Problem 62
Question
Find the hydronium ion \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]\) concentration for each substance with the given \(p H\) Wine, 3.4
Step-by-Step Solution
Verified Answer
The hydronium ion concentration is approximately \(3.98 \times 10^{-4}\) M.
1Step 1: Understand the Relationship between pH and Hydronium Ion Concentration
The pH of a solution is a measure of its acidity or alkalinity. The formula to relate pH to the hydronium ion concentration is given by:\[pH = -\log_{10} \left[ \mathrm{H}_3\mathrm{O}^+ \right] \] This means that the hydronium ion concentration, \( \left[ \mathrm{H}_3\mathrm{O}^+ \right] \), can be calculated by using the inverse logarithmic function.
2Step 2: Apply the Formula to Calculate Hydronium Ion Concentration
Given the pH of wine is 3.4, we apply the formula:\[ \left[ \mathrm{H}_3\mathrm{O}^+ \right] = 10^{-\text{pH}} \]Substituting the given pH value:\[ \left[ \mathrm{H}_3\mathrm{O}^+ \right] = 10^{-3.4} \]
3Step 3: Perform the Calculation
Now, calculate the power of ten:\[ \left[ \mathrm{H}_3\mathrm{O}^+ \right] = 10^{-3.4} \approx 3.98 \times 10^{-4} \text{ M}\]This means the hydronium ion concentration in the wine is approximately \(3.98 \times 10^{-4}\) moles per liter (M).
Key Concepts
Hydronium Ion ConcentrationInverse Logarithmic FunctionAcid-Base ChemistryMolecular Concentration Calculation
Hydronium Ion Concentration
The hydronium ion concentration \([ \mathrm{H}_3\mathrm{O}^+ ]\) is a direct measure of the number of hydronium ions present in a solution. Knowing the concentration is important because it tells us how acidic or basic a solution is. For a solution like wine with a given pH value, calculating the hydronium ion concentration helps us understand its acidic strength.
To find this concentration, we use the relationship between pH and \([ \mathrm{H}_3\mathrm{O}^+ ]\): \([ \mathrm{H}_3\mathrm{O}^+ ] = 10^{-\text{pH}}\).
Applying the formula is simple once we have the pH. For wine, with a pH of 3.4, the concentration is calculated as follows: \([ \mathrm{H}_3\mathrm{O}^+ ] = 10^{-3.4} \approx 3.98 \times 10^{-4} \, \text{Molar}\).
This calculation is crucial in many fields such as chemistry and food science because it allows the evaluation of how substances will interact based on their acidity.
To find this concentration, we use the relationship between pH and \([ \mathrm{H}_3\mathrm{O}^+ ]\): \([ \mathrm{H}_3\mathrm{O}^+ ] = 10^{-\text{pH}}\).
Applying the formula is simple once we have the pH. For wine, with a pH of 3.4, the concentration is calculated as follows: \([ \mathrm{H}_3\mathrm{O}^+ ] = 10^{-3.4} \approx 3.98 \times 10^{-4} \, \text{Molar}\).
This calculation is crucial in many fields such as chemistry and food science because it allows the evaluation of how substances will interact based on their acidity.
Inverse Logarithmic Function
To understand the connection between pH and concentration, we need to utilize the inverse of the logarithmic function. A logarithmic function helps to describe how acidity is measured. The pH scale is logarithmic, meaning each unit change represents a tenfold change in hydrogen ion concentration.
In this context, the formula \[pH = -\log_{10} \left[ \mathrm{H}_3\mathrm{O}^+ \right] \] is rearranged to solve for hydronium ion concentration:
This understanding aids in practical applications, allowing chemists and scientists to predict the behavior of solutions in different pH conditions.
In this context, the formula \[pH = -\log_{10} \left[ \mathrm{H}_3\mathrm{O}^+ \right] \] is rearranged to solve for hydronium ion concentration:
- Start with the pH value.
- Use the inverse, which involves raising 10 to the power of the negative pH, to find the concentration.
This understanding aids in practical applications, allowing chemists and scientists to predict the behavior of solutions in different pH conditions.
Acid-Base Chemistry
Acid-base chemistry revolves around the behavior of acids and bases in water and their ability to donate or accept protons, often visualized through \[ \mathrm{H}_3\mathrm{O}^+ \] and \[ \mathrm{OH}^- \] ions. pH, a central concept in acid-base chemistry, tells us whether a solution is acidic or basic.
An acidic solution like wine, with a pH of less than 7, has more hydronium ions than hydroxide ions. The pH scale helps categorize solutions as:
Researchers and manufacturers rely on acid-base chemistry to tailor the properties of substances in products like food, medicine, and cleaning agents.
An acidic solution like wine, with a pH of less than 7, has more hydronium ions than hydroxide ions. The pH scale helps categorize solutions as:
- Acidic if pH < 7
- Neutral if pH = 7
- Basic if pH > 7
Researchers and manufacturers rely on acid-base chemistry to tailor the properties of substances in products like food, medicine, and cleaning agents.
Molecular Concentration Calculation
Molecular concentration is the measurement of how much of a substance is present in a unit volume of solution, usually expressed in moles per liter (M). Calculating concentrations is a fundamental aspect of chemistry.
The calculation involves knowing the initial proton concentration or using measurements like pH to back-calculate other relevant concentrations. With pH, \([ \mathrm{H}_3\mathrm{O}^+ ]\) is specifically calculated using: \[ \left[ \mathrm{H}_3\mathrm{O}^+ \right] = 10^{-\text{pH}} \].
This conversion from pH to concentration allows chemists to:
The calculation involves knowing the initial proton concentration or using measurements like pH to back-calculate other relevant concentrations. With pH, \([ \mathrm{H}_3\mathrm{O}^+ ]\) is specifically calculated using: \[ \left[ \mathrm{H}_3\mathrm{O}^+ \right] = 10^{-\text{pH}} \].
This conversion from pH to concentration allows chemists to:
- Determine the extent of chemical reactions.
- Assess the strength and behavior of acidic or basic environments.
Other exercises in this chapter
Problem 61
Solve each logarithmic equation. Express all solutions in exact form. Support your solutions by using a calculator. $$\log x=\sqrt{\log x}$$
View solution Problem 62
Use a graphing calculator to solve each equation. Give solutions to the nearest hundredth. \(\log _{10} x=x-2\)
View solution Problem 62
Solve each equation in part (a) analytically. Support your answer with a calculator graph. Then use the graph to solve the associated inequalities in parts (b)
View solution Problem 62
For each function that is one-to-one, write an equation for the inverse function in the form \(y=f^{-1}(x)\) and then graph \(f\) and \(f^{-1}\) on the same axe
View solution