Problem 62
Question
For each of the following metals, write the electronic configuration of the atom and its \(3+\) ion: (a) Fe, (b) Mo, (c) Co. Draw the crystal-field energy-level diagram for the \(d\) orbitals of an octahedral complex, and show the placement of the \(d\) electrons for each \(3+\) ion, assuming a weak-field complex. How many unpaired electrons are there in each case?
Step-by-Step Solution
Verified Answer
The electronic configurations of the 3+ ions are: Fe3+: \(3d^5\); Mo3+: \(4d^2\); Co3+: \(3d^6\). In an octahedral weak-field complex, the d-orbitals are filled as follows: Fe3+: \(t_{2g}^5 e_g^0\), Mo3+: \(t_{2g}^2 e_g^0\), and Co3+: \(t_{2g}^6 e_g^0\). There are no unpaired electrons in Fe3+ and Co3+, while Mo3+ has 2 unpaired electrons.
1Step 1: (Step 1: Find the electronic configuration of each element)
First, we'll write the electronic configuration for each metal atom:
(a) Fe: Z=26, electronic configuration: \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^6\)
(b) Mo: Z=42, electronic configuration: \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^1 4d^5\)
(c) Co: Z=27, electronic configuration: \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^7\)
2Step 2: (Step 2: Determine the electronic configuration of each element's 3+ ion)
Now, we'll find the electronic configuration of each 3+ ion:
(a) Fe3+: \(1s^2 2s^2 2p^6 3s^2 3p^6 3d^5\)
(b) Mo3+: \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 4d^2\)
(c) Co3+: \(1s^2 2s^2 2p^6 3s^2 3p^6 3d^6\)
3Step 3: (Step 3: Draw the crystal-field energy-level diagram for the d-orbitals of an octahedral complex)
For an octahedral complex, the d-orbitals split into two categories: \(e_g\) orbitals (dx²-y² and d~z²~) at higher energy levels, and \(t_{2g}\) orbitals (dxy, d~x~z, and d~y~z) at lower energy levels. In a weak-field complex, the energy gap between these orbitals isn't significant, so the electrons will occupy low-energy orbitals following Hund's Rule, prioritizing maximum unpaired electrons filling the orbitals in order.
4Step 4: (Step 4: Show the placement of d electrons for each 3+ ion, assuming a weak-field complex)
We'll now fill the d-electrons based on the weak-field energy split in an octahedral complex:
(a) Fe3+: Since we have 5 d-electrons, they will completely fill the \(t_{2g}\) orbitals, leaving 0 unpaired electrons.
The electron configuration for Fe3+ will be: \(t_{2g}^5 e_g^0\)
(b) Mo3+: Having 2 d-electrons, they will fill the two lowest-energy orbitals in the \(t_{2g}\) set.
The electron configuration for Mo3+ will be: \(t_{2g}^2 e_g^0\)
(c) Co3+: With 6 d-electrons, they will occupy all the orbitals in the \(t_{2g}\) set and one electron will be in the \(e_g\) set.
The electron configuration for Co3+ will be: \(t_{2g}^6 e_g^0\)
5Step 5: (Step 5: Find the number of unpaired electrons in each ion)
Lastly, we'll identify any unpaired electrons present in each 3+ ion:
(a) Fe3+: 0 unpaired electrons
(b) Mo3+: 2 unpaired electrons
(c) Co3+: 0 unpaired electrons
Hence, there are no unpaired electrons in Fe3+ and Co3+, while the Mo3+ ion has 2 unpaired electrons.
Key Concepts
Electronic ConfigurationTransition MetalsUnpaired Electrons
Electronic Configuration
Electronic configuration is a fundamental concept that helps us understand how electrons are distributed across the different shells and subshells in an atom. Each electron in an atom occupies a specific region in space called an orbital, and the distribution is based on specific principles:
- Aufbau Principle: Electrons occupy the lowest energy orbital available.
- Pauli Exclusion Principle: No two electrons can have the same set of four quantum numbers, meaning an orbital can hold a maximum of two electrons with opposite spins.
- Hund’s Rule: Electrons will fill degenerate orbitals (orbitals with the same energy) singly first, and only pair up when all these orbitals are half-filled.
Transition Metals
Transition metals are elements found in the d-block of the periodic table, specifically in groups 3 to 12. These metals are unique due to their ability to form variable oxidation states by losing different numbers of electrons from their s and d orbitals.Some key characteristics of transition metals include:
- Variable Oxidation States: Transition metals can form several stable oxidation states. For example, iron can form both Fe\(^{2+}\) and Fe\(^{3+}\) ions.
- Colored Compounds: Many compounds of transition metals are colored due to d-d electron transitions. These transitions are influenced by the metal's oxidation state and the nature of the ligands surrounding it.
- Formation of Complexes: Transition metals can form complex compounds with ligands due to the presence of vacant d orbitals that can accept electron pairs.
Unpaired Electrons
Unpaired electrons in an atom or ion strongly influence its magnetic properties. These are electrons in orbitals that do not have a paired electron with the opposite spin. The presence of unpaired electrons causes materials to exhibit paramagnetism—a condition where materials are attracted to external magnetic fields.To determine the unpaired electrons in d-block transition metals, we can utilize the crystal field theory, especially when they form complexes:
- Crystal Field Splitting: In an octahedral complex, the five d-orbitals split into two energy levels: three lower-energy orbitals (\(t_{2g}\): d\(_{xy}\), d\(_{xz}\), d\(_{yz}\))and two higher-energy orbitals (\(e_{g}\): d\(_{x^2-y^2}\), d\(_{z^2}\)).
- Weak Field Complexes: In weak field complexes, the electron pairing energy is higher compared to the splitting energy; electrons fill all lower energy orbitals singly before pairing starts. For example, in Fe\(^{3+}\), all five d electrons fill the lower energy \(t_{2g}\) orbitals, leading to no unpaired electrons.
Other exercises in this chapter
Problem 60
For a given metal ion and set of ligands, is the crystal-field splitting energy larger for a tetrahedral or an octahedral geometry?
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