other exercises in this chapter
Problem 62
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