Problem 62
Question
Find the point at which the lines determined by the two given equations intersect. $$ y=3 x+1 / 2, y=2 x+1 $$
Step-by-Step Solution
Verified Answer
The intersection point is \( (\frac{1}{2}, 2) \).
1Step 1: Set the Equations Equal
To find the intersection of the two lines, the first step is to set their equations equal. Since both equations are expressed as functions of the same variable, we equate the two equations: \( 3x + \frac{1}{2} = 2x + 1 \)
2Step 2: Solve for x
We solve the equation from Step 1 for \( x \). First, isolate \( x \) by moving terms involving \( x \) to one side and constant terms to the other:\[3x - 2x = 1 - \frac{1}{2}\]Simplify both sides:\[x = \frac{1}{2}\].
3Step 3: Substitute x back into one equation
Substitute \( x = \frac{1}{2} \) back into either of the original equations to find \( y \). Let's use \( y = 2x + 1 \):\[y = 2\left(\frac{1}{2}\right) + 1 = 1 + 1 = 2\]
4Step 4: State the Intersection Point
Now that we have both \( x \) and \( y \), state the point of intersection. From the calculations, we find that the lines intersect at the point \( \left( \frac{1}{2}, 2 \right) \).
Key Concepts
Systems of EquationsSolving Linear EquationsGraphing Lines
Systems of Equations
A system of equations is a set of two or more equations that share two or more unknowns. In this context, we are dealing with linear equations, which graph as straight lines on a coordinate plane. The goal is to find a common solution that satisfies all equations in the system simultaneously.
Such an occurrence happens at the point where the lines intersect.
Such an occurrence happens at the point where the lines intersect.
- An equation might not be solvable alone if it has two variables, like in our original exercise with the equations for two lines.
- When two lines intersect, they have one unique solution as they cross each other on a graph.
- If the lines are parallel, they never meet, meaning there is no solution.
Solving Linear Equations
Solving linear equations is all about finding the value of the variables that make the equation true. Linear equations are algebraic expressions that form a straight line when graphed on a coordinate plane. Let's break down the process:
- First, we need to express the equation in terms of the variables involved. In our exercise, these are given as two equations relating to a single variable, \(y=3x+\frac{1}{2}\) and \(y=2x+1\).
- The next step involves isolating one variable so as to make it easier for solving the equation. This was done in our solution by setting the equations equal to each other and solving for \(x\).
- After finding \(x\), substitute this value back into one of the original equations to solve for \(y\).
Graphing Lines
Graphing lines on a coordinate grid can make it easier to visualize equations and see relationships between variables clearly. When graphing a linear equation, you can follow these steps:
- Recognize the slope-intercept form: \(y = mx + b\). Here, \(m\) is the slope, indicating the steepness and direction of the line, and \(b\) is the y-intercept, where the line crosses the y-axis.
- To graph a line, start by plotting the y-intercept on the graph.
- Use the slope to determine the next points on the line. The slope \(m\) is the ratio \(\Delta y/\Delta x\); for example, a slope of 3 means the line rises by 3 for every step to the right.
Other exercises in this chapter
Problem 62
Sketch the set. \(\\{(x, y):|x|
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A function \(f\) is said to have period \(p\) if there is a smallest positive number \(p\) such that \(f(x+p)=f(x)\) for all \(x\) in the domain of \(f\). Find
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Determine the interval that \(y\) must lie in to agree with \(x\) to \(q\) decimal places. \(x=0.213462 \times 10^{-1}, q=5\)
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Find a function \(g\) such that \(g \circ f=h\) \(f(x)=x^{2}-9, h(x)=2 x^{2}\)
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