Problem 62
Question
Let \(a, b\) and \(c\) be in G.P. with common ratio \(r\), where \(a \neq 0\)
and \(0
Step-by-Step Solution
Verified1Step 1: Define Geometric Progression
We know that in a geometric progression (G.P.), consecutive terms are related by a common ratio, \( r \). This means:1. \( b = ar \)2. \( c = ar^2 \)
2Step 2: Define Arithmetic Progression
In an arithmetic progression (A.P.), the difference between consecutive terms remains constant:1. Let the A.P. be defined as \( x_1, x_2, x_3, \ldots \)2. Given terms of A.P. are \( x_1 = 3a \), \( x_2 = 7b \), and \( x_3 = 15c \).3. The common difference \( d \) is defined as \( d = x_2 - x_1 = x_3 - x_2 \).
Key Concepts
Geometric Progressioncommon ratiocommon difference
Geometric Progression
A Geometric Progression (G.P.) is a sequence where each term after the first is obtained by multiplying the previous one by a fixed, non-zero number known as the common ratio.
If you have terms like \( a, b, \) and \( c \) in a geometric sequence, you can express these terms using the formula:
G.P. is incredibly useful in understanding various phenomena, such as exponential growth or decay, in mathematical contexts and even in real-world scenarios. For example, the population growth often follows a geometric progression.
If you have terms like \( a, b, \) and \( c \) in a geometric sequence, you can express these terms using the formula:
- The second term \( b \) can be expressed as \( ar \), where \( a \) is the first term and \( r \) is the common ratio.
- The third term \( c \) can be expressed as \( ar^2 \).
G.P. is incredibly useful in understanding various phenomena, such as exponential growth or decay, in mathematical contexts and even in real-world scenarios. For example, the population growth often follows a geometric progression.
common ratio
The common ratio is a crucial concept in geometric progressions. It defines the constant factor between consecutive terms in the sequence. When you move from one term to the next in a geometric progression, you multiply by this common ratio to find the subsequent term.
Let's examine the common ratio a bit more:
Let's examine the common ratio a bit more:
- If your G.P. has terms \( a, b, \) and \( c \), the common ratio \( r \) is found by dividing any term by its previous term, such as \( r = \frac{b}{a} = \frac{c}{b} \).
- It's crucial to note that the common ratio can be less than 1, which indicates a reducing sequence, or greater than 1, leading to an increasing sequence.
- The conditions given in the exercise are noteworthy: \( 0 < r \leq \frac{1}{2} \), suggesting the sequence is shrinking or stable but not increasing.
common difference
In contrast to geometric progression, an Arithmetic Progression (A.P.) involves a sequence of numbers where the difference between any two successive terms is constant, known as the common difference.
To see how this works, consider the sequence formed by terms like \( 3a, 7b, \) and \( 15c \). To find the common difference \( d \) between these terms:
An arithmetic progression is found in regular patterns such as calendar days, equal payments in an installment plan, etc., where increments remain steady over time.
To see how this works, consider the sequence formed by terms like \( 3a, 7b, \) and \( 15c \). To find the common difference \( d \) between these terms:
- Calculate \( d = x_2 - x_1 \), substituting \( x_1 = 3a \) and \( x_2 = 7b \).
- Also, \( d = x_3 - x_2 \), and substituting \( x_2 = 7b \) and \( x_3 = 15c \).
An arithmetic progression is found in regular patterns such as calendar days, equal payments in an installment plan, etc., where increments remain steady over time.
Other exercises in this chapter
Problem 60
The coefficient of \(x^{7}\) in the expression \((1+x)^{10}+x(1+x)^{9}+x^{2}(1+x)^{8}+\ldots+x^{10}\) is: [Jan. 7, 2020 (II)] (a) 210 (b) 330 (c) 120 (d) 420
View solution Problem 61
If \(\alpha, \beta\) and \(\gamma\) are three consecutive terms of a nonconstant G.P. such that the equations \(\alpha x^{2}+2 \beta x+\gamma=0\) and \(x^{2}+x-
View solution Problem 64
The product of three consecutive terms of a G.P. is 512 . If 4 is added to each of the first and the second of these terms, the three terms now form an A.P. The
View solution Problem 65
Let \(\alpha\) and \(\beta\) be the roots of the quadratic equation \(x^{2} \sin \theta-x(\sin \theta \cos \theta+1)+\cos \theta=0\left(0
View solution