Problem 62
Question
Rewrite each angle in degree measure. (Do not use a calculator.) (a) \(-\frac{7 \pi}{12}\) (b) \(\frac{\pi}{9}\)
Step-by-Step Solution
Verified Answer
The angle \(-\frac{7 \pi}{12}\) radians is equal to -105 degrees and the angle \(\frac{\pi}{9}\) radians is equal to 20 degrees.
1Step 1: Convert the first angle from radians to degrees
The first angle given is \(-\frac{7 \pi}{12}\) radians. To convert this to degrees, multiply by the factor \(\frac{180}{\pi}\) degrees/radian. The \(\pi\) in the numerator of the angle and the \(\pi\) in the denominator of the conversion factor will cancel out. So the calculation becomes: \(-\frac{7 \pi}{12} \times \frac{180}{\pi} = -\frac{7 \times 180}{12} = -105\). Therefore, \(-\frac{7 \pi}{12}\) radians is exactly -105 degrees.
2Step 2: Convert the second angle from radians to degrees
The second angle given is \(\frac{\pi}{9}\) radians. Similar to the first angle, to convert this to degrees, multiply by the conversion factor \(\frac{180}{\pi}\). Thus, we get \(\frac{\pi}{9} \times \frac{180}{\pi}\). The \(\pi\) in the numerator of the angle and the \(\pi\) in the denominator of the conversion factor will cancel out, leaving: \(\frac{1 \times 180}{9} = 20\). Therefore, \(\frac{\pi}{9}\) radians is exactly 20 degrees.
Other exercises in this chapter
Problem 62
Find the values of \(\theta\) in degrees \(\left(0^{\circ}
View solution Problem 62
Determine whether the statement is true or false. Justify your answer. $$ \tan a=\tan (a-6 \pi) $$
View solution Problem 62
A buoy oscillates in simple harmonic motion as waves go past. It is noted that the buoy moves a total of 3.5 feet from its low point to its high point (see figu
View solution Problem 62
Find the exact value of the expression. (Hint: Sketch a right triangle.) $$ \tan \left[\arcsin \left(-\frac{3}{4}\right)\right] $$
View solution