Problem 62
Question
For each of the following metals, write the electronic con- figuration of the atom and its \(3+\) ion: \((\mathbf{a}) \mathrm{Fe},(\mathbf{b}) \mathrm{Mo},(\mathbf{c}) \mathrm{Co} .\) Draw the crystal-field energy-level diagram for the \(d\) orbitals of an octahedral complex, and show the placement of the \(d\) electrons for each \(3+\) ion, assuming a weak-field complex. How many unpaired electrons are there in each case?
Step-by-Step Solution
Verified Answer
Fe: 5 unpaired; Mo: 3 unpaired; Co: 0 unpaired.
1Step 1: Writing Electron Configuration of Atoms
The electron configurations of the neutral atoms are as follows: For iron (Fe): The atomic number is 26, so the configuration is \([\text{Ar}] \, 4s^2 \, 3d^6\). For molybdenum (Mo): The atomic number is 42, leading to \([\text{Kr}] \, 5s^1 \, 4d^5\) due to a half-filled d subshell. For cobalt (Co): The atomic number is 27, making the configuration \([\text{Ar}] \, 4s^2 \, 3d^7\).
2Step 2: Writing Electron Configuration of the 3+ Ions
To find the electron configuration of the \(3+\) ions, remove three electrons from the atom, prioritizing removal from the highest principal energy level first. For \(\text{Fe}^{3+}\): Remove two electrons from \(4s\) and one from \(3d\), resulting in \([\text{Ar}] \, 3d^5\). For \(\text{Mo}^{3+}\): Remove the electron from \(5s\) and two from \(4d\), leading to \([\text{Kr}] \, 4d^3\). For \(\text{Co}^{3+}\): Remove two electrons from \(4s\) and one from \(3d\), yielding \([\text{Ar}] \, 3d^6\).
3Step 3: Drawing the Crystal-Field Energy-Level Diagram for \(3+\) Ions in a Weak-Field Octahedral Complex
In an octahedral complex, the d orbitals split into two sets: \(t_{2g}\) (\(d_{xy}\), \(d_{xz}\), \(d_{yz}\)) and \(e_g\) (\(d_{x^2-y^2}\), \(d_{z^2}\)). For a weak-field situation, electrons will fill each orbital singly before pairing. For \(\text{Fe}^{3+}\): There are 5 d electrons, filling half of the \(t_{2g}\) orbitals. For \(\text{Mo}^{3+}\): There are 3 d electrons, filling each of the \(t_{2g}\) orbitals singly. For \(\text{Co}^{3+}\): There are 6 d electrons, with 3 filling \(t_{2g}\) singly, the fourth adding another electron into \(t_{2g}\), and the remaining 2 pairing in \(e_g\).
4Step 4: Counting Unpaired Electrons
Determine the number of unpaired electrons in the \(3+\) ions. \(\text{Fe}^{3+}\): There are 5 electrons, all in \(t_{2g}\), resulting in 5 unpaired electrons. \(\text{Mo}^{3+}\): There are 3 electrons, all in \(t_{2g}\), resulting in 3 unpaired electrons. \(\text{Co}^{3+}\): There are 6 electrons, with 4 in \(t_{2g}\) (3 unpaired, 1 paired) and 2 in \(e_g\) (both paired), resulting in no unpaired electrons.
Key Concepts
Octahedral ComplexCrystal-Field TheoryUnpaired Electrons
Octahedral Complex
An octahedral complex is a common type of coordination compound where six ligands are symmetrically arranged around a central metal ion, forming the vertices of an octahedron. This arrangement maximizes the ligand-metal ion interactions, as the ligands can approach the metal from maximum symmetry positions.
In the case of a weak-field octahedral complex:
In the case of a weak-field octahedral complex:
- The d orbitals of the central metal ion split into two distinct sets of energy levels due to the electrostatic interactions with the ligands.
- The three lower energy d orbitals form the t2g set, which includes the dxy, dxz, and dyz orbitals.
- The two higher energy d orbitals make up the eg set, composed of dx2-y2 and dz2 orbitals.
Crystal-Field Theory
Crystal-field theory is a model that describes the electronic structure of transition metal complexes. It focuses on the interaction between the central metal ion and the surrounding ligands, treating the ligands as point charges in the simplified model.
The primary concepts behind this theory include:
The primary concepts behind this theory include:
- The splitting of d orbitals: In an octahedral complex, the presence of ligands disrupts the degeneracy of the d orbitals, splitting them into different energy levels. The t2g orbitals have lower energy compared to the eg orbitals.
- Weak-field versus strong-field ligands: In a weak-field complex, splitting is small, and electrons remain unpaired to a greater extent. In strong-field complexes, the energy gap is large enough to potentially force electron pairing within the lower energy orbitals.
Unpaired Electrons
Unpaired electrons in a d orbital refer to electrons that remain unpaired due to electron configuration and ligand strength. The presence of unpaired electrons is vital when determining the magnetic properties of a complex.
In a weak-field octahedral complex:
In a weak-field octahedral complex:
- For Fe3+ with 5 d electrons: All occupy the lower energy t2g orbitals, resulting in 5 unpaired electrons.
- For Mo3+ with 3 d electrons: Each fills one t2g orbital, keeping all 3 electrons unpaired.
- For Co3+ with 6 d electrons: An electron pairs up in the t2g, and the eg orbitals are fully paired, resulting in no unpaired electrons.
Other exercises in this chapter
Problem 59
A classmate says, "A weak-field ligand usually means the complex is high spin." Is your classmate correct? Explain.
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For a given metal ion and set of ligands, is the crystal-field splitting energy larger for a tetrahedral or an octahedral geometry?
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Draw the crystal-field energy-level diagrams and show the placement of \(d\) electrons for each of the following: (a) \(\left[\mathrm{Cr}\left(\mathrm{H}_{2} \m
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Draw the crystal-field energy-level diagrams and show the placement of electrons for the following complexes: (a) \(\left[\mathrm{VCl}_{6}\right]^{3-}\), (b) \(
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