Problem 62
Question
Factor. $$ r^{3}+125 $$
Step-by-Step Solution
Verified Answer
The expression factors to \( (r + 5)(r^2 - 5r + 25) \).
1Step 1: Recognize the Sum of Cubes
The expression given is in the form \( r^3 + 125 \). We recognize this as a sum of cubes because it can be written as \( r^3 + 5^3 \). The sum of cubes can be factored using the formula: \( a^3 + b^3 = (a + b)(a^2 - ab + b^2) \).
2Step 2: Apply the Sum of Cubes Formula
Identify \( a = r \) and \( b = 5 \). Substitute these into the sum of cubes formula: \( (r + 5)(r^2 - r \times 5 + 5^2) \).
3Step 3: Simplify the Factorization
Simplify the expression inside the second parenthesis from Step 2: \( r^2 - 5r + 25 \). Therefore, the factorization of \( r^3 + 125 \) is \( (r + 5)(r^2 - 5r + 25) \).
Key Concepts
Factoring PolynomialsAlgebraic ExpressionsCubic Equations
Factoring Polynomials
Factoring polynomials is like finding the building blocks of an algebraic expression. Consider it as the process of breaking down a complex expression into simpler pieces. This makes it easier to solve equations or understand the inherent properties of the expression.
Factoring can involve the following steps:
Factoring can involve the following steps:
- Identify the type of polynomial.
- Look for common factors.
- Apply specific formulas based on the polynomial format, like the sum of cubes.
Algebraic Expressions
Algebraic expressions are combinations of numbers, variables, and mathematical operations packed into a compact form. Think of them as the language of algebra that helps in expressing relationships and forming equations.
Every part of an expression has a name:
Every part of an expression has a name:
- **Terms** are the pieces separated by addition or subtraction signs, like \(r^3\) and \(125\) in our example.
- **Coefficients** are the numbers in front of variables; in this case, the coefficient of \(r^3\) is 1.
- **Constants** are standalone numbers like the 125 here.
Cubic Equations
Cubic equations are equations of the form \(ax^3 + bx^2 + cx + d = 0\). These can be daunting due to their complex nature, but breaking them down into more manageable components, like factoring, can make solving them easier.
To solve a cubic equation or simplify its expression form:
To solve a cubic equation or simplify its expression form:
- Identify if it's a sum or difference of cubes.
- Apply appropriate formulas to transform them.
- Factor step-by-step until you simplify the equation.
Other exercises in this chapter
Problem 61
Factor each trinomial completely. See Examples 1 through 7. \(30 x^{3}+38 x^{2}+12 x \quad\) 62. \(6 x^{3}-28 x^{2}+16 x\)
View solution Problem 61
Solve each equation. $$ 12 y=8 y^{2} $$
View solution Problem 62
Factor each polynomial by grouping. $$ x^{2 n}+6 x^{n}+10 x^{n}+60 $$
View solution Problem 62
Factor each four-term polynomial by grouping. If this is not possible, write "not factorable by grouping." $$ x y+y+2 x+2 $$
View solution