Problem 62
Question
Find the parametric equation of the line in \(x-y-z\) space that goes through the given points. \((1,0,4)\) and \((3,2,0)\)
Step-by-Step Solution
Verified Answer
The parametric equation is \( (x, y, z) = (1 + 2t, 2t, 4 - 4t) \).
1Step 1: Identify two points
The problem provides two points through which the line passes: \( (1, 0, 4) \) and \( (3, 2, 0) \). Use these points to determine the direction vector of the line.
2Step 2: Determine direction vector
The direction vector \( \vec{d} \) from point \( (1,0,4) \) to point \( (3,2,0) \) can be found by subtracting the coordinates of the first point from the second:\[ \vec{d} = (3-1, 2-0, 0-4) = (2, 2, -4) \].
3Step 3: Write the parametric equations
To write the parametric equations of the line, use the first point and the direction vector. If \( t \) is a parameter, the parametric equations are:\[x = 1 + 2t,y = 0 + 2t,z = 4 - 4t\]
Key Concepts
Direction VectorLine in SpaceParametric Form
Direction Vector
In geometry, the direction vector plays a crucial role when representing lines in space. For any line, a direction vector provides information about the path it takes. To find it, you need two points that the line passes through.
In our exercise, the two given points are
This vector tells us how to move from one point to the next along the line and therefore influences the line's orientation in space.
In our exercise, the two given points are
- Point A: (1, 0, 4)
- Point B: (3, 2, 0)
This vector tells us how to move from one point to the next along the line and therefore influences the line's orientation in space.
Line in Space
A line in space, unlike a line in a plane, exists in three-dimensional (3D) space. It traverses the dimensions represented by the axes \( x \), \( y \), and \( z \). Understanding a line's existence in 3D is crucial for solving equations involving spatial objects.
The line's path through a 3D space can be determined by its direction vector and a given point on the line. Using our example, starting from point A:
This combination ensures that no matter how far you project the line, it will maintain its direction defined by the vector.
The line's path through a 3D space can be determined by its direction vector and a given point on the line. Using our example, starting from point A:
- Point A: (1, 0, 4)
This combination ensures that no matter how far you project the line, it will maintain its direction defined by the vector.
Parametric Form
The parametric form of an equation is a powerful tool for describing lines, especially in 3-dimensional space. This form utilizes a parameter, often denoted as \( t \), which allows the calculation of the exact position on a line at any given point.
To transform a line into its parametric form, you start with a known point on the line and incorporate its direction vector. Using our given point A:
To transform a line into its parametric form, you start with a known point on the line and incorporate its direction vector. Using our given point A:
- (1, 0, 4)
- \( x = 1 + 2t \)
- \( y = 0 + 2t \)
- \( z = 4 - 4t \)
Other exercises in this chapter
Problem 61
Find the eigenvalues \(\lambda_{1}\) and \(\lambda_{2}\) for $$ A=\left[\begin{array}{ll} a & 0 \\ c & b \end{array}\right] $$
View solution Problem 61
Write down the inverse of \(A\). $$ A=\left[\begin{array}{rr} -1 & 4 \\ 5 & 0 \end{array}\right] $$
View solution Problem 62
Find the eigenvalues \(\lambda_{1}\) and \(\lambda_{2}\) for $$ A=\left[\begin{array}{ll} a & c \\ 0 & b \end{array}\right] $$
View solution Problem 62
Write down the inverse of \(A\). $$ A=\left[\begin{array}{rr} -2 & -1 \\ 3 & 2 \end{array}\right] $$
View solution