Problem 62
Question
Show that for any power function \(f(x)=x^{n}\), we have \(f^{\prime}(1)=n\)
Step-by-Step Solution
Verified Answer
The derivative \( f'(1) = n \) for \( f(x) = x^n \).
1Step 1: Understand the Problem
We need to show that the derivative of the function \( f(x) = x^n \) evaluated at \( x = 1 \) is equal to \( n \). This means finding \( f'(x) \) and then substituting \( x = 1 \) into this derivative.
2Step 2: Recall the Power Rule for Derivatives
The power rule states that if \( f(x) = x^n \), then the derivative \( f'(x) \) is found using the formula \( f'(x) = nx^{n-1} \). This formula is applicable for any real number \( n \).
3Step 3: Apply the Power Rule
Using the power rule, we differentiate the function \( f(x) = x^n \) to get \( f'(x) = nx^{n-1} \).
4Step 4: Evaluate the Derivative at x = 1
Substitute \( x = 1 \) into the derivative \( f'(x) = nx^{n-1} \). We have \( f'(1) = n(1)^{n-1} = n \), since \( 1^{n-1} = 1 \) for any \( n \).
5Step 5: Conclusion
We have shown that \( f'(1) = n \) for the power function \( f(x) = x^n \), as required by the problem statement.
Key Concepts
DerivativesPower RuleEvaluating Derivatives
Derivatives
To start with the concept of derivatives, it is essential to understand that a derivative of a function essentially tells us how the function's value changes as the input changes. When we talk about derivatives, we are often referring to the slope of the function's graph at a particular point. For a function given by \( f(x) = x^n \), the derivative \( f'(x) \) represents the rate at which \( f(x) \) changes with respect to \( x \).
Derivatives are foundational in calculus, because they give us powerful tools to analyze and interpret functions. By knowing how a function behaves in relation to its input, we are able to make predictions about the function's tendencies, such as increasing or decreasing behaviour. Understanding derivatives is crucial for solving many real-world problems, such as optimization and curve sketching.
In our context, the derivative helps determine the nature of the polynomial \( x^n \) at specific points, such as \( x = 1 \).
Derivatives are foundational in calculus, because they give us powerful tools to analyze and interpret functions. By knowing how a function behaves in relation to its input, we are able to make predictions about the function's tendencies, such as increasing or decreasing behaviour. Understanding derivatives is crucial for solving many real-world problems, such as optimization and curve sketching.
In our context, the derivative helps determine the nature of the polynomial \( x^n \) at specific points, such as \( x = 1 \).
Power Rule
The power rule is one of the simplest yet most useful rules for finding derivatives. It applies when we have a power function, which is a function in the form \( f(x) = x^n \). In essence, the power rule tells us how to quickly differentiate such functions.
For example, if \( n = 3 \), the derivative of \( x^3 \) will be \( 3x^2 \). This simplification is incredibly handy because it allows you to differentiate power functions rapidly without dealing with limits directly every time.
By using the power rule, it becomes straightforward to find the derivative of any power function and analyze its behavior confidently at any point, such as \( x = 1 \), in our case.
- If \( f(x) = x^n \), then its derivative, denoted \( f'(x) \), is \( nx^{n-1} \).
For example, if \( n = 3 \), the derivative of \( x^3 \) will be \( 3x^2 \). This simplification is incredibly handy because it allows you to differentiate power functions rapidly without dealing with limits directly every time.
By using the power rule, it becomes straightforward to find the derivative of any power function and analyze its behavior confidently at any point, such as \( x = 1 \), in our case.
Evaluating Derivatives
Evaluating derivatives means finding the specific value of the derivative at a certain point. This process involves two main steps: first, finding the general derivative of the function, and second, substituting the specific point into this derivative to evaluate it.
In our example with the power function \( f(x) = x^n \), we first used the power rule to find that \( f'(x) = nx^{n-1} \). For evaluation, we substitute \( x = 1 \) into this expression, giving us \( f'(1) = n(1)^{n-1} \).
In our example with the power function \( f(x) = x^n \), we first used the power rule to find that \( f'(x) = nx^{n-1} \). For evaluation, we substitute \( x = 1 \) into this expression, giving us \( f'(1) = n(1)^{n-1} \).
- Since \( 1^{n-1} = 1 \) for any \( n \), the result simplifies to \( f'(1) = n \).
Other exercises in this chapter
Problem 60
A ball is dropped from the top of the Empire State Building. The height, \(y\), of the ball above the ground (in feet) is given as a function of time, \(t\), (i
View solution Problem 61
Let \(f(x)=x^{3}-6 x^{2}-15 x+20\). Find \(f^{\prime}(x)\) and all values of \(x\) for which \(f^{\prime}(x)=0 .\) Explain the relationship between these values
View solution Problem 63
If the demand curve is a line, we can write \(p=b+m q\), where \(p\) is the price of the product, \(q\) is the quantity sold at that price, and \(b\) and \(m\)
View solution Problem 59
The cost (in dollars) of producing \(q\) items is given by \(C(q)=0.08 q^{3}+75 q+1000\) (a) Find the marginal cost function. (b) Find \(C(50)\) and \(C^{\prime
View solution