Problem 63
Question
A rectangular playing field with a perimeter of 100 meters is to have an area of at least 500 square meters (see figure). Within what bounds must the length be?
Step-by-Step Solution
Verified Answer
The length of the rectangular field must be between approximately 15.81 meters and 34.19 meters.
1Step 1: Formulate the Constraints
First, write down the formulas for the perimeter and the area of a rectangle. The perimeter \(P\) of a rectangle with length \(L\) and width \(W\) is \(P=2(L+W)\), and the area \(A\) is \(A=LW\). Given that \(P = 100\) m and \(A = 500\) m², we have the two equations \(2(L + W)=100\) and \(LW=500\).
2Step 2: Solve for \(W\)
Rearrange the equation for \(P\) to compute for \(W\). From \(2(L+W)=100\), we can simplify to \(L+W=50\) m. Isolate \(W\) to obtain \(W=50-L\).
3Step 3: Substitute \(W\) in Area Equation
Substitute \(W=50-L\) into the equation for \(A\), which gives us the equation \(L(50-L)=500\). Expand this to \(50L - L^2 = 500.\)
4Step 4: Solve for \(L\)
Rearrange and solve the equation \(50L - L^2 = 500\) giving us a quadratic equation \(L^2 - 50L + 500 = 0\). Solve this quadratic equation for \(L\) using the quadratic formula \(L = \frac{50 \pm \sqrt{50^2 - 4*500}}{2}\), which yields two solutions for \(L\) that will represent the bounds for the length of the rectangle.
Key Concepts
Quadratic EquationsRectangular GeometryPerimeter and Area
Quadratic Equations
Quadratic equations are fundamental in algebra, often represented in the form \( ax^2 + bx + c = 0 \). They arise in many areas such as physics, engineering, and as we see here, geometry. When solving quadratic equations, we commonly encounter terms like \( L^2 - 50L + 500 = 0 \) in this exercise. This form is the "standard form" of a quadratic equation, where:
- \( L^2 \) is the quadratic term,
- \( 50L \) is the linear term,
- 500 is the constant term.
Rectangular Geometry
Rectangular geometry encompasses shapes with four sides and right angles, known as rectangles. In mathematics, these figures are characterized by parameters such as length \( L \) and width \( W \). These parameters are essential as they determine properties like perimeter and area.
In the given problem, the playing field's dimensions are subject to certain conditions, like the perimeter \( P = 2(L + W) \) and area \( A = LW \). By manipulating these formulas, we can express one property in terms of the other.
In the given problem, the playing field's dimensions are subject to certain conditions, like the perimeter \( P = 2(L + W) \) and area \( A = LW \). By manipulating these formulas, we can express one property in terms of the other.
- Perimeter gives us "circumference," or total boundary, of the rectangle.
- We can solve for unknown dimensions when one characteristic, like length, is constrained.
Perimeter and Area
In any geometry-related problem involving rectangles, understanding the concepts of perimeter and area is crucial.
The perimeter of a rectangle, calculated by \( P = 2(L + W) \), represents the total distance around the shape. For the field in question, the perimeter is 100 meters which limits the sum of the length and width to 50 meters.
The perimeter of a rectangle, calculated by \( P = 2(L + W) \), represents the total distance around the shape. For the field in question, the perimeter is 100 meters which limits the sum of the length and width to 50 meters.
- Perimeter is significant in problems where the physical length of fencing, border, or frame material is constrained.
- It influences spatial design and layout considerations.
- Area affects space utilization and capacity.
- It's pivotal in assessing usage efficiency of rectangular domains.
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