Problem 62
Question
Predict the geometric shapes of (a) \(\mathrm{CO} ;\) (b) \(\mathrm{SiCl}_{4}\); (c) \(\mathrm{PH}_{3} ;\) (d) \(\mathrm{ICl}_{3} ;\) (e) \(\mathrm{SbCl}_{5} ;\) (f) \(\mathrm{SO}_{2} ;\) (g) \(\mathrm{AlF}_{6}^{3-}\).
Step-by-Step Solution
Verified Answer
The shapes of the molecules are: (a) CO, linear; (b) SiCl4, tetrahedral; (c) PH3, trigonal pyramidal; (d) ICl3, T-shaped; (e) SbCl5, trigonal bipyramidal; (f) SO2, bent or V-shaped; (g) AlF6^3-, octahedral.
1Step 1: Determine the Central Atom
The first step is to identify the central atom in each molecule. The central atom is generally the one that is linked to all other atoms in the molecule. In our case, for (a) CO, the central atom is C; (b) SiCl4, the central atom is Si; (c) PH3, the central atom is P; (d) ICl3, the central atom is I; (e) SbCl5, the central atom is Sb; (f) SO2, the central atom is S; (g) AlF6^3-, the central atom is Al.
2Step 2: Count the Number of Electron Groups Around Central Atom
Count the number of bonding groups (single, double, or triple bonds) and non-bonding groups (lone pairs of electrons) around the central atom. For: (a) CO, 3 groups (two bonding, one non-bonding); (b) SiCl4, 4 groups (all bonding); (c) PH3, 4 groups (3 bonding, 1 non-bonding); (d) ICl3, 5 groups (3 bonding, 2 non-bonding); (e) SbCl5, 5 groups (all bonding); (f) SO2, 3 groups (two bonding, one non-bonding); (g) AlF6^3-, 6 groups (all bonding).
3Step 3: Determine the Molecular Geometry
Based on these number of groups and the VSEPR theory, the shapes are: (a) CO, linear; (b) SiCl4, tetrahedral; (c) PH3, trigonal pyramidal; (d) ICl3, T-shaped; (e) SbCl5, trigonal bipyramidal; (f) SO2, bent or V-shaped; (g) AlF6^3-, octahedral.
Key Concepts
Molecular GeometryBonding GroupsCentral Atom IdentificationElectron Groups
Molecular Geometry
Molecular geometry refers to the three-dimensional arrangement of atoms within a molecule. This arrangement determines the overall shape of the molecule and plays a crucial role in its reactivity and properties. According to VSEPR (Valence Shell Electron Pair Repulsion) theory, the geometry of a molecule depends on the number and arrangement of electron groups around the central atom. These electron groups strive to position themselves as far apart as possible to minimize repulsion.
For example,
For example,
- In a molecule like \({\mathrm{CO}}\), with a central carbon atom and two electron groups, the molecular geometry is linear.
- This contrasts with a molecule like \({\mathrm{SiCl_{4}}}\), which has four bonding groups and a tetrahedral shape, due to the four groups arranging themselves at maximum distances from each other.
Bonding Groups
Bonding groups are critical in understanding molecular geometry as they represent the connections that form between atoms, whether through single, double, or triple bonds. Each bond, regardless of its type, is considered one bonding group within the framework of VSEPR theory.
For instance,
For instance,
- In \({\mathrm{PH}_{3}}\), there are three bonding groups corresponding to the three hydrogen atoms bonded to phosphorus.
- Similarly, \({\mathrm{SbCl}_{5}}\) has five bonding groups, each chlorine atom individually bonded to antimony.
Central Atom Identification
Identifying the central atom in a molecule is the first and perhaps most straightforward step in applying VSEPR theory. The central atom is typically the least electronegative and often bears the most capacity to form bonds compared to the other atoms in the molecule. This atom anchors the various bonding and non-bonding groups, determining the molecule's overall geometry.
Let's take
Let's take
- \({\mathrm{CO}}\): the central atom is carbon, as it's positioned between oxygen and bonds directly with it.
- In \({\mathrm{SiCl_{4}}}\), silicon serves as the central atom because it integrates into four bonds with chlorine atoms.
Electron Groups
Electron groups include all areas surrounding a central atom where electrons are expected to be found. They consist of both bonding groups (bonds) and lone pairs (non-bonding groups). VSEPR theory uses these electron groups to predict molecular geometry.
Consider these molecules:
Consider these molecules:
- For \({\mathrm{SO}_{2}}\), there are three electron groups: two associated with bonding to oxygen atoms and one lone pair on sulfur, resulting in a bent molecular shape.
- Likewise, in \({\mathrm{AlF}_{6}^{3-}}\), there are six electron groups, all bonding, leading to an octahedral shape.
Other exercises in this chapter
Problem 60
Use VSEPR theory to predict the geometric shapes of the following molecules and ions: (a) \(\mathrm{PCl}_{3} ;\) (b) \(\mathrm{SO}_{4}^{2-}\); (c) \(\mathrm{SOC
View solution Problem 61
Each of the following is either linear, angular (bent), planar, tetrahedral, or octahedral. Indicate the correct shape of (a) \(\mathrm{H}_{2} \mathrm{S} ;\) (b
View solution Problem 63
One of the following ions has a trigonal-planar shape: \(\mathrm{SO}_{3}^{2-} ; \mathrm{PO}_{4}^{3-} ; \mathrm{PF}_{6}^{-} ; \mathrm{CO}_{3}^{2-} .\) Which ion
View solution Problem 65
Each of the following molecules contains one or more multiple covalent bonds. Draw plausible Lewis structures to represent this fact, and predict the shape of e
View solution