Problem 62
Question
Shows a bird catching a fish. Assume that initially the fish jumps up and that the bird coasts horizontally and does not touch the water with its feet or flap its wings. (a) Is this kind of collision (1) elastic, (2) inelastic, or (3) completely inelastic? Why? (b) If the mass of the bird is \(5.0 \mathrm{~kg}\), the mass of the fish is \(0.80 \mathrm{~kg}\), and the bird coasts with a speed of \(6.5 \mathrm{~m} / \mathrm{s}\) before grabbing, what is the speed of the bird after grabbing the fish?
Step-by-Step Solution
Verified Answer
(a) The collision is (3) completely inelastic. (b) The speed of the bird after grabbing the fish is approximately 5.6 m/s.
1Step 1: Analyze the Type of Collision
This scenario involves a bird catching a fish in the air. In this event, the bird and the fish stick together after the interaction. In collisions where the objects stick together, the collision is known as completely inelastic. Thus, this collision is (3) completely inelastic.
2Step 2: Setup Conservation of Momentum Equation
In completely inelastic collisions, the mass after collision is the sum of the masses of the two objects, and only momentum is conserved. The momentum before the collision is \( m_b v_b + m_f v_f \), and after the collision is \( (m_b + m_f) v' \), where \( v' \) is the final velocity of the bird-fish system, \( m_b \) is the mass of the bird, and \( m_f \) is the mass of the fish.
3Step 3: Determine Initial Momentum
Before the collision, the fish's initial vertical speed does not contribute to horizontal momentum of the bird-fish system, so \( v_f = 0 \) m/s. The initial total horizontal momentum is thus \( m_b v_b = 5.0 \times 6.5 = 32.5 \text{ kg m/s} \).
4Step 4: Calculate Final Velocity of Bird and Fish System
Since the momentum is conserved, set the initial horizontal momentum equal to the final horizontal momentum: \( 32.5 = (5.0 + 0.80) v' \). Solve for \( v' \): \( v' = \frac{32.5}{5.8} \approx 5.6 \text{ m/s} \).
Key Concepts
Conservation of MomentumCollision TypesMomentum Calculation
Conservation of Momentum
In physics, momentum is a fundamental concept that embodies the motion of objects. The conservation of momentum principle is crucial in understanding interactions like collisions. Conservation of momentum means that in a closed system with no external forces, the total momentum remains constant before and after a collision.
Imagine a scenario where a bird catches a fish. From the problem, we assume no external horizontal forces act on the bird-fish system during the interaction. This makes it an excellent example of momentum conservation.
\[ m_b v_b + m_f v_f = (m_b + m_f) v' \]Where:
\( m_b \) and \( m_f \) are the masses of the bird and fish respectively,
\( v_b \) and \( v_f \) are their respective velocities before the collision,
\( v' \) is the shared velocity after the collision.
Imagine a scenario where a bird catches a fish. From the problem, we assume no external horizontal forces act on the bird-fish system during the interaction. This makes it an excellent example of momentum conservation.
- Before the collision, the bird is flying horizontally with momentum calculated as the product of its mass and velocity, given by \( m_b v_b \).
- The fish leaps into the air and has no initial horizontal momentum, \( v_f = 0 \) m/s.
\[ m_b v_b + m_f v_f = (m_b + m_f) v' \]Where:
\( m_b \) and \( m_f \) are the masses of the bird and fish respectively,
\( v_b \) and \( v_f \) are their respective velocities before the collision,
\( v' \) is the shared velocity after the collision.
Collision Types
Collisions in physics can be broadly categorized based on how energy and momentum are conserved during the interaction.
These categories include elastic, inelastic, and completely inelastic collisions. Specifically, a completely inelastic collision is backed by unique characteristics:
These categories include elastic, inelastic, and completely inelastic collisions. Specifically, a completely inelastic collision is backed by unique characteristics:
- In an **elastic collision**, both momentum and kinetic energy are conserved.
- In an **inelastic collision**, only momentum is conserved, not kinetic energy.
- In a **completely inelastic collision**, as seen in the problem, momentum is conserved but objects stick together post-collision.
Momentum Calculation
Calculating the momentum in systems like a bird catching a fish helps understand the velocities involved in collisions. Initially, we focus on the momentum of each object before they interact:
\[ 5.0 \times 6.5 = 32.5 \text{ kg m/s} \]
This is the total initial momentum, entirely contributed by the bird's flight. Post-collision, the final momentum has to match this initial value since momentum is conserved:
\[ (m_b + m_f) \times v' = 32.5 \text{ kg m/s} \]
Where:
\[ v' = \frac{32.5}{5.8} \approx 5.6 \text{ m/s} \]
This result gives the speed of both the bird and fish after they collide and move together, highlighting the concept of momentum conservation in action.
- The bird's initial momentum is computed as \( m_b \times v_b \).
- For the fish, since it leaps upward, its horizontal velocity is \( v_f = 0 \), giving it zero initial horizontal momentum.
\[ 5.0 \times 6.5 = 32.5 \text{ kg m/s} \]
This is the total initial momentum, entirely contributed by the bird's flight. Post-collision, the final momentum has to match this initial value since momentum is conserved:
\[ (m_b + m_f) \times v' = 32.5 \text{ kg m/s} \]
Where:
- \( m_b = 5.0 \text{ kg} \) is the mass of the bird,
- \( m_f = 0.80 \text{ kg} \) is the mass of the fish,
- \( v' \) is the velocity to find.
\[ v' = \frac{32.5}{5.8} \approx 5.6 \text{ m/s} \]
This result gives the speed of both the bird and fish after they collide and move together, highlighting the concept of momentum conservation in action.
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