Problem 62
Question
Find each of the products and express the answers in the standard form of a complex number. $$ (-6 i)(9 i) $$
Step-by-Step Solution
Verified Answer
The product is 54 + 0i.
1Step 1: Multiply the Coefficients
Start by multiplying the numbers that are not associated with 'i', the imaginary unit. In this case, \[(-6) imes (9) = -54.\]
2Step 2: Multiply the Imaginary Units
Next, multiply the imaginary units together: \[i imes i = i^2\]Remember that \(i^2\) equals \(-1\).
3Step 3: Combine the Results
Combine the results from the previous steps:\[-54 imes i^2 = -54 imes (-1) = 54.\]
4Step 4: Express in Standard Form
The resulting number from multiplying these complex numbers is a real number with no imaginary part. Therefore, the standard form of our result is \[54 + 0i.\]
Key Concepts
Imaginary UnitMultiplication of Complex NumbersStandard Form of a Complex Number
Imaginary Unit
When dealing with complex numbers, the imaginary unit is a crucial concept. It is represented by the symbol 'i' and is defined as the square root of -1. This means that:
- \(i = \sqrt{-1}\)
- \(i^2 = -1\).
Multiplication of Complex Numbers
Multiplying complex numbers involves more than just numbers alone. You have to take into account both the real and imaginary components. Let's quickly review how this works. Consider two arbitrary complex numbers in the form \(a + bi\) and \(c + di\). When you multiply them, you distribute the multiplication over the binomials:
- \((a + bi)(c + di) = ac + adi + bci + bdi^2\)
- \(ac + adi + bci - bd\)
- \((ac - bd) + (ad + bc)i\)
Standard Form of a Complex Number
The standard form of a complex number is written as \(a + bi\), where \(a\) is the real part and \(bi\) is the imaginary part. This form allows for easy addition, subtraction, multiplication, and division of complex numbers. In our exercise solution, we arrived at a product that was real after simplification, 54, with no imaginary part. Hence, we expressed it in the simplest standard form:
- \(54 + 0i\)
Other exercises in this chapter
Problem 62
Another of your friends claims that the quadratic formula can be used to solve the equation \(x^{2}-9=0\). How would you react to this claim?
View solution Problem 62
Explain the process of completing the square to solve a quadratic equation.
View solution Problem 63
Set up an equation and solve each problem. A group of students agreed that each would contribute the same amount to buy their favorite teacher an \(\$ 80\) birt
View solution Problem 63
Why must we change the equation \(3 x^{2}-2 x=4\) to \(3 x^{2}-2 x-4=0\) before applying the quadratic formula?
View solution