Problem 62
Question
Either show that the equation \(i s\) an identity or show that the equation \(is\quad not\) an identity. $$\frac{\tan ^{2} x}{\sec x-1}=\sec x$$
Step-by-Step Solution
Verified Answer
The equation is not an identity.
1Step 1: Understand the Given Equation
We need to check if the equation \( \frac{\tan^2 x}{\sec x - 1} = \sec x \) is an identity. An identity holds for all values in its domain.
2Step 2: Express Functions in Sine and Cosine
Rewrite the trigonometric functions in terms of sine and cosine. We have \( \tan x = \frac{\sin x}{\cos x} \) and \( \sec x = \frac{1}{\cos x} \). Substitute these into the equation:\[\frac{\left( \frac{\sin x}{\cos x} \right)^2}{\frac{1}{\cos x} - 1} = \frac{1}{\cos x}\]
3Step 3: Simplify the Left Side
Simplify the expression on the left side by substituting the expressions for \(\tan x\) and \(\sec x\):\[\frac{\frac{\sin^2 x}{\cos^2 x}}{\frac{1 - \cos x}{\cos x}}\]The denominator becomes \(\frac{1 - \cos x}{\cos x}\). Multiply numerator and denominator by \(\cos^2 x\):\[= \frac{\sin^2 x \cdot \cos x}{1 - \cos x}\]
4Step 4: Simplify Further and Compare
Simplify the numerator \(\sin^2 x \cdot \cos x\) and try to simplify both sides:\[\frac{\sin^2 x \cdot \cos x}{1 - \cos x} eq \frac{1}{\cos x}\]The expression does not simplify to match \(\sec x\), indicating a discrepancy.
5Step 5: Conclude on Identity Status
Since the two sides of the equation do not simplify to equal each other for all \(x\), the equation \(\frac{\tan^2 x}{\sec x - 1} = \sec x\) is not an identity. There are values of \(x\) for which this equation does not hold, proving it is not universally true.
Key Concepts
Simplification of Trigonometric ExpressionsSine and Cosine FunctionsEquivalent Trigonometric Forms
Simplification of Trigonometric Expressions
Simplification of trigonometric expressions often involves breaking down complex equations into simpler components. This is accomplished by expressing trigonometric functions in terms of basic identities like sine and cosine. Consider the expression \( \frac{\tan^2 x}{\sec x - 1} \). A useful strategy here is to express \( \tan x \) and \( \sec x \) in terms of sine and cosine.
- \( \tan x = \frac{\sin x}{\cos x} \): Tangent is the ratio of sine to cosine.
- \( \sec x = \frac{1}{\cos x} \): Secant is the reciprocal of cosine.
Sine and Cosine Functions
One of the core foundations in trigonometry is the use of sine and cosine functions. These functions are crucial as they form the basis for expressing other trigonometric identities. For instance, in our problem, tangent and secant were rewritten using sine and cosine:
- \( \tan x = \frac{\sin x}{\cos x} \)
- \( \sec x = \frac{1}{\cos x} \)
Equivalent Trigonometric Forms
Understanding equivalent trigonometric forms is crucial when analyzing whether two expressions are identical for every value within a certain range. Simplification often reveals these forms. For instance, when equivalent forms like \( \frac{1}{\cos x} \) for \( \sec x \) align through transformations, an identity may be possible. This concept promotes an in-depth understanding of how transformations work:
- Applying transformations converts complex expressions into simpler or comparable forms.
- Equivalent forms may appear different but are equal for all applicable values of \( x \).
Other exercises in this chapter
Problem 62
Use inverse trigonometric functions to find the solutions of the equation that are in the given interval, and approximate the solutions to four decimal places.
View solution Problem 62
Graphically solve the trigonometric equation on the indicated interval to two decimal places. \(\tan \left(\frac{3}{2} x+\frac{1}{2}\right)=\frac{3}{2} \sin 2 x
View solution Problem 62
Exer. \(57-62:\) Use an addition or subtraction formula to find the solutions of the equation that are in the Interval \([0, \pi)\) $$\tan t-\tan 4 t=1+\tan 4 t
View solution Problem 62
Find the solutions of the equation that are in the interval \([0,2 \pi)\). $$2 \sin v \csc v-\csc v=4 \sin v-2$$
View solution