Problem 63
Question
A particle with mass \(m\) and total energy \(E\) tunnels through a square barrier of height \(U_{0}\) and width \(L .\) When the trans- mission coefficient is not much less than unity, it is given by $$T=\left[1+\frac{\left(U_{0} \sinh \kappa L\right)^{2}}{4 E\left(U_{0}-E\right)}\right]^{-1}$$ where \(\sinh \kappa L=\left(e^{\kappa L}-e^{-\kappa L}\right) / 2\) is the hyperbolic sine of \(\kappa L .\) (a) Show that if \(\kappa L \gg 1\) , this expression for \(T\) approaches Eq. \((40.42) .\) (b) Explain why the restriction \(\kappa L>1\) in part (a) implies either that the barrier is relatively wide or the energy \(E\) is relatively low compared to \(U_{0 .}\) (c) Show that as the particle's incident kinetic energy \(E\) approaches the barrier height \(U_{0}\) . \(T\) approaches \(\left[1+(k L / 2)^{2}\right]^{-1},\) where \(k=\sqrt{2 m E / \hbar}\) is the wave number of the incident particle. (Hint: If \(|z|<1,\) then \(\sinh z \approx z . )\)
Step-by-Step Solution
VerifiedKey Concepts
transmission coefficient
The formula for the transmission coefficient can vary under different conditions, but in this scenario, it is given by:
- \[T = \left[1 + \frac{(U_0 \sinh \kappa L)^2}{4E(U_0 - E)}\right]^{-1}\]
Under certain conditions, like \( \kappa L \gg 1 \), the transmission coefficient can be simplified, reflecting a lesser probability for particles to pass through very thick barriers. This provides insight into the delicate balance between particle energy, barrier height, and width in determining tunneling behavior.
potential barrier
For a particle approaching such a barrier, its behavior is dictated by the relative sizes of its energy \( E \) and the barrier height \( U_0 \).
- If \( E \) is greater than \( U_0 \), the particle can move over the barrier.
- If \( E \) is less than \( U_0 \), the particle must rely on tunneling.
hyperbolic sine function
This function becomes significant particularly when \( \kappa L \) is large, (
- If \( \kappa L \gg 1 \), \( \sinh \kappa L \) simplifies to \( \frac{1}{2} e^{\kappa L} \).
One might wonder why \( \sinh \) instead of regular sine is used. This lies in the mathematics governing quantum mechanics, where certain differential equations naturally lead to hyperbolic rather than trigonometric functions. Trigonometric functions like sine and cosine are used for oscillatory behavior, whereas hyperbolic functions are suited for exponential-type decay or growth, typical of quantum tunneling scenarios.