Problem 62
Question
In Problems \(49-62, \mathbf{u}=\langle 2,-3\rangle, \mathbf{v}=\langle-1,5\rangle,\) and \(\mathbf{w}=\langle 3,-2\rangle .\) Find the indicated scalar or vector. $$ (\mathbf{w} \cdot \mathbf{v}) \mathbf{u} $$
Step-by-Step Solution
Verified Answer
The result is the vector \( \langle -26, 39 \rangle \).
1Step 1: Understanding Dot Product
The dot product of two vectors \( \mathbf{a} = \langle a_1, a_2 \rangle \) and \( \mathbf{b} = \langle b_1, b_2 \rangle \) is calculated as \( \mathbf{a} \cdot \mathbf{b} = a_1b_1 + a_2b_2 \). We need to find the dot product \( \mathbf{w} \cdot \mathbf{v} \).
2Step 2: Calculate \( \mathbf{w} \cdot \mathbf{v} \)
Given \( \mathbf{w} = \langle 3, -2 \rangle \) and \( \mathbf{v} = \langle -1, 5 \rangle \), compute the dot product: \( \mathbf{w} \cdot \mathbf{v} = 3(-1) + (-2)(5) = -3 - 10 = -13 \).
3Step 3: Multiply Result by Vector \( \mathbf{u} \)
Now that we have \( \mathbf{w} \cdot \mathbf{v} = -13 \), we multiply this scalar by \( \mathbf{u} = \langle 2, -3 \rangle \). The result is a vector: \( -13 \cdot \mathbf{u} = -13 \cdot \langle 2, -3 \rangle = \langle -13 \cdot 2, -13 \cdot (-3) \rangle \).
4Step 4: Perform Scalar Multiplication
Compute the final vector: \( \langle -13 \cdot 2, -13 \cdot (-3) \rangle = \langle -26, 39 \rangle \). Thus, the result is the vector \( \langle -26, 39 \rangle \).
Key Concepts
dot productscalar multiplicationvector arithmetic
dot product
When you hear the term "dot product," think of it as a way to combine two vectors to produce a single number, also known as a scalar. This operation is fundamental in vector mathematics because it helps us understand how vectors relate to each other. Given two vectors, \( \mathbf{a} = \langle a_1, a_2 \rangle \) and \( \mathbf{b} = \langle b_1, b_2 \rangle \), the dot product is calculated by multiplying corresponding components and then adding the results. This is expressed as:
- \( \mathbf{a} \cdot \mathbf{b} = a_1b_1 + a_2b_2 \)
- \( 3(-1) + (-2)(5) = -3 - 10 = -13 \)
scalar multiplication
Scalar multiplication involves taking a vector and multiplying it by a real number, known as a scalar. This operation stretches or shrinks the vector, but keeps its direction the same unless the scalar is negative, which reverses the direction. This concept helps in scaling vectors up or down based on the context of the problem.To multiply a vector \( \mathbf{u} = \langle u_1, u_2 \rangle \) by a scalar \( k \), you calculate:
- \( k \cdot \mathbf{u} = \langle k \cdot u_1, k \cdot u_2 \rangle \)
- \( -13 \cdot \mathbf{u} = \langle -13 \cdot 2, -13 \cdot (-3) \rangle = \langle -26, 39 \rangle \)
vector arithmetic
Vector arithmetic includes operations like addition, subtraction, and scaling of vectors, which are essential for performing complex mathematical and physical calculations. Understanding these operations lays the foundation for manipulating vectors to solve various problems.
- Vector Addition: To add two vectors \( \mathbf{a} = \langle a_1, a_2 \rangle \) and \( \mathbf{b} = \langle b_1, b_2 \rangle \), you simply add their corresponding components: \( \mathbf{a} + \mathbf{b} = \langle a_1 + b_1, a_2 + b_2 \rangle \).
- Vector Subtraction: To subtract one vector from another, subtract their corresponding components: \( \mathbf{a} - \mathbf{b} = \langle a_1 - b_1, a_2 - b_2 \rangle \).
- Scalar Multiplication: As detailed earlier, this scales the vector by a scalar.
Other exercises in this chapter
Problem 60
In Problems \(49-62, \mathbf{u}=\langle 2,-3\rangle, \mathbf{v}=\langle-1,5\rangle,\) and \(\mathbf{w}=\langle 3,-2\rangle .\) Find the indicated scalar or vect
View solution Problem 61
In Problems \(49-62, \mathbf{u}=\langle 2,-3\rangle, \mathbf{v}=\langle-1,5\rangle,\) and \(\mathbf{w}=\langle 3,-2\rangle .\) Find the indicated scalar or vect
View solution Problem 63
Find the dot product \(\mathbf{u} \cdot \mathbf{v}\) if the smaller angle between \(\mathbf{u}\) and \(\mathbf{v}\) is as given. $$ |\mathbf{u}|=10,|\mathbf{v}|
View solution Problem 64
Find the dot product \(\mathbf{u} \cdot \mathbf{v}\) if the smaller angle between \(\mathbf{u}\) and \(\mathbf{v}\) is as given. $$ |\mathbf{u}|=6,|\mathbf{v}|=
View solution