Problem 62
Question
Verify that each equation is an identity. $$\sec 2 x=\frac{1+\tan ^{2} x}{1-\tan ^{2} x}$$
Step-by-Step Solution
Verified Answer
The given equation is an identity because both sides simplify to \( \frac{1}{\cos 2x} \).
1Step 1: Understand the Identity
We are given the equation \( \sec 2x = \frac{1 + \tan^2 x}{1 - \tan^2 x} \) and need to verify if it is true for all \( x \). An identity holds true for all values within the domain of the functions involved. First, we should recall that \( \sec 2x = \frac{1}{\cos 2x} \).
2Step 2: Express in Terms of Sine and Cosine
Express both sides of the identity in terms of sine and cosine:- For the left side, \( \sec 2x = \frac{1}{\cos 2x} \).- For the right side, use the identity \( \tan x = \frac{\sin x}{\cos x} \), so \( \tan^2 x = \frac{\sin^2 x}{\cos^2 x} \). Substituting, we have:\[\frac{1 + \tan^2 x}{1 - \tan^2 x} = \frac{1 + \frac{\sin^2 x}{\cos^2 x}}{1 - \frac{\sin^2 x}{\cos^2 x}} = \frac{\frac{\cos^2 x + \sin^2 x}{\cos^2 x}}{\frac{\cos^2 x - \sin^2 x}{\cos^2 x}}\]
3Step 3: Simplify the Right Hand Side
Notice that \( \cos^2 x + \sin^2 x = 1 \). Therefore, the right side simplifies to:\[\frac{1}{\frac{\cos^2 x - \sin^2 x}{\cos^2 x}} = \frac{\cos^2 x}{\cos^2 x - \sin^2 x} = \frac{\cos^2 x}{\cos 2x}\] since \( \cos 2x = \cos^2 x - \sin^2 x \). Then, the right side becomes: \( \frac{1}{\cos 2x} \).
4Step 4: Conclude the Verification
Both sides of the equation have now been simplified to \( \frac{1}{\cos 2x} \), confirming that the given equation \( \sec 2x = \frac{1 + \tan^2 x}{1 - \tan^2 x} \) is indeed an identity. Thus, it holds true for all \( x \) where the expressions are defined.
Key Concepts
Secant FunctionTangent FunctionPythagorean Identity
Secant Function
The secant function, denoted as \( \sec x \), is one of the six fundamental trigonometric functions. It is the reciprocal of the cosine function, meaning that \( \sec x = \frac{1}{\cos x} \). The secant function is particularly interesting because it tends to exhibit vertical asymptotes, which occur at the zeros of the cosine function.
Aside from its relationship with the cosine function, the secant function finds its application in various scenarios, such as in calculating the magnitudes of vectors and in waveforms.
Aside from its relationship with the cosine function, the secant function finds its application in various scenarios, such as in calculating the magnitudes of vectors and in waveforms.
- When examining functions like \( \sec 2x \), we apply transformations to the standard secant function, which involves stretching the curve horizontally, making it useful in complex equations and identities.
- Understanding the secant function in relation to the cosine function helps in verifying and manipulating trigonometric identities effectively.
Tangent Function
The tangent function, represented by \( \tan x \), is another fundamental trigonometric function. It is defined as the ratio of the sine and cosine functions, expressed as \( \tan x = \frac{\sin x}{\cos x} \).
In practical terms, the tangent function describes the slope of the line formed by an angle in the unit circle and is essential in determining angles in various calculations like elevations and depressions.
In practical terms, the tangent function describes the slope of the line formed by an angle in the unit circle and is essential in determining angles in various calculations like elevations and depressions.
- One of the key properties of the tangent function is that it is periodic with a period of \( \pi \), meaning it repeats its values in intervals of \( \pi \).
- Like the secant function, the tangent function also exhibits asymptotic behavior, specifically around points where its denominator, \( \cos x \), equals zero.
Pythagorean Identity
The Pythagorean identity is one of the most important identities in trigonometry, establishing a fundamental link among the sine, cosine, and secant functions. It is usually expressed as \( \sin^2 x + \cos^2 x = 1 \).
This relation stems from the unit circle, where any point on the circle can be represented as \( (\cos x, \sin x) \), leading to the equation of the circle being \( x^2 + y^2 = 1 \).
This relation stems from the unit circle, where any point on the circle can be represented as \( (\cos x, \sin x) \), leading to the equation of the circle being \( x^2 + y^2 = 1 \).
- The identity allows for transformations and simplifications of more complex expressions by substituting one part of the identity to simplify trigonometric equations.
- It also provides a pathway to derive other forms of the identity, such as \( 1 + \tan^2 x = \sec^2 x \), by dividing the initial identity by \( \cos^2 x \).
Other exercises in this chapter
Problem 61
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