Problem 63
Question
(a) factor by grouping. Identify any prime polynomials. (b) check. $$ 3 a c+b d-3 a d-b c $$
Step-by-Step Solution
Verified Answer
The polynomial factors to \( (3a - b)(c - d) \).
1Step 1: Group the terms
Group the terms in pairs to make the factoring process easier: \(3ac + bd - 3ad - bc\).
2Step 2: Factor out the common factor from each group
Factor out the common factor from each group: \(3ac - 3ad\) and \(bd - bc\). This results in: \( 3a(c - d) + b(d - c) \).
3Step 3: Factor out the common binomial factor
Notice that \( c - d \) and \( d - c \) are opposites. Rewrite \( b(d - c) \) as \( -b(c - d) \), and then factor out the common binomial factor \( c - d \): \( 3a(c - d) - b(c - d) \).
4Step 4: Simplify the expression
Factor \( c - d \) from the expression: \( (3a - b)(c - d) \).
5Step 5: Check the factorization
Expand \( (3a - b)(c - d) \) to confirm it matches the original polynomial: \( (3a - b)(c - d) = 3ac - 3ad - bc + bd \). The factorization is correct.
Key Concepts
polynomial factorizationcommon factorsbinomial expressionselementary algebra
polynomial factorization
Polynomial factorization involves breaking down a polynomial into simpler factors. These factors multiply to give the original polynomial.
In the problem, we have the polynomial expression: \(3ac + bd - 3ad - bc\).
The goal is to factor it into simpler expressions. We start by grouping the terms.
In the problem, we have the polynomial expression: \(3ac + bd - 3ad - bc\).
The goal is to factor it into simpler expressions. We start by grouping the terms.
common factors
Identifying common factors in a polynomial helps break it down into simpler parts. In the polynomial expression given, we group terms to find common factors:
\(3ac - 3ad\) and \(bd - bc\).
From the first pair, the common factor is \(3a\).
From the second pair, the common factor is \(b\).
Factoring these out, we get: \(3a(c - d) + b(d - c)\).
\(3ac - 3ad\) and \(bd - bc\).
From the first pair, the common factor is \(3a\).
From the second pair, the common factor is \(b\).
Factoring these out, we get: \(3a(c - d) + b(d - c)\).
binomial expressions
A binomial expression contains two terms. Here, the binomial expressions \((c - d)\) and\((d - c)\) appear after factoring out the common factors from each group:
\(3a(c - d) + b(d - c)\).
Notice that \(d - c\) is the opposite of \(c - d\).
By rewriting \(b(d - c)\) as \(-b(c - d)\), we can factor out the common binomial expression \((c - d)\):
\(3a(c - d) - b(c - d)\)
which simplifies to \((3a - b)(c - d)\).
\(3a(c - d) + b(d - c)\).
Notice that \(d - c\) is the opposite of \(c - d\).
By rewriting \(b(d - c)\) as \(-b(c - d)\), we can factor out the common binomial expression \((c - d)\):
\(3a(c - d) - b(c - d)\)
which simplifies to \((3a - b)(c - d)\).
elementary algebra
Elementary algebra involves basic algebraic operations, including factorization, which we used in this exercise. The steps taken are fundamental techniques:
This matches the original polynomial, confirming our factorization is correct.
- Grouping terms to simplify the expression.
- Factoring out common factors.
- Identifying binomial expressions and common factors within them.
This matches the original polynomial, confirming our factorization is correct.
Other exercises in this chapter
Problem 63
Use any of the factoring methods to factor. Identify any prime polynomials. $$ 18 x^{2}+5 x-7 $$
View solution Problem 63
Factor. Either factor out the greatest common factor, factor by grouping, use the guess and check method, or use the \(a c\) method. $$ 8 d^{2}+26 d+21 $$
View solution Problem 64
(a) solve. (b) check. $$ 6 v^{2}+31 v+35=0 $$
View solution Problem 64
Factor completely. Identify any prime polynomials. $$ 5 k y^{2}-10 y^{2} $$
View solution