Problem 62
Question
In Exercises 59-64, use a graphing utility to graph the polar equation. Find an interval for \(\theta\) for which the graph is traced only once. \(r=3\ \cos \left(\dfrac{5\theta}{2}\right)\)
Step-by-Step Solution
Verified Answer
The interval for \(\theta\) for which the polar equation \(r=3\ \cos \left(\dfrac{5\theta}{2}\right)\) is traced only once is \(0 \leq \theta < \dfrac{4\pi}{5}\).
1Step 1: Graph the Polar Equation
Use a graphing utility to graph the polar equation \(r=3\ \cos \left(\dfrac{5\theta}{2}\right)\). Inspect the graph to understand the behaviour of the polar equation.
2Step 2: Identify the Pattern
Upon inspecting the graph, it can be noticed that the graph patterns seems to repeat itself every once a full cycle (360 degrees or \(2\pi\) radians) of \(\dfrac{5\theta}{2}\) has been made. Largely due to the periodic nature of cosine function. The period of \( \cos x \) is \(2\pi\), so the period of \( \cos \left(\dfrac{5x}{2}\right) \) would be \( \dfrac{4\pi}{5} \).
3Step 3: Determine the Interval for \(\theta\)
Since the graph of the polar equation repeats itself every \( \dfrac{4\pi}{5} \) radians, we can find an interval for \(\theta\) by starting from \(\theta = 0\), which is usually the starting point for analysing polar graphs. Therefore, \(0 \leq \theta < \dfrac{4\pi}{5}\) is an interval for \(\theta\) for which the polar equation \(r=3\ \cos \left(\dfrac{5\theta}{2}\right)\) is traced only once.
Key Concepts
Graphing UtilityInterval for \(\theta\)Periodic Function
Graphing Utility
A graphing utility is a vital tool for visualizing equations, especially in polar coordinates. To use it effectively for polar equations, one must understand its capabilities in displaying data in the polar form. Here's a helpful guide on what you can do with a graphing utility:
- Input the equation directly, as provided. For example, you can enter the equation as \( r = 3\cos\left(\frac{5\theta}{2}\right) \).
- Ensure that the utility is set to polar mode, as opposed to Cartesian mode.
- Watch how the graph draws itself based on these inputs. This will give insights into its structure and shape.
Interval for \(\theta\)
Determining the correct interval for \(\theta\) is essential for understanding where the polar graph traces out its path once completely. For the equation \( r = 3 \cos \left( \frac{5\theta}{2} \right) \), the interval for \( \theta \) can be found by considering the period of the function.A cosine function itself has a natural period of \( 2\pi \), meaning it repeats its values every \( 2\pi \) radian increment. However, due to the multiplication inside the argument, \(\frac{5\theta}{2}\), we need to adjust this.
To find the period of \( \cos \left( \frac{5\theta}{2} \right) \), solve the equation for one complete cycle:
To find the period of \( \cos \left( \frac{5\theta}{2} \right) \), solve the equation for one complete cycle:
- Set \( \frac{5\theta}{2} = 2\pi \)
- Solving for \( \theta \) yields \( \frac{4\pi}{5} \)
Periodic Function
The concept of a periodic function is crucial in polar equations. A periodic function is one that repeats after a fixed interval known as the period. For example, the basic cosine function, \( \, \cos \theta \, \), repeats every \( 2\pi \) radians.
In the case of \( r = 3\cos(\frac{5\theta}{2}) \), the periodic nature is slightly altered by the coefficient \(\frac{5}{2}\) within the cosine function.
In the case of \( r = 3\cos(\frac{5\theta}{2}) \), the periodic nature is slightly altered by the coefficient \(\frac{5}{2}\) within the cosine function.
- This coefficient affects the argument \(\theta\) by stretching or compressing the cosine wave.
- The new period becomes \( \frac{4\pi}{5} \), as deduced from setting the equation \( \frac{5\theta}{2} = 2\pi \).
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